Triangle Area with 9-Unit Median-Height: Special Case Calculation

To solve the problem of finding the area of triangle $ABC$, we follow these steps:

• Step 1: Recognize that $AD$ is a median and also the height, hence it bisects $BC$ into two equal lengths.
• Step 2: Given $BD = DC = 6.5$, determine $BC = 2 \times 6.5 = 13$.
• Step 3: Use the area formula for triangles, $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$.
• Step 4: Substitute the known values: $\text{Area} = \frac{1}{2} \times 13 \times 9 = 58.5$.

The area of triangle $ABC$ is, therefore, $58.5$.