**Formula to calculate the area of a scalene triangle:**

Calculate the area of the triangle ABC using the data in the figure.

It's very simple to calculate the area of a scalene triangle if we remember the formula and strictly follow the steps. Don't worry, we're here to teach you exactly what to pay attention to—we won't leave you adrift!**First of all, let's look at the formula you need to remember in order to calculate the area of the scalene triangle:**

Multiply the height by the base (the side corresponding to that height) and divide by $2$.

**Pay attention:**

Make sure to place in the formula the corresponding height and side. That is, if a certain height and a side that does not form a right angle of $90^o$ degrees with the used height is placed in the formula, it will be wrong.

Given the triangle $ABC$

Given that:

$DB=6$ Height

$AC = 7$

What is the area of the triangle?

**Solution:**

We will see that the given side $AC$ actually forms, with the height, an angle of $90^o$ degrees.

After verifying the data, we will go to the formula and place there:

$\frac{6\times7}{2}=21$

The area of the triangle $ABC$ is $21\operatorname{cm}^2$

Test your knowledge

Question 1

Calculate the area of the right triangle below:

Question 2

Calculate the area of the following triangle:

Question 3

Calculate the area of the following triangle:

Given the right triangle $EFG$

Given that:

angle $EFG = 90$

$EF=5$

$FG=6$** Calculate the area of the triangle.**

**Solution:**

Let's remember that the key to calculating the area of any triangle is to multiply the height

by the corresponding side and then divide that product by$2$

In a right triangle, we actually already have the height!

We don't need to calculate another height and, in fact, we can afford to use the given height along with the side that forms the $90^o$ degree angle.

In our exercise: The side is $EF$ or $FG$**What conclusion do we reach?**

The conclusion is that the formula to calculate the area of a right triangle is the product of the two legs divided by $2$Let's put it in the formula and we will get:

$\frac{6\times5}{2}=15$

The area of the triangle $EFG$ is $15cm^2$

Calculating the area of an obtuse triangle is a bit more complicated, but I assure you that once you understand the basic principle, you will be able to calculate the area of an obtuse triangle even in your sleep...

In certain cases, in an obtuse triangle, we will be given a height that is outside the triangle.**As in the following illustration:**

In this illustration, the height $AG$ has been drawn outside of the triangle. In reality, if we were to extend the side $CB$ (marked in green), it would form a right angle with the height.

How is the area of an obtuse triangle calculated?

**Remember the following guidelines and you will do well:**

- In calculating the area of the obtuse triangle, we refer to the actual side length of the triangle and not to its dotted extension.
- In calculating the area of the obtuse triangle, we refer to the given height (even if it is outside the triangle) and look for the corresponding side, which together with it forms a $90^o$ degree angle when extended outside the triangle.

**Now let's solve an exercise so you can understand it more easily:**

Given the triangle $\triangle ABC$

Given that:

$BD= 2$ Height of the triangle

$AD= 5$

$CD= 12$

What is the area of the triangle?

**Solution:**

We observe that the length of the side $DB = 2$

and the corresponding side that forms with it a $90^o$ degree angle (the dotted part outside the triangle) is $CA$

If we go back to the first point we needed to remember - we will understand that, to calculate the area, we must only take into account the length of $AC$ without its dotted extension.

Therefore, we will see it as $12-5=7$

$AC=7$

And now we can safely place the data, according to the basic formula:

$\frac{7\times2}{2}=7$

The area of the triangle $ABC$ is $7cm^2$

Find the area of the triangle (note that this is not always possible)

The formula to calculate the area of a triangle is:

(side * height corresponding to the side) / 2

Note that in the triangle provided to us, we have the length of the side but not the height.

That is, we do not have enough data to perform the calculation.

Cannot be calculated

Which of the following triangles have the same area?

We calculate the area of triangle ABC:

$\frac{12\times5}{2}=\frac{60}{2}=30$

We calculate the area of triangle EFG:

$\frac{6\times10}{2}=\frac{60}{2}=30$

We calculate the area of triangle JIK:

$\frac{6\times5}{2}=\frac{30}{2}=15$

It can be seen that after the calculation, the areas of the similar triangles are ABC and EFG

EFG, ABC

Given the triangle PRS

The length of side SR is 4 cm

The area of the triangle PSR is 30 cm²

Calculate the height PQ

We use the formula to calculate the area of the triangle.

Pay attention: in the obtuse triangle, its height is located outside the triangle!

$\frac{Lado\cdot\text{Altura}}{2}=Área~del~triangulo$

Double the equation by a common denominator.

$\frac{4\cdot PQ}{2}=30$

$\cdot2$

Divide the equation by the coefficient of $PQ$.

$4PQ=60$ / $:4$

$PQ=15$

15 cm

Find X using the data from the figure:

The formula to calculate the area of a triangle is:

(side * height descending from the side) /2

We place the data we have into the formula to find X:

$20=\frac{AB\times AC}{2}$

$20=\frac{x\times5}{2}$

Multiply by 2 to get rid of the fraction:

$5x=40$

Divide both sections by 5:

$\frac{5x}{5}=\frac{40}{5}$

$x=8$

8

The area of trapezoid ABCD is X cm².

The line AE creates triangle AED and parallelogram ABCE.

It is known that the ratio between the area of triangle AED and the area of parallelogram ABCE is 1:3.

Calculate the ratio between sides DE and EC

To calculate the ratio between the sides we will use the existing figure:

$\frac{A_{AED}}{A_{ABCE}}=\frac{1}{3}$

We calculate the ratio between the sides according to the formula to find the area and then replace the data.

We know that the area of triangle ADE is equal to:

$A_{ADE}=\frac{h\times DE}{2}$

We know that the area of the parallelogram is equal to:

$A_{ABCD}=h\times EC$

We replace the data in the formula given by the ratio between the areas:

$\frac{\frac{1}{2}h\times DE}{h\times EC}=\frac{1}{3}$

We solve by cross multiplying and obtain the formula:

$h\times EC=3(\frac{1}{2}h\times DE)$

We open the parentheses accordingly

$h\times EC=1.5h\times DE$

We divide both sides by h

$EC=\frac{1.5h\times DE}{h}$

We simplify to h

$EC=1.5DE$

Therefore, the ratio between$\frac{EC}{DE}=\frac{1}{1.5}$

$1:1.5$

Do you know what the answer is?

Question 1

Calculate the area of the following triangle:

Question 2

Calculate the area of the following triangle:

Question 3

Find the area of the triangle using the data from the figure:

Related Subjects

- Area
- Trapezoids
- Parallelogram
- Perimeter of a Parallelogram
- Kite
- Area of a Deltoid (Kite)
- The Area of a Rhombus
- Congruent Triangles
- How is the radius calculated using its circumference?
- The Center of a Circle
- Area of a circle
- Congruent Rectangles
- Acute triangle
- Obtuse Triangle
- Scalene triangle
- Triangle similarity criteria
- Triangle Height
- Midsegment
- Exterior angle of a triangle
- Relationships Between Angles and Sides of the Triangle
- Relations Between Sides of a Triangle
- Rhombus, kite, or diamond?
- Perimeter
- Triangle
- Angles In Parallel Lines