The Associative Property of Multiplication - Examples, Exercises and Solutions

First, we'll solve the right-hand exercise, since adding the numbers will give us a round number:

$5+5=10$

Now we'll get an easier exercise to solve:

$13+10=23$

First, we'll solve the right-hand exercise, since adding the numbers will give us a round number:

$2+8=10$

Now we'll get an easier exercise to solve:

$38+10=48$

First, we'll solve the left exercise, since adding the numbers will give us a round number:

$8+2=10$

Now we'll get an easier exercise to solve:

$10+7=17$

First, we'll solve the left exercise, since adding the numbers will give us a round number:

$13+7=20$

Now we'll get an easier exercise to solve:

$20+100=120$

We will use the commutative property and first solve the addition exercise on the right:

$2+8=10$

Now we get:

$13+10=23$

Let's break down 4 into a smaller addition problem:

$3+1$

Now we'll get the exercise:

$3+1+9+8=$

Since the exercise only involves addition, we'll use the commutative property and start with the exercise:

$1+9=10$

Now we'll get the exercise:

$3+10+8=$

Let's solve the exercise from right to left:

$10+8=18$

$18+3=21$

We solve the exercise from left to right, we place the addition exercise in parentheses and then subtract:

$(2+4)-3=$

$6-3=3$

First, we place the subtraction exercise in parentheses, and then we add:

$(-3-2)+10=$

$-5+10=$

We use the substitution property to make solving the exercise easier:

$10-5=5$

Given that in the exercise there is only one addition operation, the substitution property can be used:

$5+4+2a=$

We solve the exercise from left to right:

$5+4=9$

Now we obtain:

$2a+9$

We solve the exercise according to the order of operations.

We place the addition and subtraction exercises in parentheses in the following way to make it easier to solve:

$(2+6)-10+(30-2)=$

We solve the exercises in parentheses:

$8-10+28=$

We place the subtraction exercise in parentheses:

$(8-10)+28=$

$-2+28=26$

According to the order of operations, we first solve the division exercise, and then the subtraction:

$(6:2)+9-4=$

$6:2=3$

Now we place the subtraction exercise in parentheses:

$3+(9-4)=$

$3+5=8$

According to the rules of the order of operations, we first solve the division exercise:

$9:3=3$

Now we obtain the exercise:

$3-3=0$

According to the rules of the order of operations, we first solve the division exercise:

$6:2=3$

Now we get the exercise:

$-5+2-3=$

We solve the exercise from left to right:

$-5+2=-3$

$-3-3=-6$

According to the rules of the order of operations, we first solve the multiplication exercise:

$4\times2=8$

Now we obtain the exercise:

$8-5+4=$

We solve the exercise from left to right:

$8-5=3$

$3+4=7$

According to the rules of the order of operations, you can use the substitution property and start the exercise from right to left to calculate comfortably:

$8+12=20$

Now we obtain the exercise:

$7+20=27$