Given the rectangle ABCD
Given BC=X and the side AB is larger by 4 cm than the side BC.
The area of the triangle ABC is 8X cm².
What is the area of the rectangle?
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Given the rectangle ABCD
Given BC=X and the side AB is larger by 4 cm than the side BC.
The area of the triangle ABC is 8X cm².
What is the area of the rectangle?
Let's calculate the area of triangle ABC:
Multiply by 2:
Divide by x:
Let's move 4 to the left side and change the sign accordingly:
Now let's calculate the area of the rectangle, multiply the length and width where BC equals 12 and AB equals 16:
192
Look at the rectangle below.
Side DC has a length of 1.5 cm and side AD has a length of 9.5 cm.
What is the perimeter of the rectangle?
Triangle ABC is exactly half of rectangle ABCD since the diagonal divides it into two equal triangles. Using the triangle area 8X helps us find the variable X first!
In a rectangle, adjacent sides are perpendicular, so any two connecting sides work as base and height. Here, BC = X and AB = X+4 are perfect choices.
Since X represents a length measurement, it must be positive! If you get negative, check your algebra steps - you might have made an error in solving the equation.
Both methods work! Multiplying by 2 often feels easier: becomes . Choose whichever feels more comfortable to you.
Substitute X=12: Length = 12+4 = 16, Width = 12. Rectangle area = 16 × 12 = 192. Also verify the triangle area matches: ✓
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