Examples with solutions for Parts of a Triangle: Determine the size of the given angles

Exercise #1

Find the size of the angle α \alpha .

2x+30α=x+30

Video Solution

Step-by-Step Solution

To find the size of angle α \alpha , we proceed as follows:

  • Step 1: Establish the relationship for the angles as supplementary: α+(2x+30)=180\alpha + (2x + 30) = 180^\circ.
  • Step 2: Substitute α=x+30\alpha = x + 30 into the equation:

Substituting, we get:

(x+30)+(2x+30)=180 (x + 30) + (2x + 30) = 180

Combine like terms:

3x+60=180 3x + 60 = 180

Step 3: Solve for x x :
Subtract 60 from both sides:

3x=120 3x = 120

Divide both sides by 3:

x=40 x = 40

  • Step 4: Substitute x=40 x = 40 back into α=x+30\alpha = x + 30 to find α\alpha:

α=40+30=70 \alpha = 40 + 30 = 70

Thus, the size of the angle α \alpha is 70.

Answer

70

Exercise #2

Find the size of the angle α \alpha .

αααβ=65

Video Solution

Step-by-Step Solution

To solve this problem, let's identify the angle relationships based on the given information:

Step 1: From the diagram, angle β\beta is stated to be 6565^\circ. It is important to recognize that α\alpha and β\beta are positioned such that they form a pair of vertical angles.

Step 2: According to the vertical angle theorem, vertical angles are congruent. This means that if β=65\beta = 65^\circ, then α\alpha must also equal 6565^\circ because they are vertical angles created by intersecting lines.

Therefore, the size of angle α\alpha is 65\mathbf{65^\circ}.

Answer

65

Exercise #3

Find the size of the given angle.

12456

Video Solution

Answer

180

Exercise #4

Find the size of the angle α \alpha .

β=2x+60α=x+86

Video Solution

Answer

112

Exercise #5

Find the size of the angle ACB ∢\text{ACB} .

βββCCCBBBAAAα=8575

Video Solution

Answer

20