Examples with solutions for Multiplication of Powers: Inverse formula

Exercise #1

Expand the following equation:

22+5= 2^{2+5}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll apply the rule for adding exponentials:

  • Step 1: Identify the base and the exponents.
    The base is 22 and the exponents, when added, are 2+52 + 5.
  • Step 2: Apply the rule for multiplication of powers.
    Using am+n=am×ana^{m+n} = a^m \times a^n, we have 22+5=22×252^{2+5} = 2^2 \times 2^5.
  • Step 3: Simplify and expand the expression.
    Split the expression into 222^2 and 252^5, which is the expanded form based on the power rule.

Therefore, the expanded form of the equation is 22×252^2 \times 2^5.

Answer

22×25 2^2\times2^5

Exercise #2

Expand the following equation:

44+6= 4^{4+6}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the base and the exponents in the expression
  • Step 2: Apply the exponent rule am+n=am×an a^{m+n} = a^m \times a^n
  • Step 3: Rewrite the expression using the rule

Now, let's work through each step:
Step 1: The problem gives us the expression (4)4+6(4)^{4+6}. Here, the base is 4, and the exponent is the sum 4+64 + 6.
Step 2: We'll apply the rule am+n=am×an a^{m+n} = a^m \times a^n , which allows us to write the expression as the product of two powers.
Step 3: According to the rule, (4)4+6(4)^{4+6} becomes (4)4×(4)6(4)^4 \times (4)^6.

This means that (4)4+6(4)^{4+6} expands to (4)4×(4)6(4)^4 \times (4)^6.

Therefore, the solution to the problem is 44×46\boxed{4^4 \times 4^6}, corresponding to choice 4.

Answer

44×46 4^4\times4^6

Exercise #3

Expand the following equation:

63+2= 6^{3+2}=

Video Solution

Step-by-Step Solution

Let's solve this problem step-by-step using the rules of exponents:

  • Step 1: Identify the expression. We are given 63+26^{3+2}.

  • Step 2: Apply the exponent rule am+n=am×ana^{m+n} = a^m \times a^n. This allows us to split the addition in the exponent into separate multiplicative terms.

  • Step 3: Break down the exponent addition 3+23+2 into: 63×626^3 \times 6^2.

By applying the rules of exponents, the expression 63+26^{3+2} can be expanded to:
63×62 6^3 \times 6^2

Therefore, the expanded form of the expression is 63×62 6^3 \times 6^2 .

Answer

63×62 6^3\times6^2

Exercise #4

Expand the following equation:

78= 7^8=

Video Solution

Step-by-Step Solution

To address this problem, we need to verify the set of exponent rules for each choice provided and determine which, if any, results in 78 7^8 .

Let's explore and verify the provided choices:

  • Choice 1: 72×74 7^2 \times 7^4
  • Using the rule am×an=am+n a^m \times a^n = a^{m+n} , we have:

    72×74=72+4=76 7^2 \times 7^4 = 7^{2+4} = 7^6

    This does not equal 78 7^8 .

  • Choice 2: 78×71 7^8 \times 7^1
  • Using the rule am×an=am+n a^m \times a^n = a^{m+n} , we have:

    78×71=78+1=79 7^8 \times 7^1 = 7^{8+1} = 7^9

    This does not equal 78 7^8 .

  • Choice 3: 74×72 7^4 \times 7^2
  • Using the rule am×an=am+n a^m \times a^n = a^{m+n} , we have:

    74×72=74+2=76 7^4 \times 7^2 = 7^{4+2} = 7^6

    This does not equal 78 7^8 .

Upon evaluating all given choices, none of the expressions equal 78 7^8 .

Therefore, based on the analysis, the correct choice is None of the answers are correct.

Answer

None of the answers are correct

Exercise #5

Expand the following equation:

84= 8^4=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Understand the given information, which is the expression 84 8^4 .
  • Step 2: Check each choice to see if it is a valid decomposition of 84 8^4 .
  • Step 3: Validate each decomposition by applying the formula am×an=am+n a^m \times a^n = a^{m+n} .

Now, let's work through each step:
Step 1: The given expression is 84 8^4 . We need to expand it using the properties of exponents.
Step 2: Check each choice:
- Choice 1: 81×83 8^1 \times 8^3 . According to the law am×an=am+n a^m \times a^n = a^{m+n} , this gives 81+3=84 8^{1+3} = 8^4 . Correct.
- Choice 2: 82×82 8^2 \times 8^2 . Similarly, 82+2=84 8^{2+2} = 8^4 . Correct.
- Choice 3: 83×81 8^3 \times 8^1 . This gives 83+1=84 8^{3+1} = 8^4 . Correct.
Step 3: All choices decompose 84 8^4 correctly into powers of 8 that multiply back to the original value, confirming their validity.

Therefore, the solution to the problem is all answers are correct.

Answer

All answers are correct

Exercise #6

Expand the following expression:

76= 7^6=

Video Solution

Step-by-Step Solution

To solve this problem, let's examine the possible answer choices to determine which ones equal 76 7^6 .

  • **Choice 1:** 71×72×74 7^1 \times 7^2 \times 7^4
    By exponent rules: 717274=71+2+4=77 7^1 \cdot 7^2 \cdot 7^4 = 7^{1+2+4} = 7^7 .
  • **Choice 2:** 71×7×74 7^1 \times 7 \times 7^4
    Here, 7=71 7 = 7^1 . So, 717174=71+1+4=76 7^1 \cdot 7^1 \cdot 7^4 = 7^{1+1+4} = 7^6 .
  • **Choice 3:** 72×72×72 7^2 \times 7^2 \times 7^2
    Using the rule: 727272=72+2+2=76 7^2 \cdot 7^2 \cdot 7^2 = 7^{2+2+2} = 7^6 .
  • **Choice 4:** This states choices 'b + c are correct'.

After calculations, choices 2 and 3 simplify to 76 7^6 . Therefore, the correct answer is indeed that choices 'b+c are correct'. Thus, the correct choice is:

Choice 4: b+c are correct

Answer

b+c are correct

Exercise #7

Expand the following equation:

312+10+5= 3^{12+10+5}=

Video Solution

Step-by-Step Solution

To expand the equation 312+10+5 3^{12+10+5} , we will apply the rule of exponents that states: when you multiply powers with the same base, you can add the exponents. However, in this case, we are starting with a single term and want to represent it as a product of terms with the base being raised to each of the individual exponents given in the sum. Here’s a step-by-step explanation:

1. Start with the expression: 312+10+5 3^{12+10+5} .

2. Recognize that the exponents are added together. According to the property of exponents (Multiplication of Powers), we can express a single power with summed exponents as a product of powers:

3. Break down the exponents: 312+10+5=312×310×35 3^{12+10+5} = 3^{12} \times 3^{10} \times 3^5 .

4. As seen from the explanation: 312+10+5 3^{12+10+5} is expanded to the product 312×310×35 3^{12} \times 3^{10} \times 3^5 by expressing each part of the sum as an exponent with the base 3.

The final expanded form is therefore: 312×310×35 3^{12} \times 3^{10} \times 3^5 .

Answer

312×310×35 3^{12}\times3^{10}\times3^5

Exercise #8

Expand the following equation:

612= 6^{12}=

Video Solution

Step-by-Step Solution

To solve this problem, let's expand 612 6^{12} as a product of three powers of 6:

  • Step 1: Understand that we need three exponents, a a , b b , and c c , such that a+b+c=12 a + b + c = 12 .
  • Step 2: Check each combination in the choices:
    • Choice 1: 63×62×623+2+2=7 6^3 \times 6^2 \times 6^2 \Rightarrow 3 + 2 + 2 = 7 (not equal to 12)
    • Choice 2: 64×64×634+4+3=11 6^4 \times 6^4 \times 6^3 \Rightarrow 4 + 4 + 3 = 11 (not equal to 12)
    • Choice 3: 62×63×672+3+7=12 6^2 \times 6^3 \times 6^7 \Rightarrow 2 + 3 + 7 = 12 (equal to 12) ✔
    • Choice 4: 61×611×61+11+1=13 6^1 \times 6^{11} \times 6 \Rightarrow 1 + 11 + 1 = 13 (not equal to 12)
  • Step 3: Verify that choice 3, 62×63×67 6^2 \times 6^3 \times 6^7 , correctly expands to 612 6^{12} since 62×63×67=62+3+7=612 6^2 \times 6^3 \times 6^7 = 6^{2+3+7} = 6^{12} .

Therefore, the correct expansion of 612 6^{12} is 62×63×67 6^2 \times 6^3 \times 6^7 .

Answer

62×63×67 6^2\times6^3\times6^7

Exercise #9

Expand the following equation:

810= 8^{10}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the base and exponent given in the expression
  • Step 2: Choose an appropriate combination of exponents for the expansion
  • Step 3: Verify the selected combination by checking it matches the rule ax×ay×az=a10 a^x \times a^y \times a^z = a^{10}

Now, let's work through each step:
Step 1: We start with the expression 810 8^{10} . Our goal is to express this as a product of three powers of 8 that sum to the same exponent.
Step 2: Using the exponent addition rule, we need to find three exponents a,b, a, b, and c c such that 8a×8b×8c=810 8^a \times 8^b \times 8^c = 8^{10} . One possible approach is to try combinations that could plausibly sum to 10. For example, let’s choose a=3 a = 3 , b=3 b = 3 , c=4 c = 4 . Observing that 3+3+4=10 3 + 3 + 4 = 10 , a valid distribution can be 83×83×84 8^3 \times 8^3 \times 8^4 .
Step 3: Verify if this aligns with the multiplication of powers: 83×83×84=83+3+4=810 8^3 \times 8^3 \times 8^4 = 8^{3+3+4} = 8^{10} , confirming that this product is indeed equivalent to 810 8^{10} .

Therefore, the correct expanded form of 810 8^{10} is 83×83×84 8^3\times8^3\times8^4 , corresponding to answer choice 2.

Answer

83×83×84 8^3\times8^3\times8^4

Exercise #10

Expand the following equation:

72x+7= 7^{2x+7}=

Video Solution

Step-by-Step Solution

To tackle this problem, we need to expand the expression 72x+7 7^{2x+7} using the properties of exponents:

  • Step 1: Identify the structure of the exponent in the form 2x+7 2x + 7 .
  • Step 2: Recognize this as a sum of two components: 2x 2x and 7 7 .
  • Step 3: Apply the exponent rule am+n=am×an a^{m+n} = a^m \times a^n to separate the expression into two distinct exponent terms.

Now, let's proceed with the solution:

Step 1: Given the exponent is 2x+7 2x + 7 , break it down into individual components:
2x+7=x+x+7 2x + 7 = x + x + 7 .

Step 2: Applying the rule am+n=am×an a^{m+n} = a^m \times a^n :
72x+7=7x+x+7=7x×7x+7 7^{2x+7} = 7^{x+x+7} = 7^x \times 7^{x+7} .

Therefore, the expanded form of the expression is 7x×7x+7 7^x \times 7^{x+7} .

Answer

7x×7x+7 7^x\times7^{x+7}

Exercise #11

Expand the following equation:

g10a+5x= g^{10a+5x}=

Video Solution

Step-by-Step Solution

To solve this problem, we will use the properties of exponents:

  • Step 1: Recognize that the exponent 10a+5x 10a + 5x can be expressed as the sum of two terms, namely (5a+5x)+5a (5a + 5x) + 5a .
  • Step 2: Apply the property gm+n=gm×gn g^{m+n} = g^{m} \times g^{n} to the expression g10a+5x g^{10a + 5x} .
  • Step 3: Expand the expression using the identified split:
    Since 10a+5x=(5a+5x)+5a 10a + 5x = (5a + 5x) + 5a , we have:
    g10a+5x=g(5a+5x)+5a=g5a+5x×g5a g^{10a + 5x} = g^{(5a + 5x) + 5a} = g^{5a + 5x} \times g^{5a} .

Thus, the expanded form of the expression is given by g5a+5x×g5a g^{5a+5x} \times g^{5a} .

Answer

g5a+5x×g5a g^{5a+5x}\times g^{5a}

Exercise #12

Expand the following expression:

46= 4^{-6}=

Video Solution

Step-by-Step Solution

The problem asks us to expand the expression 46 4^{-6} using the rules of exponents.

To start, recognize that the negative exponent 6-6 can be split into smaller parts, which can be achieved by breaking it into two equal parts: 3+(3) -3 + (-3) . This means we can rewrite 46 4^{-6} as:

46=43+(3)=43×43 4^{-6} = 4^{-3 + (-3)} = 4^{-3} \times 4^{-3}

By expressing 46 4^{-6} as a product of two identical terms, 43×43 4^{-3} \times 4^{-3} , we have expanded the original expression correctly according to the rules of exponents. This uses the property of exponents that states am+n=am×an a^{m+n} = a^m \times a^n .

Thus, the expanded form of 46 4^{-6} is 43×43 4^{-3} \times 4^{-3} .

Answer

43×43 4^{-3}\times4^{-3}

Exercise #13

Expand the following expression:

b7= b^7=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the power that needs expansion: b7 b^7 .
  • Step 2: Use the rule for the multiplication of powers to express this as a product of smaller powers of b b .
  • Step 3: Decompose 7 into a sum of smaller numbers and express the power as a product of smaller terms.

Now, let's apply these steps:

Step 1: We have b7 b^7 and need to write it as a product of powers.

Step 2: Recall the rule for multiplication of powers, ba×bb=ba+b b^a \times b^b = b^{a+b} . We will express 7 as the sum of smaller numbers.

Step 3: Choose smaller exponents that add up to 7. Here, we can use 1+2+4=7 1 + 2 + 4 = 7 . Therefore, b7=b1×b2×b4 b^7 = b^1 \times b^2 \times b^4 .

Therefore, the expanded form of the expression is b1×b2×b4 b^1 \times b^2 \times b^4 .

Answer

b1×b2×b4 b^1\times b^2\times b^4

Exercise #14

Expand the following expression:

t9= t^9=

Video Solution

Step-by-Step Solution

To expand the expression t9 t^9 , we will express it as a product of powers. Using the exponent rule, which states that you can multiply powers with the same base by adding their exponents, we need to find powers such that the sum of the exponents equals 9.

Let's consider the expression t4×t2×t3 t^4 \times t^2 \times t^3 . When we apply the multiplication rule of exponents with the same base t t , we have:

  • t9=t4×t2×t3 t^9 = t^4 \times t^2 \times t^3
  • Here, 4+2+3=9 4 + 2 + 3 = 9 , confirming that the sum of the exponents equals the original exponent.

Thus, the expanded form of t9 t^9 is indeed t4×t2×t3 t^4 \times t^2 \times t^3 , which confirms that this is the correct expansion.

Therefore, the solution to the problem is t4×t2×t3\boldsymbol{t^4 \times t^2 \times t^3}.

Answer

t4×t2×t3 t^4\times t^2\times t^3

Exercise #15

Insert the corresponding expression:

97= 9^{-7}=

Video Solution

Step-by-Step Solution

We are given the expression 97 9^{-7} and need to express it as a product of lower powers of 9 using negative exponents. This requires using the properties of exponents:

  • If am×an=am+n a^m \times a^n = a^{m+n} , then you can decompose a power into smaller factors.

To decompose 7-7, we seek integers whose sum equals 7-7. A possible set of integers is 4-4, 2-2, and 1-1. Therefore, we express 97 9^{-7} as:

97=94×92×91 9^{-7} = 9^{-4} \times 9^{-2} \times 9^{-1}

Looking at the given multiple-choice options:

  • Option 1: 97×91 9^{-7} \times 9^{-1} would sum the exponents to become 7+(1)=8 -7 + (-1) = -8 , which is incorrect.
  • Option 2: 94×92×91 9^{-4} \times 9^{-2} \times 9^{-1} correctly adds 4+(2)+(1)=7 -4 + (-2) + (-1) = -7 , matching our requirement.
  • Option 3: 97×91 9^7 \times 9^{-1} simplifies to 71=6 7 - 1 = 6 , not 7-7, so it's incorrect.
  • Option 4: "A+C are correct" is incorrect as neither A nor C solve the problem correctly.

Option 2 is correct. Therefore, the solution is:

The expression 97 9^{-7} can be written as 94×92×91 9^{-4} \times 9^{-2} \times 9^{-1} .

Answer

94×92×91 9^{-4}\times9^{-2}\times9^{-1}

Exercise #16

Expand the following equation:

a3+5= a^{3+5}=

Video Solution

Step-by-Step Solution

To solve this problem, we begin by rewriting the expression that incorporates exponent rules. The expression given is a3+5 a^{3+5} . According to the rule of exponents, when you have a base raised to a power that is a sum, am+n=am×an a^{m+n} = a^m \times a^n .

Let's apply this rule:

  • Write the exponent as a sum: 3+5 3 + 5 .
  • Apply the exponent rule: a3+5 a^{3+5} becomes a3×a5 a^3 \times a^5 .

Thus, the expanded form of a3+5 a^{3+5} using the rule of exponents is a3×a5 a^3 \times a^5 .

Finally, comparing with the provided options, choice 1 ( a3×a5 a^3 \times a^5 ) is the correct one, as it correctly uses the exponent rule.

Therefore, the solution to the problem is a3×a5 a^3\times a^5 .

Answer

a3×a5 a^3\times a^5

Exercise #17

Expand the following equation:

32a+x+a= 3^{2a+x+a}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Analyze the given expression's exponent.
  • Step 2: Apply the exponent addition rule to expand the expression.
  • Step 3: Identify the correct choice from a set of given options.

Now, let's work through each step:
Step 1: The expression given is 32a+x+a 3^{2a + x + a} . Here the exponent is 2a+x+a 2a + x + a .
Step 2: We apply the rule bm+n=bm×bn b^{m+n} = b^m \times b^n by rewriting the exponent sum as individual terms: (2a) (2a) , x x , and a a .
Thus, we can rewrite the expression using the property of exponents: 32a+x+a=32a×3x×3a 3^{2a + x + a} = 3^{2a} \times 3^x \times 3^a .
Step 3: Upon expanding, the solution corresponds to option :

32a×3x×3a 3^{2a}\times3^x\times3^a

.

Therefore, the expanded expression is 32a×3x×3a 3^{2a}\times3^x\times3^a .

Answer

32a×3x×3a 3^{2a}\times3^x\times3^a

Exercise #18

Expand the following equation:

4a+b+c= 4^{a+b+c}=

Video Solution

Step-by-Step Solution

To solve this problem, we will use the rule of exponents that allows us to expand the sum a+b+c a + b + c in the exponent:

  • Given: 4a+b+c 4^{a+b+c}
  • According to the exponent rule xm+n+p=xm×xn×xp x^{m+n+p} = x^m \times x^n \times x^p , we can express:
  • Step: Break down 4a+b+c 4^{a+b+c} to:
  • 4a×4b×4c 4^a \times 4^b \times 4^c

Therefore, the expanded form of the equation is 4a×4b×4c 4^a \times 4^b \times 4^c .

Answer

4a×4b×4c 4^a\times4^b\times4^c

Exercise #19

Expand the following expression:

101= 10^{-1}=

Video Solution

Step-by-Step Solution

Let's solve the problem step by step:

The expression given is 101 10^{-1} . A negative exponent indicates a reciprocal, so:

101=110 10^{-1} = \frac{1}{10}

We can express this as a multiplication form of powers of 10:

Using the property of exponents, specifically the multiplication of powers, we can rewrite:

110=1011×1010 \frac{1}{10} = 10^{-11} \times 10^{10}

To verify:

  • Apply the rule of exponents: 1011×1010=1011+10=101 10^{-11} \times 10^{10} = 10^{-11 + 10} = 10^{-1}

  • This confirms the expression is correctly transformed back to 101 10^{-1} .

Thus, the expanded expression of 101 10^{-1} is:

1011×1010 10^{-11}\times10^{10}

Answer

1011×1010 10^{-11}\times10^{10}

Exercise #20

Expand the following equation:

22a+a= 2^{2a+a}=

Video Solution

Step-by-Step Solution

To solve the problem, we can follow these steps:

  • Step 1: Recognize that the given expression is 22a+a 2^{2a+a} .
  • Step 2: Use the Power of a Power Rule for exponents, which allows us to write am+n=am×an a^{m+n} = a^m \times a^n .
  • Step 3: Rewrite the expression as follows:

Given: 22a+a 2^{2a+a}

Step 4: Simplify the exponent by splitting it:

Since the expression in the exponent is 2a+a 2a+a , we can write:

22a+a=22a×2a 2^{2a+a} = 2^{2a} \times 2^a

Thus, applying the properties of exponents correctly leads us to the expanded form.

Therefore, the expanded equation is 22a×2a 2^{2a} \times 2^a .

Answer

22a×2a 2^{2a}\times2^a