# Subtracting Whole Numbers with Addition in Parentheses - Examples, Exercises and Solutions

Subtraction of whole numbers with addition in parentheses refers to a situation where we must perform the mathematical operation of subtraction on the sum of some terms that are in parentheses.
In this case, we must remember that the subtraction will be performed on each and every term separately.

The rule is as follows:

$a - (b +c) = a - b - c$

Each of the terms has its own numerical value.

## examples with solutions for subtracting whole numbers with addition in parentheses

### Exercise #1

$38-(18+20)=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

$18+20=38$

Now, the exercise obtained is:

$38-38=0$

$0$

### Exercise #2

$8-(2+1)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2+1=3$

Now we solve the rest of the exercise:

$8-3=5$

$5$

### Exercise #3

$22-(28-3)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$28-3=25$

Now we obtain the exercise:

$22-25=-3$

$-3$

### Exercise #4

$12:(2\times2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2\times2=4$

Now we divide:

$12:4=3$

$3$

### Exercise #5

$100-(30-21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$30-21=9$

Now we obtain:

$100-9=91$

$91$

## examples with solutions for subtracting whole numbers with addition in parentheses

### Exercise #1

$80-(4-12)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-12=-8$

Now we obtain the exercise:

$80-(-8)=$

Remember that the product of plus and plus gives us a positive:

$-(-8)=+8$

Now we obtain:

$80+8=88$

$88$

### Exercise #2

$7-(4+2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+2=6$

Now we solve the rest of the exercise:

$7-6=1$

$1$

### Exercise #3

$37-(4-7)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-7=-3$

Now we obtain:

$37-(-3)=$

Remember that the product of a negative and a negative results in a positive, therefore:

$-(-3)=+3$

Now we obtain:

$37+3=40$

$40$

### Exercise #4

$28-(4+9)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+9=13$

Now we obtain the exercise:

$28-13=15$

$15$

### Exercise #5

$13-(7+4)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$7+4=11$

Now we subtract:

$13-11=2$

$2$

## examples with solutions for subtracting whole numbers with addition in parentheses

### Exercise #1

$55-(8+21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$8+21=29$

Now we obtain the exercise:

$55-29=26$

$26$

### Exercise #2

$60:(10\times2)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{10\times2}=$

Let's separate the numerator into a multiplication exercise:

$\frac{10\times6}{10\times2}=$

We simplify the 10 in the numerator and denominator, obtaining:

$\frac{6}{2}=3$

$3$

### Exercise #3

$60:(5\times3)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{5\times3}$

We break down 60 into a multiplication exercise:

$\frac{20\times3}{5\times3}=$

We simplify the 3s and obtain:

$\frac{20}{5}$

We break down the 5 into a multiplication exercise:

$\frac{5\times4}{5}=$

We simplify the 5 and obtain:

$\frac{4}{1}=4$

$4$

### Exercise #4

$73-(22-(-11))=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

Remember that the product of a negative by a negative gives a positive result, therefore:

$-(-11)=+11$

Now we obtain the exercise:

$73-(22+11)=$

We solve the exercise within parentheses:

$22+11=33$

We obtain:

$73-33=40$

$40$

### Exercise #5

$-45-(8+10)=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

$8+10=18$

Now we obtain the exercise:

$-45-(18)=$

We open the parentheses, remember to change the corresponding sign:

$-45-18=-63$

$-63$