ABCD is a parallelogram.
CE is its height.
CB = 5
AE = 7
EB = 2
What is the area of the parallelogram?
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ABCD is a parallelogram.
CE is its height.
CB = 5
AE = 7
EB = 2
What is the area of the parallelogram?
To find the area,
first, the height of the parallelogram must be found.
To conclude, let's take a look at triangle EBC.
Since we know it is a right triangle (since it is the height of the parallelogram)
the Pythagorean theorem can be used:
In this case:
We place the given information:
We isolate the variable:
We solve:
Now all that remains is to calculate the area.
It is important to remember that for this, the length of each side must be used.
That is, AE+EB=2+7=9
41.24
Look at the triangle in the diagram. How long is side AB?
CB is the slanted side of the parallelogram, not the height! The height must be perpendicular to the base. CE is the perpendicular distance from C to line AB.
CE is described as the height of the parallelogram, which means it's perpendicular to the base AB. This creates a right angle at E, making triangle EBC a right triangle.
The base is the entire bottom side AB. Since AE = 7 and EB = 2, the total base length is AE + EB = 7 + 2 = 9.
Because the height is an irrational number (approximately 4.58). When multiplied by 9, you get 41.24. This is perfectly normal in geometry!
Verify that by calculating: , so ✓
You could use coordinate geometry or trigonometry, but the Pythagorean theorem method is the most straightforward since you're given a right triangle with two known sides.
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