Power Property of Logorithms - Examples, Exercises and Solutions

To simplify the expression $3\log_76$, we apply the power property of logarithms, which states:

$a\log_b c = \log_b(c^a)$

Step 1: Identify the given expression: $3\log_76$.

Step 2: Apply the power property of logarithms:

$3\log_76 = \log_7(6^3)$

Step 3: Calculate $6^3$:

$6^3 = 6 \times 6 \times 6 = 36 \times 6 = 216$

Step 4: Substitute back into the logarithmic expression:

$\log_7(6^3) = \log_7216$

Therefore, the simplified expression is $\log_7216$.

Comparing with the answer choices, the correct choice is:

$\log_7216$

To solve this problem, let's simplify $2\log_3 8$ using logarithm rules.

• Step 1: Recognize the expression form
  The expression is of the form $a \cdot \log_b c$, where $a = 2$, $b = 3$, and $c = 8$.
• Step 2: Apply the power property
  According to the power property of logarithms, $2 \cdot \log_3 8$ can be simplified to $\log_3 (8^2)$.
• Perform the calculation
  Calculate $8^2$, which is $64$.
• Step 3: Simplify further
  Therefore, we have $\log_3 64$.

This is a straightforward application of the power property of logarithms. By applying this property correctly, we've simplified the original expression correctly.

Therefore, the simplified form of $2\log_3 8$ is $\log_3 64$.

To solve the problem $\log_6 8$, we need to express the number 8 as a power of a base that simplifies the logarithm. We can write 8 as $2^3$, because 8 equals 2 multiplied by itself three times.

Let's use the power property of logarithms, which is:

• $\log_b (a^n) = n \log_b a$

Applying this property to $\log_6 8$, we have:

$\log_6 8 = \log_6 (2^3)$

Using the power property, this becomes:

$\log_6 (2^3) = 3 \log_6 2$

Therefore, the expression for $\log_6 8$ in terms of $\log_6 2$ is:

$3 \log_6 2$.

To solve this problem, we'll follow the steps outlined:

• Step 1: Recognize that the expression $x \ln 7$ can be thought of in terms of the power property of logarithms, which helps reframe it into a single logarithm.
• Step 2: Apply the formula $\ln(a^b) = b \ln a$. This tells us that if we have something of the form $b \ln a$, we can express it as $\ln(a^b)$.
• Step 3: Utilize the known expression and rule by substituting $a = 7$ and $b = x$. Thus, $x \ln 7$ becomes $\ln(7^x)$.

Therefore, the rewritten expression for $x \ln 7$ using logarithm rules is $\ln 7^x$.

This matches choice 4 from the provided options.

To solve the inequality $7\log_4 2 < \log_4 x$, we will follow these steps:

• Step 1: Simplify $7\log_4 2$ using the logarithm properties.
• Step 2: Write the inequality $\log_4(2^7) < \log_4 x$.
• Step 3: Solve for $x$ by converting the logarithmic inequality into an exponential form.

Let's now proceed with these steps:

Step 1: Using the power property of logarithms, we have $7\log_4 2 = \log_4 (2^7)$. This step simplifies the multiplication into a single logarithmic term.

Step 2: Using substitution in the inequality, we write it as $\log_4 (2^7) < \log_4 x$.

Step 3: Since logarithms are one-to-one functions, we can conclude that if $\log_4 (2^7) < \log_4 x$, then $2^7 < x$. This results from the property $a^c = a^d \iff c = d$ where the bases are equal.

Therefore, the solution to the inequality is $\mathbf{2^7 < x}$.