Distributive property for seventh grade - Examples, Exercises and Solutions

$94+72=$

To facilitate the resolution process, we break down 94 and 72 into smaller numbers. Preferably round numbers

We obtain:

$90+4+70+2=$

Using the associative property, we arrange the exercise in a more comfortable way:

$90+70+4+2=$

We solve the exercise in the following way, first the round numbers and then the small numbers.

$90+70=160$

$4+2=6$

Now we obtain the exercise:

$160+6=166$

166

$63-36=$

To solve the problem, first we will use the distributive property on the two numbers:

(60+3)-(30+6)

Now, we will use the substitution property to arrange the exercise in the way that is most convenient for us to solve:

60-30+3-6

It is important to pay attention that when we open the second parentheses, the minus sign moved to the two numbers inside.

30-3 = 

27

27

$133+30=$

To solve the question, we first use the distributive property for 133:

$(100+33)+30=$

Now we use the distributive property for 33:

$100+30+3+30=$

We arrange the exercise in a more comfortable way:

$100+30+30+3=$

We solve the middle exercise:

$30+30=60$

Now we obtain the exercise:

$100+60+3=163$

163

$140-70=$

To facilitate the resolution process, we use the distributive property for 140:

$100+40-70=$

Now we arrange the exercise using the substitution property in a more convenient way:

$100-70+40=$

We solve the exercise from left to right:

$100-70=30$

$30+40=70$

70

Solve the exercise:

84:4=

There are several ways to solve the exercise,

We will present two of them.

In both ways, in the first step we divide the number 84 into 80 and 4.

$\frac{4}{4}=1$

And thus we are left with only the 80.

From the first method, we will decompose 80 into$10\times8$

We know that:$\frac{8}{4}=2$

And therefore, we reduce the exercise $\frac{10}{4}\times8$

In fact, we will be left with$2\times10$

which is equal to 20

In the second method, we decompose 80 into$40+40$

We know that: $\frac{40}{4}=10$

And therefore: $\frac{40+40}{4}=\frac{80}{4}=20=10+10$

which is also equal to 20

Now, let's remember the 1 from the first step and add them:

$20+1=21$

And thus we manage to decompose that:$\frac{84}{4}=21$

21

Which equation is the same as the following?

$13\times29$

We solve each of the options and keep in mind the order of arithmetic operations: calculation of the operation within parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$(10+3)\times(30-1)=13\times29$

b.

$10\times3\times30\times1=30\times30\times1=900$

c.

$(10\times3)\times30=13\times30$

d.

$10\times3+29=30+29=59$

Therefore, the answer is option A.

$(10+3)\times(30-1)$

Which equation is the same as the following?

$36\times4$

We solve each of the options and keep in mind the order of operations: calculation of the operation within parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$36+4=40$

b.

$4\times(30+6)=4\times36$

c.

$40-4+4=36+4=40$

d.

$4\times30+6=120+6=126$

Therefore, the answer is option B.

$4\times(30+6)$

Which equation is the same as the following?

$3\times83$

We solve each of the options and keep in mind the order of arithmetic operations: calculation of the operation within parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$3\times8\times3=24\times3=72$

b.

$(2+1)\times(80+3)=3\times83$

c.

$3+(80+3)=3+83$

d.

$3+83=86$

Therefore, the answer is option B.

$(2+1)\times(80+3)$

Which equation is the same as the following?

$14\times42$

We solve each of the options and keep in mind the order of operations: calculation of the operation within parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$10+4+40+2=14+42=36$

b.

$(10\times4)+(40\times2)=40+80$

c.

$(10+4)\times(40+2)=14\times42$

d.

$10\times4\times40\times2=40\times40\times2=160\times2=360$

Therefore, the answer is option C.

$(10+4)\times(40+2)$

Which equation is the same as the following?

$160\times6$

We solve each of the options and keep in mind the order of operations: calculation of the operation inside parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$160+6=166$

b.

$(100\times60)\times6=6,000\times6$

c.

$(100+60)+(3+3)=160+6$

d.

$(100+60)\times(3+3)=160\times6$

Therefore, the answer is option D.

$(100+60)\times(3+3)$

Which equation is the same as the following?

$34\times11$

We solve each of the options and keep in mind the order of operations: calculation of the operation within parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$(30+4)+11=34+11$

b.

$30\times4\times11=120\times11=1,320$

c.

$(30+4)+10+1=34+11$

d.

$(30+4)\times(10+1)=34\times11$

Therefore, the answer is option D.

$(30+4)\times(10+1)$

Which equation is the same as the following?

$39\times19$

We solve each of the options and keep in mind the order of operations: calculation of the operation within parentheses, multiplication and division (from left to right), addition and subtraction (from left to right).

a.

$(30×9)+(10×9)= 270+90$

b.

$(30+9)×(10×9)= 39×90$

c.

$(40-1)×(20-1)= 39×19$

d.

$(40-1)+(20×1)= 39+20$

Therefore, the answer is option C.

$(40-1)\times(20-1)$

$4\times53=$

To make solving easier, we break down 53 into more comfortable numbers, preferably round ones.

We obtain:

$4\times(50+3)=$

We multiply 2 by each of the terms inside the parentheses:

$(4\times50)+(4\times3)=$

We solve the exercises inside the parentheses and obtain:

$200+12=212$

212

$11\times34=$

To make solving easier, we break down 11 into more comfortable numbers, preferably round ones.

We obtain:

$(10+1)\times34=$

We multiply 34 by each of the terms in parentheses:

$(34\times10)+(34\times1)=$

We solve the exercises in parentheses and obtain:

$340+34=374$

374

$6\times29=$

To make solving easier, we break down 29 into more comfortable numbers, preferably round ones.

We obtain:

$6\times(30-1)=$

We multiply 6 by each of the terms in parentheses:

$(6\times30)-(6\times1)=$

We solve the exercises in parentheses and obtain:

$180-6=174$

174