Solve Complex Fraction Equation: (√15 + 34/z)/(4y-12+4) = 5

15+34:z4y12+8:2=5 \frac{\sqrt{15}+34:z}{4y-12+8:2}=5

What is the field of application of the equation?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the domain of definition of the function
00:03 According to mathematical laws, division by 0 is forbidden
00:07 Since there is a variable in the denominator, we need to ensure it's different from 0
00:12 This is the first division case we need to verify
00:16 This is the first domain of definition for variable Z
00:27 There is also a variable in the larger numerator of the function
00:36 Therefore in this case we must also ensure that the denominator is different from 0
00:43 We'll solve according to proper mathematical order of operations
00:50 Let's isolate variable Y
01:05 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

15+34:z4y12+8:2=5 \frac{\sqrt{15}+34:z}{4y-12+8:2}=5

What is the field of application of the equation?

2

Step-by-step solution

To solve this problem, we need to identify the values of yy for which the denominator of the expression becomes zero, as these values are not part of the domain.

First, let's simplify the denominator of the given equation:

Original equation: 15+34z4y12+82=5 \frac{\sqrt{15} + \frac{34}{z}}{4y - 12 + \frac{8}{2}} = 5

Simplifying the terms: 34:z remains as it is for simplification purposes, and 82=4 34:z \text{ remains as it is for simplification purposes, and } \frac{8}{2} = 4

Thus, the denominator becomes: (4y12+4)=4y8 (4y - 12 + 4) = 4y - 8

We need to ensure the denominator is not zero to avoid undefined expressions: 4y80 4y - 8 \neq 0

Simplify and solve for yy: 4y80    4y8    y2 4y - 8 \neq 0 \implies 4y \neq 8 \implies y \neq 2

Therefore, the equation is undefined for y=2y = 2, and the answer is that the field of application excludes y=2y = 2.

Given the possible choices for the problem, the correct choice is: y2 y\operatorname{\ne}2

The solution to this problem is y2 y \neq 2 .

3

Final Answer

y2 y\operatorname{\ne}2

Practice Quiz

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Solve for X:

\( x - 3 + 5 = 8 - 2 \)

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