Solve and Apply: Finding the Field of Application for (x+y:3)/(2x+6)=4

Domain Restrictions with Rational Expressions

x+y:32x+6=4 \frac{x+y:3}{2x+6}=4

What is the field of application of the equation?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:12 Let's find the domain of the function.
00:16 Remember, dividing by zero is not okay in math.
00:20 Since our denominator has a variable, it can't be zero.
00:25 So, we need to make sure the main denominator is not zero.
00:30 Now, let's figure out what makes the variable X not equal to zero.
00:36 Once we solve that, we have our answer. And that's how we tackle this problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

x+y:32x+6=4 \frac{x+y:3}{2x+6}=4

What is the field of application of the equation?

2

Step-by-step solution

To solve this problem, we'll follow these steps to find the domain:

  • Step 1: Recognize that the expression x+y:32x+6=4\frac{x+y:3}{2x+6}=4 involves a fraction. The denominator 2x+62x + 6 must not be zero, as division by zero is undefined.
  • Step 2: Set the denominator equal to zero and solve for xx to find the values that must be excluded: 2x+6=02x + 6 = 0.
  • Step 3: Solve 2x+6=02x + 6 = 0:
    • 2x+6=02x + 6 = 0
    • 2x=62x = -6
    • x=3x = -3
  • Step 4: Conclude that the domain of the function excludes x=3x = -3, meaning x3x \neq -3.

Thus, the domain of the given expression is all real numbers except x=3x = -3. This translates to:

x3 x\operatorname{\ne}-3

3

Final Answer

x3 x\operatorname{\ne}-3

Key Points to Remember

Essential concepts to master this topic
  • Domain Rule: Denominator cannot equal zero in rational expressions
  • Technique: Set 2x + 6 = 0, solve to get x = -3
  • Check: Verify x = -3 makes denominator zero: 2(-3) + 6 = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Solving the entire equation instead of finding domain restrictions
    Don't solve (x+y:3)/(2x+6) = 4 for x and y values = wrong focus! The question asks for field of application (domain), not solutions. Always identify what makes the denominator zero first.

Practice Quiz

Test your knowledge with interactive questions

Solve for X:

\( x - 3 + 5 = 8 - 2 \)

FAQ

Everything you need to know about this question

What does 'field of application' mean in math?

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The field of application is another term for domain - all the values that x can take without making the expression undefined. It's where the equation 'works'!

Why can't the denominator be zero?

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Division by zero is undefined in mathematics! When the denominator equals zero, the fraction doesn't have a meaningful value, so we must exclude those x-values.

How do I write 'x cannot equal -3' properly?

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Use the notation x3 x \neq -3 which means 'x is not equal to -3'. You can also write it as x ≠ -3 or say 'all real numbers except x = -3'.

What if there are multiple terms in the denominator?

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Set the entire denominator equal to zero and solve. For example, if the denominator is x24 x^2 - 4 , solve x24=0 x^2 - 4 = 0 to find all restricted values.

Do I need to worry about the numerator being zero?

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No! A numerator can be zero - that just makes the whole fraction equal to zero, which is perfectly fine. Only worry about the denominator being zero.

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