# Division of Whole Numbers Within Parentheses Involving Division - Examples, Exercises and Solutions

The division of whole numbers within parentheses where there is a division refers to the situation in which we must carry out the mathematical operation of dividing a whole number by the result of dividing two elements, that is, by their quotient.

For example:

$24 : (6 : 2)$

There are two ways to solve this type of exercises.

The first one will be to open the parentheses and extract the numbers that were inside them.

That is, in our example:

$24 : (6 : 2) =$

$24:6\times2=$

$4\times2=8$

## Examples with solutions for Division of Whole Numbers Within Parentheses Involving Division

### Exercise #1

$100-(30-21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$30-21=9$

Now we obtain:

$100-9=91$

$91$

### Exercise #2

$13-(7+4)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$7+4=11$

Now we subtract:

$13-11=2$

$2$

### Exercise #3

$12:(2\times2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2\times2=4$

Now we divide:

$12:4=3$

$3$

### Exercise #4

$15:(2\times5)=$

### Step-by-Step Solution

We will use the formula:

$a:(b\times c)=a:b:c$

Therefore, we get:

$15:2:5=$

Let's write the exercise as a fraction:

$\frac{\frac{15}{2}}{5}=$

We'll convert it to a multiplication of two fractions:

$\frac{15}{2}\times\frac{1}{5}=$

We multiply numerator by numerator and denominator by denominator, and we get:

$\frac{15}{10}=1\frac{5}{10}=1\frac{1}{2}$

$1\frac{1}{2}$

### Exercise #5

$55-(8+21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$8+21=29$

Now we obtain the exercise:

$55-29=26$

$26$

### Exercise #6

$60:(5\times3)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{5\times3}$

We break down 60 into a multiplication exercise:

$\frac{20\times3}{5\times3}=$

We simplify the 3s and obtain:

$\frac{20}{5}$

We break down the 5 into a multiplication exercise:

$\frac{5\times4}{5}=$

We simplify the 5 and obtain:

$\frac{4}{1}=4$

$4$

### Exercise #7

$60:(10\times2)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{10\times2}=$

Let's separate the numerator into a multiplication exercise:

$\frac{10\times6}{10\times2}=$

We simplify the 10 in the numerator and denominator, obtaining:

$\frac{6}{2}=3$

$3$

### Exercise #8

$28-(4+9)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+9=13$

Now we obtain the exercise:

$28-13=15$

$15$

### Exercise #9

$37-(4-7)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-7=-3$

Now we obtain:

$37-(-3)=$

Remember that the product of a negative and a negative results in a positive, therefore:

$-(-3)=+3$

Now we obtain:

$37+3=40$

$40$

### Exercise #10

$22-(28-3)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$28-3=25$

Now we obtain the exercise:

$22-25=-3$

$-3$

### Exercise #11

$38-(18+20)=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

$18+20=38$

Now, the exercise obtained is:

$38-38=0$

$0$

### Exercise #12

$7-(4+2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+2=6$

Now we solve the rest of the exercise:

$7-6=1$

$1$

### Exercise #13

$8-(2+1)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2+1=3$

Now we solve the rest of the exercise:

$8-3=5$

$5$

### Exercise #14

$66-(15-10)=$

### Step-by-Step Solution

According to the order of operations rules, we first solve the expression inside of the parentheses:

$15-10=5$

We obtain the following expression:

$66-5=61$

$61$

### Exercise #15

$21:(30:10)=$

### Step-by-Step Solution

We will use the formula:

$a:(b:c)=a:b\times c$

Therefore, we will get:

$21:30\times10=$

Let's write the division exercise as a fraction:

$\frac{21}{30}=\frac{7}{10}$

Now let's multiply by 10:

$\frac{7}{10}\times\frac{10}{1}=$

We'll reduce the 10 and get:

$\frac{7}{1}=7$

$7$