Triangle ABC is an isosceles triangle AB=AC
AD is the height of the BC
Given DC=10
The length of the height AD is greater by 20% than the length of the side BC.
Calculate the area of the triangle ABC
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Triangle ABC is an isosceles triangle AB=AC
AD is the height of the BC
Given DC=10
The length of the height AD is greater by 20% than the length of the side BC.
Calculate the area of the triangle ABC
Given that it is an isosceles triangle if then .
We are told that the height is greater by percent
than the length of the side.
That is:
From here we can calculate the area of the triangle :
240 cm²
Complete the sentence:
To find the area of a right triangle, one must multiply ________________ by each other and divide by 2.
In an isosceles triangle, the height from the vertex angle to the base always bisects the base. This means BD = DC, so BC = BD + DC = 10 + 10 = 20.
'Greater by 20%' means the new value is 100% + 20% = 120% of the original. Convert to decimal: , so AD = 1.2 × BC.
Adding 20 gives you 20 units more, not 20% more! Percentage increases are multiplicative: 20% of 20 is 4, so AD = 20 + 4 = 24, which equals 1.2 × 20.
For any triangle, use Area = . Here, BC is the base (20) and AD is the height (24), giving us .
Double-check by working backwards: if Area = 240 and BC = 20, then height = . Verify: is 24 exactly 20% more than 20? Yes, because 24 = 1.2 × 20!
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