Exploring Positive and Negative Domains: y = x² + 2x + 4.2

Find the positive and negative domains of the following function:

y=x2+2x+415 y=x^2+2x+4\frac{1}{5}

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1

Understand the problem

Find the positive and negative domains of the following function:

y=x2+2x+415 y=x^2+2x+4\frac{1}{5}

2

Step-by-step solution

To find the positive and negative domains of the function y=x2+2x+4.2 y = x^2 + 2x + 4.2 , we need to consider the graph of this function and its roots.

First, let's compute the discriminant of the quadratic y=x2+2x+4.2 y = x^2 + 2x + 4.2 . The discriminant Δ \Delta is given by b24ac b^2 - 4ac .

Here, a=1 a = 1 , b=2 b = 2 , and c=4.2 c = 4.2 .

Calculating, we have:

Δ=22414.2=416.8=12.8 \Delta = 2^2 - 4 \cdot 1 \cdot 4.2 = 4 - 16.8 = -12.8 .

Since the discriminant is negative, there are no real roots. This means the parabola does not intersect the x-axis.

Next, because a=1 a = 1 is positive, the parabola opens upwards.

Hence, the entire parabola lies above the x-axis, indicating that the function y=x2+2x+4.2 y = x^2 + 2x + 4.2 is positive for all real x x .

Thus, there is no negative domain for this quadratic since it doesn't dip below the x-axis at any point.

Therefore, the positive and negative domains are:

x>0: x > 0 : for all x x

x<0: x < 0 : none

3

Final Answer

x>0: x > 0 : for all x x

x<0: x < 0 : none

Practice Quiz

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The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

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