Division of Whole Numbers Within Parentheses Involving Division - Examples, Exercises and Solutions

The division of whole numbers within parentheses where there is a division refers to the situation in which we must carry out the mathematical operation of dividing a whole number by the result of dividing two elements, that is, by their quotient.

For example:

24:(6:2)24 : (6 : 2)

There are two ways to solve this type of exercises.

The first one will be to open the parentheses and extract the numbers that were inside them.

That is, in our example:

24:(6:2)=24 : (6 : 2) =

24:6×2= 24:6\times2=

4×2=8 4\times2=8

A - Division of Whole Numbers Within Parentheses Involving Division

Suggested Topics to Practice in Advance

  1. The commutative property
  2. The Commutative Property of Addition
  3. The Commutative Property of Multiplication
  4. The Distributive Property
  5. The Distributive Property for Seventh Graders
  6. The Distributive Property of Division
  7. The Distributive Property in the Case of Multiplication
  8. The commutative properties of addition and multiplication, and the distributive property
  9. The Associative Property
  10. The Associative Property of Addition
  11. The Associative Property of Multiplication

Practice Division of Whole Numbers Within Parentheses Involving Division

Exercise #1

60:(10×2)= 60:(10\times2)=

Video Solution

Step-by-Step Solution

We write the exercise in fraction form:

6010×2= \frac{60}{10\times2}=

Let's separate the numerator into a multiplication exercise:

10×610×2= \frac{10\times6}{10\times2}=

We simplify the 10 in the numerator and denominator, obtaining:

62=3 \frac{6}{2}=3

Answer

3 3

Exercise #2

12:(2×2)= 12:(2\times2)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

2×2=4 2\times2=4

Now we divide:

12:4=3 12:4=3

Answer

3 3

Exercise #3

7(4+2)= 7-(4+2)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

4+2=6 4+2=6

Now we solve the rest of the exercise:

76=1 7-6=1

Answer

1 1

Exercise #4

8(2+1)= 8-(2+1)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

2+1=3 2+1=3

Now we solve the rest of the exercise:

83=5 8-3=5

Answer

5 5

Exercise #5

13(7+4)= 13-(7+4)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

7+4=11 7+4=11

Now we subtract:

1311=2 13-11=2

Answer

2 2

Exercise #1

38(18+20)= 38-(18+20)=

Video Solution

Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

18+20=38 18+20=38

Now, the exercise obtained is:

3838=0 38-38=0

Answer

0 0

Exercise #2

28(4+9)= 28-(4+9)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

4+9=13 4+9=13

Now we obtain the exercise:

2813=15 28-13=15

Answer

15 15

Exercise #3

55(8+21)= 55-(8+21)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

8+21=29 8+21=29

Now we obtain the exercise:

5529=26 55-29=26

Answer

26 26

Exercise #4

37(47)= 37-(4-7)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

47=3 4-7=-3

Now we obtain:

37(3)= 37-(-3)=

Remember that the product of a negative and a negative results in a positive, therefore:

(3)=+3 -(-3)=+3

Now we obtain:

37+3=40 37+3=40

Answer

40 40

Exercise #5

80(412)= 80-(4-12)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

412=8 4-12=-8

Now we obtain the exercise:

80(8)= 80-(-8)=

Remember that the product of plus and plus gives us a positive:

(8)=+8 -(-8)=+8

Now we obtain:

80+8=88 80+8=88

Answer

88 88

Exercise #1

100(3021)= 100-(30-21)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

3021=9 30-21=9

Now we obtain:

1009=91 100-9=91

Answer

91 91

Exercise #2

22(283)= 22-(28-3)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

283=25 28-3=25

Now we obtain the exercise:

2225=3 22-25=-3

Answer

3 -3

Exercise #3

60:(5×3)= 60:(5\times3)=

Video Solution

Step-by-Step Solution

We write the exercise in fraction form:

605×3 \frac{60}{5\times3}

We break down 60 into a multiplication exercise:

20×35×3= \frac{20\times3}{5\times3}=

We simplify the 3s and obtain:

205 \frac{20}{5}

We break down the 5 into a multiplication exercise:

5×45= \frac{5\times4}{5}=

We simplify the 5 and obtain:

41=4 \frac{4}{1}=4

Answer

4 4

Exercise #4

35:(2×7)= 35:(2\times7)=

Video Solution

Step-by-Step Solution

We write the exercise in fraction form:

352×7= \frac{35}{2\times7}=

We separate the numerator into a multiplication exercise:

7×52×7= \frac{7\times5}{2\times7}=

We simplify the 7 in the numerator and denominator, obtaining:

52=212 \frac{5}{2}=2\frac{1}{2}

Answer

212 2\frac{1}{2}

Exercise #5

9:(3×2)= 9:(3\times2)=

Video Solution

Step-by-Step Solution

We rewrite the expression as a fraction:

93×2= \frac{9}{3\times2}=

We rewrite the numerator as a multiplication expression:

3×33×2= \frac{3\times3}{3\times2}=

We simplify the 3 in the numerator and denominator, obtaining:

32=112=1.5 \frac{3}{2}=1\frac{1}{2}=1.5

Answer

1.5 1.5

Topics learned in later sections

  1. Advanced Arithmetic Operations
  2. Subtracting Whole Numbers with Addition in Parentheses