Solving xyz/(2(3+y)+4) = 8: Understanding the Field of Application

Domain Restrictions with Rational Expressions

xyz2(3+y)+4=8 \frac{xyz}{2(3+y)+4}=8

What is the field of application of the equation?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the domain of the function
00:03 According to mathematical laws, division by 0 is forbidden
00:07 Since there is a variable in the denominator, we must ensure it is not 0
00:15 To do this, set the denominator equal to 0 and solve
00:18 Properly expand the parentheses, multiply by each factor
00:30 Collect like terms
00:38 Isolate the variable Y
00:52 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

xyz2(3+y)+4=8 \frac{xyz}{2(3+y)+4}=8

What is the field of application of the equation?

2

Step-by-step solution

To find the domain of the given equation xyz2(3+y)+4=8 \frac{xyz}{2(3+y)+4}=8 , we need to ensure the denominator is not zero. This means solving 2(3+y)+4=0 2(3+y) + 4 = 0 .

Let's solve this step-by-step:

  • Step 1: Simplify the expression 2(3+y)+4=0 2(3+y) + 4 = 0 .
  • Step 2: Expand to 6+2y+4=0 6 + 2y + 4 = 0 .
  • Step 3: Combine like terms to get 2y+10=0 2y + 10 = 0 .
  • Step 4: Isolate the variable y y . Subtract 10 from both sides: 2y=10 2y = -10 .
  • Step 5: Divide by 2 to solve for y y : y=5 y = -5 .

If y=5 y = -5 , the denominator becomes zero, which makes the original expression undefined.

Therefore, the value of y y must not be 5-5 for the expression to be valid. In conclusion, the restriction on y y is that y5 y \neq -5 .

The correct answer choice is: y5 y \neq -5 .

3

Final Answer

y5 y\ne-5

Key Points to Remember

Essential concepts to master this topic
  • Domain Rule: Denominator cannot equal zero in any rational expression
  • Technique: Set denominator equal to zero: 2(3+y)+4=0 2(3+y)+4 = 0
  • Check: Verify y=5 y = -5 makes denominator zero, so y5 y \neq -5

Common Mistakes

Avoid these frequent errors
  • Ignoring the denominator when finding domain
    Don't just look at the numerator or focus only on solving the equation = missing critical restrictions! The denominator determines where the expression is undefined. Always identify values that make the denominator zero first.

Practice Quiz

Test your knowledge with interactive questions

Solve for X:

\( 6 - x = 10 - 2 \)

FAQ

Everything you need to know about this question

What exactly is the 'field of application' or domain?

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The domain (or field of application) is all the values that make the expression valid. For fractions, we exclude any values that make the denominator zero because division by zero is undefined.

Why can't the denominator be zero?

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Division by zero is undefined in mathematics! When the denominator equals zero, the fraction has no meaning. That's why we must exclude these values from the domain.

Do I need to worry about the numerator being zero?

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No! If the numerator equals zero, the fraction just equals zero, which is perfectly fine. Only worry about the denominator when finding domain restrictions.

How do I solve 2(3+y)+4 = 0 step by step?

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Step 1: Distribute: 6+2y+4=0 6 + 2y + 4 = 0

Step 2: Combine like terms: 2y+10=0 2y + 10 = 0

Step 3: Subtract 10: 2y=10 2y = -10

Step 4: Divide by 2: y=5 y = -5

What's the difference between y = -5 and y ≠ -5?

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y=5 y = -5 means y equals -5, but y5 y \neq -5 means y can be any value except -5. Since -5 makes our denominator zero, we exclude it from the domain.

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