Solve Rectangle Area: Length = Width + 3, Area = 27 cm²

Quadratic Equations with Rectangle Area Applications

Given: the length of a rectangle is 3 greater than its width.

The area of the rectangle is equal to 27 cm².

Calculate the length of the rectangle

2727273x3x3xxxx

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Calculate the length of rectangle X
00:03 Apply the formula for calculating the area of the rectangle (side x side)
00:07 Insert the relevant values into the formula according to the given data and solve for X
00:16 Isolate X
00:27 Simplify wherever possible
00:40 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given: the length of a rectangle is 3 greater than its width.

The area of the rectangle is equal to 27 cm².

Calculate the length of the rectangle

2727273x3x3xxxx

2

Step-by-step solution

The area of the rectangle is equal to length multiplied by width.

Let's set up the data in the formula:

27=3x×x 27=3x\times x

27=3x2 27=3x^2

273=3x23 \frac{27}{3}=\frac{3x^2}{3}

9=x2 9=x^2

x=9=3 x=\sqrt{9}=3

3

Final Answer

x=3 x=3

Key Points to Remember

Essential concepts to master this topic
  • Formula Setup: Area equals length times width: A=l×w A = l \times w
  • Variable Substitution: Replace length with 3x 3x and width with x x to get 27=3x×x 27 = 3x \times x
  • Check: Verify x=3 x = 3 gives length = 9 and 9×3=27 9 \times 3 = 27

Common Mistakes

Avoid these frequent errors
  • Setting up the equation as addition instead of multiplication
    Don't write 27 = 3 + x because area uses multiplication, not addition! This gives x = 24, but length would be 27 cm, making area 27 × 24 = 648 cm². Always use Area = length × width for rectangle problems.

Practice Quiz

Test your knowledge with interactive questions

Solve for X:

\( x - 3 + 5 = 8 - 2 \)

FAQ

Everything you need to know about this question

Why is the width called x and not just a number?

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We use x because we don't know the width yet! It's our unknown variable that we need to solve for. Once we find x = 3, we know the width is 3 cm.

How do I know which dimension to call x?

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Choose the simpler dimension as x. Since width is 3 less than length, it's easier to call width = x and length = x + 3 (or 3x in this case).

Why does the equation become 3x² instead of 3x × x?

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Because x×x=x2 x \times x = x^2 ! When you multiply a variable by itself, you get that variable squared. So 3x×x=3x2 3x \times x = 3x^2 .

What if I get a negative answer when taking the square root?

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In geometry problems, always use the positive square root because lengths and widths cannot be negative! 9=±3 \sqrt{9} = ±3 , but we only use +3.

How do I check if my final dimensions are correct?

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Substitute back into both conditions: Does length = width + 3? (9 = 3 + 3 ✗, but 9 = 3 × 3 ✓) And does length × width = 27? (9 × 3 = 27 ✓)

Can I solve this without using x²?

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Not easily! This is a quadratic equation because one dimension depends on the other. You need to use algebra with variables to find the unknown measurements.

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