Solve and Apply: Finding the Field of Application for (x+y:3)/(2x+6)=4

Question

x+y:32x+6=4 \frac{x+y:3}{2x+6}=4

What is the field of application of the equation?

Video Solution

Solution Steps

00:12 Let's find the domain of the function.
00:16 Remember, dividing by zero is not okay in math.
00:20 Since our denominator has a variable, it can't be zero.
00:25 So, we need to make sure the main denominator is not zero.
00:30 Now, let's figure out what makes the variable X not equal to zero.
00:36 Once we solve that, we have our answer. And that's how we tackle this problem.

Step-by-Step Solution

To solve this problem, we'll follow these steps to find the domain:

  • Step 1: Recognize that the expression x+y:32x+6=4\frac{x+y:3}{2x+6}=4 involves a fraction. The denominator 2x+62x + 6 must not be zero, as division by zero is undefined.
  • Step 2: Set the denominator equal to zero and solve for xx to find the values that must be excluded: 2x+6=02x + 6 = 0.
  • Step 3: Solve 2x+6=02x + 6 = 0:
    • 2x+6=02x + 6 = 0
    • 2x=62x = -6
    • x=3x = -3
  • Step 4: Conclude that the domain of the function excludes x=3x = -3, meaning x3x \neq -3.

Thus, the domain of the given expression is all real numbers except x=3x = -3. This translates to:

x3 x\operatorname{\ne}-3

Answer

x3 x\operatorname{\ne}-3