Calculate Trapezoid Area: Given Parallel Sides 5cm, 9cm and Height 7cm

The formula for the area of a trapezoid is:

$\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$

We are given the following dimensions:

• Base $AB = 5$ cm
• Base $DC = 9$ cm
• Height $h = 7$ cm

Substituting these values into the formula, we have:

$\text{Area} = \frac{1}{2} \times (5 + 9) \times 7$

First, add the lengths of the bases:

$5 + 9 = 14$

Now substitute back into the formula:

$\text{Area} = \frac{1}{2} \times 14 \times 7$

Calculate the multiplication:

$\frac{1}{2} \times 14 = 7$

Then multiply by the height:

$7 \times 7 = 49$

Thus, the area of the trapezoid is 49 cm$^2$.