Find the Domain of y=-(x+7)²-5: Negative Quadratic Function Analysis

Domain Analysis with Negative Quadratic Functions

Find the positive and negative domains of the function below:

y=(x+7)25 y=-\left(x+7\right)^2-5

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+7)25 y=-\left(x+7\right)^2-5

2

Step-by-step solution

The function given is y=(x+7)25 y = -\left(x + 7\right)^2 - 5 , which is a parabola that opens downwards. Let's determine the positive and negative domains:

Firstly, we identify the vertex of the function as (7,5) (-7, -5) . The vertex form tells us that the parabola opens downwards because the coefficient of the squared term is negative (a=1 a = -1 ). This indicates that the maximum point of the parabola is at the vertex, and the function decreases on either side of the vertex.

Given the downward opening of the parabola and the maximum value y=5 y = -5 at x=7 x = -7 , the graph of the parabola lies entirely beneath this maximum point. Thus, the function is always non-positive.

Since the function never crosses the x-axis and is below or equal to the vertex's y-coordinate at all points, we find that:

  • No values of x x give y>0 y > 0 , so the positive domain is empty.
  • All real values of x x result in y0 y \leq 0 , indicating a negative domain for x x .

Therefore, the solutions are:

x<0: x < 0 : none

x>0: x > 0 : all x x

The correct choice is:

Choice 4: x<0: x < 0 : none

x>0: x > 0 : all x x

3

Final Answer

x<0: x < 0 : none

x>0: x > 0 : all x x

Key Points to Remember

Essential concepts to master this topic
  • Vertex Form: y=a(xh)2+k y = a(x-h)^2 + k reveals vertex at (h,k) (h,k)
  • Sign Analysis: When a<0 a < 0 , parabola opens downward with maximum at vertex
  • Domain Check: All real numbers give valid outputs, so domain is all x x

Common Mistakes

Avoid these frequent errors
  • Confusing domain with range or positive/negative y-values
    Don't restrict domain based on y-values = missing valid x-inputs! Domain asks what x-values work, not what y-values result. Always remember domain is all possible x-inputs that produce real outputs.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

FAQ

Everything you need to know about this question

What's the difference between domain and range?

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Domain is all possible x-values you can input. Range is all possible y-values that come out. For y=(x+7)25 y = -(x+7)^2 - 5 , domain is all real numbers, but range is y5 y ≤ -5 .

Why is the domain all real numbers if the function is always negative?

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Domain only cares about what x-values work, not what y-values result! You can substitute any real number for x and get a real output, so domain is unrestricted.

How do I find where the function is positive or negative?

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Since the maximum y-value is 5 -5 at the vertex, and the parabola opens downward, all y-values are negative or zero. The function is never positive!

What does the vertex (-7, -5) tell me?

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The vertex shows the highest point since the parabola opens downward. At x=7 x = -7 , the maximum y-value is 5 -5 . All other points have smaller (more negative) y-values.

Why don't the answer choices make sense to me?

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The question seems to have unclear wording about 'positive and negative domains.' Based on standard terminology, domain is all real x-values for this function, regardless of output signs.

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