Area - Examples, Exercises and Solutions

Question Types:
Area of a Circle: Applying the formulaArea of a Deltoid: Applying the formulaArea of a Parallelogram: Applying the formulaArea of a Rectangle: Applying the formulaArea of a Rhombus: Applying the formulaArea of a Trapezoid: Applying the formulaArea of a Triangle: Applying the formulaArea of the Square: Applying the formulaArea of a Triangle: Ascertaining whether or not there are errors in the dataArea of a Circle: A shape consisting of several shapes (requiring the same formula)Area of a Rectangle: A shape consisting of several shapes (requiring the same formula)Area of a Circle: Calculate The Missing Side based on the formulaArea of a Deltoid: Calculate The Missing Side based on the formulaArea of a Parallelogram: Calculate The Missing Side based on the formulaArea of a Rectangle: Calculate The Missing Side based on the formulaArea of a Rhombus: Calculate The Missing Side based on the formulaArea of a Trapezoid: Calculate The Missing Side based on the formulaArea of a Triangle: Calculate The Missing Side based on the formulaArea of the Square: Calculate The Missing Side based on the formulaArea of a Parallelogram: Calculating in two waysArea of a Triangle: Calculating in two waysArea of a Circle: Calculating parts of the circleArea of a Deltoid: Calculation using percentagesArea of a Rhombus: Calculation using percentagesArea of a Rectangle: Calculation using the diagonalArea of the Square: Express usingArea of a Rectangle: Extended distributive lawArea of a Rhombus: Extended distributive lawArea of a Circle: Finding Area based off Perimeter and Vice VersaArea of a Deltoid: Finding Area based off Perimeter and Vice VersaArea of a Parallelogram: Finding Area based off Perimeter and Vice VersaArea of a Rectangle: Finding Area based off Perimeter and Vice VersaArea of a Rhombus: Finding Area based off Perimeter and Vice VersaArea of a Trapezoid: Finding Area based off Perimeter and Vice VersaArea of a Triangle: Finding Area based off Perimeter and Vice VersaArea of a Triangle: How many times does the shape fit inside of another shape?Area of a Deltoid: Identifying and defining elementsArea of a Triangle: Identifying and defining elementsArea of a Circle: Increasing a specific element by addition of.....or multiplication by.......Area of the Square: Increasing a specific element by addition of.....or multiplication by.......Area of a Circle: Subtraction or addition to a larger shapeArea of a Deltoid: Subtraction or addition to a larger shapeArea of a Rectangle: Subtraction or addition to a larger shapeArea of a Trapezoid: Subtraction or addition to a larger shapeArea of a Triangle: Subtraction or addition to a larger shapeArea of a Trapezoid: Suggesting options for terms when the formula result is knownArea of the Square: True / falseArea of a Circle: Using additional geometric shapesArea of a Deltoid: Using additional geometric shapesArea of a Parallelogram: Using additional geometric shapesArea of a Rectangle: Using additional geometric shapesArea of a Trapezoid: Using additional geometric shapesArea of a Triangle: Using additional geometric shapesArea of a Parallelogram: Using congruence and similarityArea of a Triangle: Using congruence and similarityArea of a Deltoid: Using external heightArea of a Parallelogram: Using external heightArea of a Circle: Using Pythagoras' theoremArea of a Deltoid: Using Pythagoras' theoremArea of a Parallelogram: Using Pythagoras' theoremArea of a Rectangle: Using Pythagoras' theoremArea of a Rhombus: Using Pythagoras' theoremArea of a Trapezoid: Using Pythagoras' theoremArea of a Triangle: Using Pythagoras' theoremArea of a Deltoid: Using ratios for calculationArea of a Parallelogram: Using ratios for calculationArea of a Rectangle: Using ratios for calculationArea of a Rhombus: Using ratios for calculationArea of a Trapezoid: Using ratios for calculationArea of a Triangle: Using ratios for calculationArea of a Rectangle: Using short multiplication formulasArea of a Deltoid: Using variablesArea of a Parallelogram: Using variablesArea of a Rectangle: Using variablesArea of a Rhombus: Using variablesArea of a Trapezoid: Using variablesArea of a Triangle: Using variablesArea of a Deltoid: Verifying whether or not the formula is applicableArea of a Parallelogram: Verifying whether or not the formula is applicableArea of a Rhombus: Verifying whether or not the formula is applicableArea of a Rectangle: Worded problemsArea of a Triangle: Worded problemsArea of the Square: Worded problems

In this article, we will learn what area is, and understand how it is calculated for each shape, in the most practical and simple way there is.
Shall we start?

What is the area?

Area is the definition of the size of something. In mathematics, which is precisely what interests us now, it refers to the size of some figure.
In everyday life, you have surely heard about area in relation to the surface of an apartment, plot of land, etc.
In fact, when they ask what the surface area of your apartment is, they are asking about its size and, instead of answering with words like "big" or "small" we can calculate its area and express it with units of measure. In this way, we can compare different sizes.

Units of measurement of area

Large areas such as apartments are usually measured in meters, therefore, the unit of measurement will be m2 m^2 square meter.
On the other hand, smaller figures are generally measured in centimeters, that is, the unit of measurement for the area will be cm2 cm^2 square centimeter.
Remember:
Units of measurement for the area in cm=>cm2 cm => cm^2
Units of measurement for the area m=>m2 m=>m^2

Suggested Topics to Practice in Advance

  1. Square

Practice Area

Examples with solutions for Area

Exercise #1

Calculate the area of the right triangle below:

101010666888AAACCCBBB

Video Solution

Step-by-Step Solution

Due to the fact that AB is perpendicular to BC and forms a 90-degree angle,

it can be argued that AB is the height of the triangle.

Hence we can calculate the area as follows:

AB×BC2=8×62=482=24 \frac{AB\times BC}{2}=\frac{8\times6}{2}=\frac{48}{2}=24

Answer

24 cm²

Exercise #2

ABDC is a deltoid.

AB = BD

DC = CA

AD = 12 cm

CB = 16 cm

Calculate the area of the deltoid.

161616121212CCCAAABBBDDD

Video Solution

Step-by-Step Solution

First, let's recall the formula for the area of a rhombus:

(Diagonal 1 * Diagonal 2) divided by 2

Now we will substitute the known data into the formula, giving us the answer:

(12*16)/2
192/2=
96

Answer

96 cm²

Exercise #3

Calculate the area of the triangle ABC using the data in the figure.

121212888999AAABBBCCCDDD

Video Solution

Step-by-Step Solution

First, let's remember the formula for the area of a triangle:

(the side * the height that descends to the side) /2

 

In the question, we have three pieces of data, but one of them is redundant!

We only have one height, the line that forms a 90-degree angle - AD,

The side to which the height descends is CB,

Therefore, we can use them in our calculation:

CB×AD2 \frac{CB\times AD}{2}

8×92=722=36 \frac{8\times9}{2}=\frac{72}{2}=36

Answer

36 cm²

Exercise #4

The trapezoid ABCD is shown below.

AB = 2.5 cm

DC = 4 cm

Height (h) = 6 cm

Calculate the area of the trapezoid.

2.52.52.5444h=6h=6h=6AAABBBCCCDDD

Video Solution

Step-by-Step Solution

First, let's remind ourselves of the formula for the area of a trapezoid:

A=(Base + Base) h2 A=\frac{\left(Base\text{ }+\text{ Base}\right)\text{ h}}{2}

We substitute the given values into the formula:

(2.5+4)*6 =
6.5*6=
39/2 = 
19.5

Answer

1912 19\frac{1}{2}

Exercise #5

Given that the diameter of the circle is 7 cm

What is the area?

777

Video Solution

Step-by-Step Solution

First we need the formula for the area of a circle:

 πr2 \pi r^2

In the question, we are given the diameter of the circle, but we still need the radius.

It is known that the radius is actually half of the diameter, therefore:

r=7:2=3.5 r=7:2=3.5

We substitute the value into the formula.

π3.52=12.25π \pi3.5^2=12.25\pi

Answer

12.25π 12.25\pi cm².

Exercise #6

The trapezoid ABCD is shown below.

Base AB = 6 cm

Base DC = 10 cm

Height (h) = 5 cm

Calculate the area of the trapezoid.

666101010h=5h=5h=5AAABBBCCCDDD

Video Solution

Step-by-Step Solution

First, we need to remind ourselves of how to work out the area of a trapezoid:

Formula for calculating trapezoid area

Now let's substitute the given data into the formula:

(10+6)*5 =
2

Let's start with the upper part of the equation:

16*5 = 80

80/2 = 40

Answer

40 cm²

Exercise #7

Shown below is the deltoid ABCD.

The diagonal AC is 8 cm long.

The area of the deltoid is 32 cm².

Calculate the diagonal DB.

S=32S=32S=32888AAABBBCCCDDD

Video Solution

Step-by-Step Solution

First, we recall the formula for the area of a kite: multiply the lengths of the diagonals by each other and divide the product by 2.

We substitute the known data into the formula:

 8DB2=32 \frac{8\cdot DB}{2}=32

We reduce the 8 and the 2:

4DB=32 4DB=32

Divide by 4

DB=8 DB=8

Answer

8 cm

Exercise #8

What is the area of the triangle in the drawing?

5557778.68.68.6

Video Solution

Step-by-Step Solution

First, we will identify the data points we need to be able to find the area of the triangle.

the formula for the area of the triangle: height*opposite side / 2

Since it is a right triangle, we know that the straight sides are actually also the heights between each other, that is, the side that measures 5 and the side that measures 7.

We multiply the legs and divide by 2

5×72=352=17.5 \frac{5\times7}{2}=\frac{35}{2}=17.5

Answer

17.5

Exercise #9

Given the trapezoid:

999121212555AAABBBCCCDDDEEE

What is the area?

Video Solution

Step-by-Step Solution

Formula for the area of a trapezoid:

(base+base)2×altura \frac{(base+base)}{2}\times altura

We substitute the data into the formula and solve:

9+122×5=212×5=1052=52.5 \frac{9+12}{2}\times5=\frac{21}{2}\times5=\frac{105}{2}=52.5

Answer

52.5

Exercise #10

Look at rectangle ABCD below.

Side AB is 10 cm long and side BC is 2.5 cm long.

What is the area of the rectangle?
1010102.52.52.5AAABBBCCCDDD

Video Solution

Step-by-Step Solution

Let's begin by multiplying side AB by side BC

If we insert the known data into the above equation we should obtain the following:

10×2.5=25 10\times2.5=25

Thus the area of rectangle ABCD equals 25.

Answer

25 cm²

Exercise #11

Look at the deltoid in the figure:

777444

What is its area?

Video Solution

Step-by-Step Solution

Let's begin by reminding ourselves of the formula for the area of a kite

Diagonal1×Diagonal22 \frac{Diagonal1\times Diagonal2}{2}

Both these values are given to us in the figure thus we can insert them directly into the formula:

(4*7)/2

28/2

14

Answer

14

Exercise #12

Given the following rectangle:

111111777AAABBBDDDCCC

Find the area of the rectangle.

Video Solution

Step-by-Step Solution

Let's calculate the area of the rectangle by multiplying the length by the width:

11×7=77 11\times7=77

Answer

77

Exercise #13

Given the following rectangle:

222555AAABBBDDDCCC

Find the area of the rectangle.

Video Solution

Step-by-Step Solution

Let's calculate the area of the rectangle by multiplying the length by the width:

2×5=10 2\times5=10

Answer

10

Exercise #14

Given the following rectangle:

888444AAABBBDDDCCC

Find the area of the rectangle.

Video Solution

Step-by-Step Solution

Let's calculate the area of the rectangle by multiplying the length by the width:

4×8=32 4\times8=32

Answer

32

Exercise #15

Look at the rectangle ABCD below.

Given in cm:

AB = 10

BC = 5

Calculate the area of the rectangle.

101010555AAABBBCCCDDD

Video Solution

Step-by-Step Solution

Let's calculate the area of the rectangle by multiplying the length by the width:

AB×BC=10×5=50 AB\times BC=10\times5=50

Answer

50

More Questions

Topics learned in later sections

  1. Area of a square