Extracting Square Roots Practice Problems & Solutions

Master quadratic equations by extracting square roots with step-by-step practice problems. Learn to solve x² - c = 0 equations efficiently and avoid common mistakes.

📚Master Square Root Extraction with Interactive Practice
  • Solve quadratic equations of the form x² - c = 0 using square root extraction
  • Master the three-step process: isolate x², take square roots, write solutions
  • Handle coefficients greater than 1 by dividing to isolate x² completely
  • Recognize when equations have no solution due to negative square roots
  • Work with fractional and radical solutions confidently
  • Apply the ± symbol correctly when extracting square roots

Understanding Extracting Square Roots

Complete explanation with examples

Solution by extracting a root

Solving a quadratic equation with one variable X2c=0X^2-c=0 (where b=0b=0) by calculating the square root:

First step

Moving terms and isolating X2X^2.

Second stage

Take the square root of both sides. Don't forget to insert ±\pm before the square root of the free term.

Third stage

Writing solutions in an organized manner or writing "no solution" in case of a root of a negative number.

Detailed explanation

Practice Extracting Square Roots

Test your knowledge with 15 quizzes

\( 4x^4-12x^3=0 \)

Solve the equation above for x.

Examples with solutions for Extracting Square Roots

Step-by-step solutions included
Exercise #1

Solve the following equation:


2x28=x2+4 2x^2-8=x^2+4

Step-by-Step Solution

Let's solve the equation step-by-step:

  • Step 1: Rearrange the equation.

We start with the given equation:

2x28=x2+42x^2 - 8 = x^2 + 4

Subtract x2+4x^2 + 4 from both sides to get:

2x28x24=02x^2 - 8 - x^2 - 4 = 0

  • Step 2: Simplify the equation.

Combine the like terms:

(2x2x2)84=0(2x^2 - x^2) - 8 - 4 = 0

This simplifies to:

x212=0x^2 - 12 = 0

  • Step 3: Solve for xx.

Add 12 to both sides:

x2=12x^2 = 12

Now take the square root of both sides:

x=±12x = \pm \sqrt{12}

Given the choices, the correct answer is ±12\pm \sqrt{12}.

Answer:

±12 ±\sqrt{12}

Video Solution
Exercise #2

Solve for X:

xx=49 x\cdot x=49

Step-by-Step Solution

We first rearrange and then set the equations to equal zero.

x249=0 x^2-49=0

x272=0 x^2-7^2=0

We use the abbreviated multiplication formula:

(x7)(x+7)=0 (x-7)(x+7)=0

x=±7 x=\pm7

Answer:

±7

Video Solution
Exercise #3

Solve the following:

x2+x23=x2+6 x^2+x^2-3=x^2+6

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Simplify the given equation.
  • Solve for x2 x^2 and find x x .

First, let's simplify the equation:

x2+x23=x2+6 x^2 + x^2 - 3 = x^2 + 6 .

Combine like terms on the left side:

2x23=x2+6 2x^2 - 3 = x^2 + 6 .

Subtract x2 x^2 from both sides to isolate one of the x x terms:

2x2x23=6 2x^2 - x^2 - 3 = 6 .

This simplifies to:

x23=6 x^2 - 3 = 6 .

Next, add 3 to both sides to solve for x2 x^2 :

x2=9 x^2 = 9 .

To find x x , take the square root of both sides:

x=±9 x = \pm\sqrt{9} .

This results in:

x=±3 x = \pm3 .

Therefore, the solution to the problem is ±3\pm3.

Answer:

±3

Video Solution
Exercise #4

Solve the following exercise:

2x28=x2+4 2x^2-8=x^2+4

Step-by-Step Solution

First, we move the terms to one side equal to 0.

2x2x284=0 2x^2-x^2-8-4=0

We simplify :

x212=0 x^2-12=0

We use the shortcut multiplication formula to solve:

x2(12)2=0 x^2-(\sqrt{12})^2=0

(x12)(x+12)=0 (x-\sqrt{12})(x+\sqrt{12})=0

x=±12 x=\pm\sqrt{12}

Answer:

±12 ±\sqrt{12}

Video Solution
Exercise #5

Solve the following exercise

x3x+7=2x2+9 x\cdot3\cdot x+7=2x^2+9

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Simplify the given expression.
  • Rearrange into standard quadratic form.
  • Solve using applicable method.

Let's begin the process:
1. Simplify the left-hand side: x3x+7=3x2+7 x \cdot 3 \cdot x + 7 = 3x^2 + 7 .

2. Set up the equation by balancing: 3x2+7=2x2+9 3x^2 + 7 = 2x^2 + 9 .

3. Rearrange the terms to form a quadratic equation: 3x22x2+79=0 3x^2 - 2x^2 + 7 - 9 = 0 .

This simplifies to: x22=0 x^2 - 2 = 0 .

4. Solve for x x :
By adding 2 to both sides, we have: x2=2 x^2 = 2 .
Take the square root of both sides: x=±2 x = \pm\sqrt{2} .

Therefore, the solution to the problem is ±2 \pm\sqrt{2} .

Answer:

±2 ±\sqrt{2}

Video Solution

Frequently Asked Questions

What is the square root extraction method for quadratic equations?

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The square root extraction method is used to solve quadratic equations of the form x² - c = 0 (where b = 0). It involves three steps: isolate x² on one side, take the square root of both sides with ± symbol, and write the two solutions clearly.

When can I use square root extraction instead of the quadratic formula?

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Use square root extraction when your quadratic equation has no middle term (b = 0) and looks like ax² + c = 0. This method is much faster than the quadratic formula for these specific equations.

Why do I need to use ± when extracting square roots?

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The ± symbol is essential because every positive number has two square roots: one positive and one negative. For example, both 4 and -4 when squared equal 16, so x = ±4 gives you both solutions.

What happens if I get a negative number under the square root?

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If you need to find the square root of a negative number, the equation has no real solution. You cannot find a real number that when squared gives a negative result, so write 'no solution' as your answer.

How do I handle coefficients in front of x² when extracting square roots?

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First divide both sides by the coefficient to completely isolate x². For example, with 3x² = 9, divide both sides by 3 to get x² = 3, then take the square root: x = ±√3.

Should I simplify square roots in my final answer?

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Yes, always simplify square roots when possible. For example, √16 should be written as 4, not left as √16. However, if the square root cannot be simplified to a whole number, it's acceptable to leave it in radical form.

What are the most common mistakes when extracting square roots?

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Common mistakes include: 1) Forgetting the ± symbol, 2) Not completely isolating x² before taking the square root, 3) Trying to find the square root of a negative number instead of writing 'no solution', and 4) Not simplifying final answers when possible.

Can I use square root extraction for equations like x² + 4 = 0?

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Yes, you can apply the method, but this specific equation has no real solution. After isolating x², you get x² = -4, and since you cannot take the square root of a negative number, the answer is 'no solution'.

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