Triangle Angle Problem: Finding Angle A = 3(B + C)

Triangle Angle Sum with Proportional Relationships

Shown below is the triangle ABC.

A ∢A is 3 times greater than the sum of the rest of the angles.

Calculate A ∢A .AAABBBCCC

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find angle A
00:04 The sum of angles in a triangle equals 180
00:13 Let's substitute the angle value expression according to the given data
00:23 Let's put the sum in parentheses as well
00:41 Let's isolate the sum of angles
00:48 This is the value of the sum of angles, now let's substitute in the expression for angle A
01:06 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Shown below is the triangle ABC.

A ∢A is 3 times greater than the sum of the rest of the angles.

Calculate A ∢A .AAABBBCCC

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Use the angle sum property of triangle ABC ABC .
  • Step 2: Set up an equation using the condition that A=3(B+C) ∢A = 3(∢B + ∢C) .
  • Step 3: Solve the equations to find A ∢A .

Now, let's work through each step:
Step 1: According to the angle sum property of a triangle:
A+B+C=180 ∢A + ∢B + ∢C = 180^\circ Step 2: We are given A=3(B+C) ∢A = 3(∢B + ∢C) . Substitute this relationship into the equation from Step 1:
3(B+C)+B+C=180 3(∢B + ∢C) + ∢B + ∢C = 180^\circ Step 3: Simplify the equation:
Start by letting B+C=x ∢B + ∢C = x , then A=3x ∢A = 3x . Substitute into the equation:
3x+x=180 3x + x = 180^\circ 4x=180 4x = 180^\circ Solving for x x :
x=1804=45 x = \frac{180^\circ}{4} = 45^\circ So, B+C=45 ∢B + ∢C = 45^\circ . Since A=3x ∢A = 3x :
A=3×45=135 ∢A = 3 \times 45^\circ = 135^\circ

Therefore, the measure of angle A ∢A is 135 \mathbf{135^\circ} .

3

Final Answer

135°

Key Points to Remember

Essential concepts to master this topic
  • Rule: All triangle angles sum to exactly 180 degrees
  • Technique: Let ∢B + ∢C = x, then ∢A = 3x gives 4x = 180°
  • Check: Verify 135° + 45° = 180° and 135° = 3(45°) ✓

Common Mistakes

Avoid these frequent errors
  • Setting up equation as A = 3B + 3C instead of A = 3(B + C)
    Don't write ∢A = 3∢B + 3∢C = individual angles tripled! This misinterprets 'three times the sum' as 'sum of three times each.' Always write ∢A = 3(∢B + ∢C) to multiply the entire sum by 3.

Practice Quiz

Test your knowledge with interactive questions

Is DE side in one of the triangles?
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FAQ

Everything you need to know about this question

What does 'three times greater than the sum' actually mean?

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It means A=3×(B+C) ∢A = 3 \times (∢B + ∢C) . First add angles B and C together, then multiply that sum by 3 to get angle A.

Why can't I just divide 180° by 3 to get each angle?

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That would only work if all angles were equal! But this triangle has unequal angles where one angle is much larger than the others due to the special relationship given.

How do I check if 135° makes sense for a triangle?

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Since 135° is less than 180° but greater than 90°, this is an obtuse triangle. The other two angles (totaling 45°) are both acute, which is perfectly valid!

What if I get confused by the wording of the problem?

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Break it down step by step: 'A is 3 times greater than the sum of the rest' means A = 3 × (sum of other angles). Always translate word problems into mathematical equations first.

Can angle A be bigger than 90 degrees in a triangle?

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Absolutely! One angle in a triangle can be obtuse (greater than 90°) as long as it's less than 180°. The other two angles will be acute to make the total equal 180°.

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