Expand and Simplify: 6x(-2x+3y)+12x² | Algebraic Expression

Distributive Property with Like Term Cancellation

6x(2x+3y)+12x2= 6x(-2x+3y)+12x^2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:02 Let's open parentheses properly
00:05 Make sure the outer term multiplies each of the terms
00:23 Collect like terms
00:27 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

6x(2x+3y)+12x2= 6x(-2x+3y)+12x^2=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Apply the distributive property to expand the expression.
  • Step 2: Simplify the expression by combining like terms.

Now, let's work through each step:

Step 1: Apply the distributive property to 6x(2x+3y) 6x(-2x + 3y) .
This gives us:
6x(2x)+6x(3y)=12x2+18xy 6x \cdot (-2x) + 6x \cdot (3y) = -12x^2 + 18xy .

Step 2: Add this result to 12x2 12x^2 :
12x2+18xy+12x2-12x^2 + 18xy + 12x^2.

Combine like terms:
12x2+12x2-12x^2 + 12x^2 cancels out, leaving 18xy 18xy .

Therefore, the simplified form of the expression is 18xy 18xy .

3

Final Answer

18xy 18xy

Key Points to Remember

Essential concepts to master this topic
  • Distribution: Multiply each term inside parentheses by outside factor
  • Technique: 6x(2x)=12x2 6x(-2x) = -12x^2 and 6x(3y)=18xy 6x(3y) = 18xy
  • Check: Verify like terms cancel: 12x2+12x2=0 -12x^2 + 12x^2 = 0

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute to all terms inside parentheses
    Don't multiply 6x by only one term like 6x(-2x) = -12x² and ignore +3y! This gives incomplete expansion and wrong final answers. Always multiply the outside factor by every single term inside the parentheses.

Practice Quiz

Test your knowledge with interactive questions

Are the expressions the same or not?

\( 20x \)

\( 2\times10x \)

FAQ

Everything you need to know about this question

Why do the x² terms cancel out completely?

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When you distribute 6x(2x) 6x(-2x) , you get 12x2 -12x^2 . Adding the existing +12x2 +12x^2 gives 12x2+12x2=0 -12x^2 + 12x^2 = 0 . Opposite coefficients always cancel!

How do I know which terms are like terms?

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Like terms have the exact same variables with the same powers. Here, 12x2 -12x^2 and 12x2 12x^2 are like terms, but x2 x^2 and xy xy are not.

What if I got 12x² + 18xy as my answer?

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You forgot to include the existing +12x2 +12x^2 term! The full expression is 12x2+18xy+12x2 -12x^2 + 18xy + 12x^2 . When you combine like terms, the x2 x^2 terms cancel out.

Why can't I combine 18xy with anything else?

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The term 18xy 18xy contains both variables x and y, making it unique. There are no other xy terms in the expression to combine with, so it stands alone in the final answer.

How can I check if 18xy is the right answer?

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Substitute simple values like x = 1, y = 1 into both the original expression and your answer. Original: 6(1)(2(1)+3(1))+12(1)2=6(1)+12=18 6(1)(-2(1)+3(1))+12(1)^2 = 6(1)+12 = 18 . Answer: 18(1)(1)=18 18(1)(1) = 18

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