Area of a Rectangle - Examples, Exercises and Solutions

Remember that the formula for the area of a rectangle is width times height

We are given that the width of the rectangle is 6

and that the length of the rectangle is 4

 Therefore we calculate:

6*4=24

We begin by multiplying side AB by side BC

We then substitute the given data and we obtain the following:

$4.5\times2=9$

Hence the area of rectangle ABCD equals 9

Let's begin by multiplying side AB by side BC

If we insert the known data into the above equation we should obtain the following:

$10\times2.5=25$

Thus the area of rectangle ABCD equals 25.

Let's calculate the area of the rectangle by multiplying the length by the width:

$AB\times BC=10\times5=50$

Let's calculate the area of the rectangle by multiplying the length by the width:

$AB\times BC=7\times5=35$

We will use the formula to calculate the area of a rectangle: length times width

$9\times6=54$

Let's calculate the area of the rectangle by multiplying the length by the width:

$4\times8=32$

Let's calculate the area of the rectangle by multiplying the length by the width:

$2\times5=10$

Let's calculate the area of the rectangle by multiplying the length by the width:

$11\times7=77$

To calculate the area of the rectangle, we multiply the length by the width:

$15\times3=45$

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information
• Step 2: Apply the appropriate formula
• Step 3: Perform the necessary calculations

Now, let's work through each step:

Step 1: The problem gives us the width, $W = 18$ cm, and the length, $L = 2$ cm.

Step 2: We'll use the formula for the area of a rectangle: $\text{Area} = \text{Length} \times \text{Width}$

Step 3: Plugging in the values, we get: $\text{Area} = 2 \times 18 = 36 \text{ square centimeters}$

Therefore, the area of the rectangle is $36$ square centimeters.

In the provided answer choices, the correct choice is:

Choice 3: $36$

First, we will multiply side AB by side BC.

We know that side BC equals 5, therefore:

$AB\times BC=AB\times5$

We will label side AB as $x$.

Therefore:

$5x=30$

Next, we will divide both sides by 5 to obtain the following:

$x=6$

Therefore:
$BC=6$

The problem requires finding the area of rectangle $ABCD$ with side lengths $AD = 2X$ and $DC = 13X$. We will use the formula for the area of a rectangle:

$A = \text{length} \times \text{width}$

Here, the length and width of the rectangle are $AD$ and $DC$. Therefore:

$A = AD \times DC = (2X) \times (13X)$

Step-by-step calculation:

• Multiply the coefficients: $2 \times 13 = 26$.
• Combine the variable terms: $X \times X = X^2$.

Thus, the area of the rectangle is:

$A = 26X^2$

The solution to the problem is $26X^2$, which corresponds to choice 1.

Let's calculate the area of the rectangle by multiplying the length and width:

$4.5\times8=36$

Let's calculate the area of the rectangle by multiplying the length by the width:

$\text{10}.5\times5=52.5$