Solve: (10^4 × 0.1^-3 × 10^-8) ÷ 1000 Using Scientific Notation

Exponent Laws with Negative Powers

Solve the following problem:

1040.131081000=? \frac{10^4\cdot0.1^{-3}\cdot10^{-8}}{1000}=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:14 Let's simplify this problem. Ready?
00:20 First, we'll convert the decimal into a fraction.
00:24 Next, we'll break down one thousand as 10 to the power of 3.
00:28 To handle negative exponents, we'll proceed.
00:32 Simply flip the fraction, making the exponent positive.
00:36 Now, let's apply this method in our exercise.
00:49 Try to reduce fractions wherever possible.
00:56 When multiplying powers with the same base, remember...
01:00 The result's exponent is the sum of the existing exponents.
01:05 Let's use this rule and add up the powers. Onward!
01:09 This follows our earlier formula, with one in the denominator.
01:15 And that's our solution! Great job!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

1040.131081000=? \frac{10^4\cdot0.1^{-3}\cdot10^{-8}}{1000}=\text{?}

2

Step-by-step solution

Begin by writing the problem and converting the decimal fraction in the problem to a simple fraction:

1040.131081000=104(110)31081000=? \frac{10^4\cdot0.1^{-3}\cdot10^{-8}}{1000}=\frac{10^4\cdot(\frac{1}{10})^{-3}\cdot10^{-8}}{1000}=\text{?}

Next

a. We'll use the law of exponents for negative exponents:

an=1an a^{-n}=\frac{1}{a^n}

b. Note that the number 1000 is a power of the number 10:

1000=103 1000=10^3

Apply the law of exponents from 'a' and the information from 'b' to the problem:

104(110)31081000=104(101)3108103 \frac{10^4\cdot(\frac{1}{10})^{-3}\cdot10^{-8}}{1000}=\frac{10^4\cdot(10^{-1})^{-3}\cdot10^{-8}}{10^3}

We applied the law of exponents from 'a' to the term inside the parentheses of the middle term in the fraction's numerator. We applied the information from 'b' to the fraction's denominator,

Next, let's recall the law of exponents for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

And we'll apply this law to the same term we dealt with until now in the expression that we obtained in the last step:

104(101)3108103=10410(1)(3)108103=104103108103 \frac{10^4\cdot(10^{-1})^{-3}\cdot10^{-8}}{10^3}=\frac{10^4\cdot10^{(-1)\cdot(-3)}\cdot10^{-8}}{10^3}=\frac{10^4\cdot10^3\cdot10^{-8}}{10^3}

We applied the above law of exponents to the middle term in the numerator carefully, since the term in parentheses has a negative exponent. Hence we used parentheses and then proceeded to simplify the resulting expression,

Note that we can reduce the middle term in the fraction's numerator with the fraction's denominator. This is possible due to the fact that a multiplication operation exists between all terms in the fraction's numerator. Let's proceed to reduce:

104103108103=104108 \frac{10^4\cdot10^3\cdot10^{-8}}{10^3}=10^4\cdot10^{-8}

Let's summarize the various steps to our solution so far:

104(110)31081000=104(101)3108103=104103108103=104108 \frac{10^4\cdot(\frac{1}{10})^{-3}\cdot10^{-8}}{1000}=\frac{10^4\cdot(10^{-1})^{-3}\cdot10^{-8}}{10^3} = \frac{10^4\cdot10^3\cdot10^{-8}}{10^3} = 10^4\cdot10^{-8}

Remember the law of exponents for multiplication of terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n}

Let's apply this law to the expression that we obtained in the last step:

104108=104+(8)1048=104 10^4\cdot10^{-8}=10^{4+(-8)}10^{4-8}=10^{-4}

Now let's once again apply the law of exponents for negative exponents mentioned in 'a' above:

104=1104=110000=0.0001 10^{-4}=\frac{1}{10^4}=\frac{1}{10000}=0.0001

When in the third step we calculated the numerical result of raising 10 to the power of 4 in the fraction's denominator. In the next step we converted the simple fraction to a decimal fraction,

Let's summarize the various steps of our solution so far:

104(110)31081000=104103108103=104=0.0001 \frac{10^4\cdot(\frac{1}{10})^{-3}\cdot10^{-8}}{1000} = \frac{10^4\cdot10^3\cdot10^{-8}}{10^3} = 10^{-4} =0.0001

Therefore the correct answer is answer a.

3

Final Answer

0.0001 0.0001

Key Points to Remember

Essential concepts to master this topic
  • Negative Exponents: an=1an a^{-n} = \frac{1}{a^n} converts negative powers to fractions
  • Power of Power: (101)3=10(1)(3)=103 (10^{-1})^{-3} = 10^{(-1)(-3)} = 10^3 multiply exponents
  • Check: Convert final answer to decimal: 104=110000=0.0001 10^{-4} = \frac{1}{10000} = 0.0001

Common Mistakes

Avoid these frequent errors
  • Forgetting to change signs when dealing with negative exponents
    Don't calculate (0.1)3 (0.1)^{-3} as 103 10^{-3} = wrong negative result! This ignores that negative exponents flip the fraction AND the sign. Always convert 0.13=(110)3=103 0.1^{-3} = (\frac{1}{10})^{-3} = 10^3 carefully.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why does 0.13 0.1^{-3} become positive instead of negative?

+

The negative exponent doesn't make the result negative! It means "flip the fraction". Since 0.1=110 0.1 = \frac{1}{10} , we get (110)3=103=1000 (\frac{1}{10})^{-3} = 10^3 = 1000 which is positive.

How do I remember which exponent law to use when?

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Use this order: 1) Convert decimals to fractions, 2) Apply power rules like (am)n=amn (a^m)^n = a^{mn} , 3) Multiply same bases by adding exponents, 4) Simplify negative exponents last.

Can I just use a calculator for problems like this?

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While calculators help check answers, understanding the steps is crucial! Exponent laws appear in algebra, chemistry, and physics. Practice by hand builds the foundation you'll need later.

What if I get confused with all the negative signs?

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Take it slow! Write each step clearly: 0.13(110)3(101)3103 0.1^{-3} → (\frac{1}{10})^{-3} → (10^{-1})^{-3} → 10^3 . Breaking it down prevents sign errors.

Why convert 1000 to 103 10^3 in the denominator?

+

Converting to the same base (10) lets you use exponent laws! When everything has base 10, you can add/subtract exponents directly instead of doing complex division.

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