Zeros of Quadratic Functions Practice Problems & Solutions

To solve for the x-intercepts of the function $f(x) = -x^2 + 5x + 6$, we will find the roots of the quadratic equation $-x^2 + 5x + 6 = 0$.

Let's attempt to factor this quadratic equation first. Rewrite the equation as follows:

$-x^2 + 5x + 6 = 0$.

To factor, we look for two numbers that multiply to $-6$ (the product of $a$ and $c$, where $a = -1$ and $c = 6$) and add to $5$ (the middle coefficient $b$).

The numbers that satisfy this condition are $-1$ and $6$.

Thus, the quadratic can be factored as:

$(x - 6)(x + 1) = 0$.

Setting each factor equal to zero gives us:

$x - 6 = 0$ or $x + 1 = 0$.

Solving these equations, we find:

$x = 6$ and $x = -1$.

Thus, the points A and B, the x-intercepts of the function, are:

$(-1, 0)$ and $(6, 0)$.

Therefore, the solution to the problem is $(-1, 0), (6, 0)$.

To solve for points A and B, we find the x-intercepts of the function by setting:

$f(x) = x^2 - 3x - 4 = 0$

We check if it can be factored:

Factor $x^2 - 3x - 4$. The factors of -4 that add to -3 are -4 and 1.

Thus, factor the function as $(x - 4)(x + 1) = 0$.

Set each factor to zero:

• $x - 4 = 0$ implies $x = 4$
• $x + 1 = 0$ implies $x = -1$

These are the x-intercepts, or roots, of the quadratic function.

Therefore, the coordinates of points A and B, where the function intersects the x-axis, are $A(-1, 0)$ and $B(4, 0)$.

The correct choice corresponding to these points is option 3: $A(-1,0), B(4,0)$.

Thus, the solution to the problem is $A(-1,0), B(4,0)$.

To solve for the points A and B, we need to find the roots of the function $f(x) = x^2 - 6x + 5$ where $f(x) = 0$.

Let's proceed step-by-step:

• Step 1: Set the function to zero
  We begin by setting the equation to zero: $x^2 - 6x + 5 = 0$.
• Step 2: Factor the quadratic
  We need to factor the expression. We look for two numbers that multiply to $c = 5$ and add to $b = -6$. These numbers are $-1$ and $-5$.
• Step 3: Write the factorization
  Therefore, we can write the quadratic as: $(x - 1)(x - 5) = 0$.
• Step 4: Solve for the roots
  Set each factor equal to zero: \begin{align*} x - 1 &= 0 \\ x &= 1 \end{align*} \begin{align*} x - 5 &= 0 \\ x &= 5 \end{align*} The roots are $x = 1$ and $x = 5$.
• Step 5: Identify the Points A and B
  The points A and B, where the function intersects the x-axis, are $(1, 0)$ and $(5, 0)$.

Thus, the coordinates of points A and B are $(1,0),(5,0)$, which matches choice 1.

To solve the problem of finding points A and B on the graph of the function $f(x) = x^2 - 6x + 8$, we need to determine where this quadratic function equals zero.

Step-by-step Approach:

• Step 1: Check Factoring Possibility
  The quadratic function is given by:

We will attempt to factor this quadratic expression. We are looking for two numbers that multiply to the constant term, 8, and add to the coefficient of $x$, which is $-6$.

• Step 2: Identify Factors
  The numbers $4$ and $2$ multiply to $8$ and add to $-6$, if we consider their negative counterparts, $-4$ and $-2$:

This matches our expression, confirming that it is the correct factorization.

• Step 3: Solve for Roots
  Set each factor equal to zero:

Thus, the points where the function intersects the x-axis, which are the roots, are $(2,0)$ and $(4,0)$.

Therefore, the solution to the problem is that points A and B are at $(2,0)$ and $(4,0)$.

Final Solution:
The points A and B are $(2,0)$ and $(4,0)$.

To solve for the points A and B, where the graph of $f(x) = x^2 - 6x$ intersects the x-axis, let's solve the equation $f(x) = 0$:
1. Write the equation in standard form:
$x^2 - 6x = 0$.

2. Factor the quadratic equation:
$x(x - 6) = 0$.

3. Set each factor equal to zero:
$x = 0$ or $x - 6 = 0$.

4. Solve each equation for $x$:
$x = 0$ and $x = 6$.

Thus, the points where the function intersects the x-axis, also the points A and B, are $(0,0)$ and $(6,0)$.

Therefore, the solution to the problem is $(6,0), (0,0)$.