Additional Arithmetic Rules Practice Problems & Solutions

Master subtraction of sums, subtraction of differences, division by products, and division by quotients with step-by-step practice problems and solutions.

📚Master Advanced Arithmetic Rules with Interactive Practice
  • Apply subtraction of sum rule: a-(b+c) = a-b-c in complex expressions
  • Solve subtraction of difference problems using a-(b-c) = a-b+c formula
  • Master division by product rule: a:(b·c) = a:b:c with step-by-step solutions
  • Practice division by quotient problems using a:(b:c) = a:b·c method
  • Compare multiple solution methods for each arithmetic rule type
  • Build confidence solving parentheses problems with distributive properties

Understanding Additional Arithmetic Rules

Complete explanation with examples

More arithmetic rules: subtraction of a sum, subtraction of a difference, division by product, and division by quotient

In this article, we will dive into the world of essential arithmetic rules that are fundamental for tackling a wide variety of mathematical exercises. Mastering these rules will provide you with a solid foundation and allow you to solve problems with greater confidence and precision. From basic operations like addition and subtraction to more advanced concepts like the division of products and quotients, we will explore each of these rules in detail. Are you ready to deepen your mathematical skills?
Let's get started!

Detailed explanation

Practice Additional Arithmetic Rules

Test your knowledge with 40 quizzes

\( 99:(33:10)= \)

Examples with solutions for Additional Arithmetic Rules

Step-by-step solutions included
Exercise #1

15:(2×5)= 15:(2\times5)= ?

Step-by-Step Solution

First we need to apply the following formula:

a:(b×c)=a:b:c a:(b\times c)=a:b:c

Therefore, we get:

15:2:5= 15:2:5=

Now, let's rewrite the exercise as a fraction:

1525= \frac{\frac{15}{2}}{5}=

Then we'll convert it to a multiplication of two fractions:

152×15= \frac{15}{2}\times\frac{1}{5}=

Finally, we multiply numerator by numerator and denominator by denominator, leaving us with:

1510=1510=112 \frac{15}{10}=1\frac{5}{10}=1\frac{1}{2}

Answer:

112 1\frac{1}{2}

Video Solution
Exercise #2

10:(10:5)= 10:(10:5)=

Step-by-Step Solution

To solve the expression 10:(10:5) 10 : (10 : 5) , we will apply the order of operations systematically.

Step 1: Evaluate the inner division 10:5 10 : 5 .
When we compute 10:5 10 : 5 , we are finding how many times 5 fits into 10. This calculation can be expressed as:
105=2 \frac{10}{5} = 2 .

Step 2: Substitute the result from step 1 into the outer division.
Now, we substitute 10:(10:5) 10 : (10 : 5) with 10:2 10 : 2 . Once again, we apply division:
102=5 \frac{10}{2} = 5 .

Therefore, the solution to the expression 10:(10:5) 10 : (10 : 5) is 5 5 .

Answer:

5 5

Video Solution
Exercise #3

18:(6×3)= 18:(6\times3)=

Step-by-Step Solution

To solve the expression 18÷(6×3) 18 \div (6 \times 3) , we need to follow the order of operations, which specifies that multiplication should be performed before division. Therefore, we proceed as follows:

  • Step 1: Calculate the operation inside the parentheses: (6×3)(6 \times 3).
    We multiply 66 by 33 to get 1818.
  • Step 2: Replace the multiplication expression in the original division: 18÷1818 \div 18.
  • Step 3: Perform the division: 18÷18=118 \div 18 = 1.

Thus, the result of the expression 18÷(6×3) 18 \div (6 \times 3) is 1\mathbf{1}.

Answer:

1

Video Solution
Exercise #4

2(1+1)= 2-(1+1)=

Step-by-Step Solution

To solve the expression 2(1+1) 2 - (1 + 1) , follow these steps:

  • First, evaluate the expression inside the parentheses: 1+1 1 + 1 .
  • This gives 2 2 .
  • Now replace the parentheses with this result, transforming the expression to 22 2 - 2 .
  • The result of 22 2 - 2 is 0 0 .

Therefore, the solution to the expression is 0 0 .

Answer:

0

Video Solution
Exercise #5

19(5+11)= 19-(5+11)=

Step-by-Step Solution

To solve the problem 19(5+11)19 - (5 + 11), we will follow these steps:

  • Step 1: Evaluate the expression inside the parentheses. This means we need to calculate 5+115 + 11.
  • Step 2: Once the sum inside the parentheses is found, subtract this sum from 19.

Let's work through each step:

Step 1: Calculate 5+115 + 11 which equals 16.

Step 2: Substitute 16 in place of 5+115 + 11 in the original expression. You have 191619 - 16.

Now, solve 191619 - 16, which equals 3.

Therefore, the solution to the problem is 33.

Answer:

3

Video Solution

Frequently Asked Questions

What is the subtraction of a sum rule in arithmetic?

+
The subtraction of a sum rule states that a-(b+c) = a-b-c. This means when subtracting a sum in parentheses, you can distribute the negative sign to each term inside the parentheses. For example, 21-(7+2) = 21-7-2 = 12.

How do you solve subtraction of difference problems?

+
Use the rule a-(b-c) = a-b+c. When subtracting a difference, distribute the negative sign: the first term becomes negative and the second term becomes positive. For instance, 33-(9-3) = 33-9+3 = 27.

What is division by product rule and how does it work?

+
The division by product rule is a:(b·c) = a:b:c. You can divide by each factor separately instead of multiplying first. Example: 50:(2·5) = 50:2:5 = 25:5 = 5, which equals 50:10 = 5.

How is division by quotient different from division by product?

+
Division by quotient follows the rule a:(b:c) = a:b·c. You divide by the first term and multiply by the second term. For example, 48:(6:2) = 48:6·2 = 8·2 = 16, or solve parentheses first: 48:3 = 16.

Why do these arithmetic rules work with algebraic expressions?

+
These rules apply to algebraic expressions because they follow the same mathematical properties as numbers. The distributive property, associative property, and order of operations remain consistent whether using numbers or variables.

When should I use the rule vs order of operations?

+
Both methods give the same result. Use the rule method when you want to practice distributive properties or when parentheses contain complex expressions. Use order of operations when the calculation inside parentheses is simple and quick to compute.

What are common mistakes with subtraction of difference problems?

+
The most common mistake is forgetting that minus times minus equals plus. In a-(b-c), students often write a-b-c instead of a-b+c. Remember: the negative sign changes both terms in the parentheses.

How can I remember these arithmetic rules easily?

+
Use these memory aids: 1) Subtraction distributes to all terms, 2) Division by product splits into separate divisions, 3) Division by quotient flips the second operation (division becomes multiplication), 4) Practice with simple numbers first before using variables.

More Additional Arithmetic Rules Questions

Continue Your Math Journey

Practice by Question Type