# Subtracting Whole Numbers with Subtraction in Parentheses - Examples, Exercises and Solutions

Subtraction of whole numbers with subtractions in parentheses refers to a situation where we perform the mathematical operation of subtraction on the difference of some terms that are in parentheses.

For example:

$12 - (3-2) =$

One way to solve this exercise will be to distribute the parentheses. To do this, we must remember that according to the law of signs of addition/ subtraction, after removing parentheses, the expressions that were inside them change their sign.

That is, in our example:

$12 - (3-2) =$

$12 - 3 + 2 =$

$9 + 2 = 11$

When distributing the parentheses, we will place a $-$ in front of the number $3$ and a $+$ before the $2$.
As you can see, in both cases the sign that was inside the parentheses has switched to the opposite sign.

Another way to solve this exercise is to use the order of operations, that is to say:

$12 - (3-2) =$

We will start by solving the expression in parentheses by using the order of operations and we will get:

$12 - 1 = 11$

## examples with solutions for subtracting whole numbers with subtraction in parentheses

### Exercise #1

$38-(18+20)=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

$18+20=38$

Now, the exercise obtained is:

$38-38=0$

### Answer

$0$

### Exercise #2

$8-(2+1)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2+1=3$

Now we solve the rest of the exercise:

$8-3=5$

### Answer

$5$

### Exercise #3

$22-(28-3)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$28-3=25$

Now we obtain the exercise:

$22-25=-3$

### Answer

$-3$

### Exercise #4

$12:(2\times2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2\times2=4$

Now we divide:

$12:4=3$

### Answer

$3$

### Exercise #5

$100-(30-21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$30-21=9$

Now we obtain:

$100-9=91$

### Answer

$91$

## examples with solutions for subtracting whole numbers with subtraction in parentheses

### Exercise #1

$80-(4-12)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-12=-8$

Now we obtain the exercise:

$80-(-8)=$

Remember that the product of plus and plus gives us a positive:

$-(-8)=+8$

Now we obtain:

$80+8=88$

### Answer

$88$

### Exercise #2

$7-(4+2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+2=6$

Now we solve the rest of the exercise:

$7-6=1$

### Answer

$1$

### Exercise #3

$37-(4-7)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-7=-3$

Now we obtain:

$37-(-3)=$

Remember that the product of a negative and a negative results in a positive, therefore:

$-(-3)=+3$

Now we obtain:

$37+3=40$

### Answer

$40$

### Exercise #4

$28-(4+9)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+9=13$

Now we obtain the exercise:

$28-13=15$

### Answer

$15$

### Exercise #5

$13-(7+4)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$7+4=11$

Now we subtract:

$13-11=2$

### Answer

$2$

## examples with solutions for subtracting whole numbers with subtraction in parentheses

### Exercise #1

$55-(8+21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$8+21=29$

Now we obtain the exercise:

$55-29=26$

### Answer

$26$

### Exercise #2

$60:(10\times2)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{10\times2}=$

Let's separate the numerator into a multiplication exercise:

$\frac{10\times6}{10\times2}=$

We simplify the 10 in the numerator and denominator, obtaining:

$\frac{6}{2}=3$

### Answer

$3$

### Exercise #3

$60:(5\times3)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{5\times3}$

We break down 60 into a multiplication exercise:

$\frac{20\times3}{5\times3}=$

We simplify the 3s and obtain:

$\frac{20}{5}$

We break down the 5 into a multiplication exercise:

$\frac{5\times4}{5}=$

We simplify the 5 and obtain:

$\frac{4}{1}=4$

### Answer

$4$

### Exercise #4

$73-(22-(-11))=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

Remember that the product of a negative by a negative gives a positive result, therefore:

$-(-11)=+11$

Now we obtain the exercise:

$73-(22+11)=$

We solve the exercise within parentheses:

$22+11=33$

We obtain:

$73-33=40$

### Answer

$40$

### Exercise #5

$-45-(8+10)=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

$8+10=18$

Now we obtain the exercise:

$-45-(18)=$

We open the parentheses, remember to change the corresponding sign:

$-45-18=-63$

### Answer

$-63$