Triangle Angle Problem: Finding Angle A = 3(B + C)

Question

Shown below is the triangle ABC.

A ∢A is 3 times greater than the sum of the rest of the angles.

Calculate A ∢A .AAABBBCCC

Video Solution

Solution Steps

00:00 Find angle A
00:04 The sum of angles in a triangle equals 180
00:13 Let's substitute the angle value expression according to the given data
00:23 Let's put the sum in parentheses as well
00:41 Let's isolate the sum of angles
00:48 This is the value of the sum of angles, now let's substitute in the expression for angle A
01:06 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Use the angle sum property of triangle ABC ABC .
  • Step 2: Set up an equation using the condition that A=3(B+C) ∢A = 3(∢B + ∢C) .
  • Step 3: Solve the equations to find A ∢A .

Now, let's work through each step:
Step 1: According to the angle sum property of a triangle:
A+B+C=180 ∢A + ∢B + ∢C = 180^\circ Step 2: We are given A=3(B+C) ∢A = 3(∢B + ∢C) . Substitute this relationship into the equation from Step 1:
3(B+C)+B+C=180 3(∢B + ∢C) + ∢B + ∢C = 180^\circ Step 3: Simplify the equation:
Start by letting B+C=x ∢B + ∢C = x , then A=3x ∢A = 3x . Substitute into the equation:
3x+x=180 3x + x = 180^\circ 4x=180 4x = 180^\circ Solving for x x :
x=1804=45 x = \frac{180^\circ}{4} = 45^\circ So, B+C=45 ∢B + ∢C = 45^\circ . Since A=3x ∢A = 3x :
A=3×45=135 ∢A = 3 \times 45^\circ = 135^\circ

Therefore, the measure of angle A ∢A is 135 \mathbf{135^\circ} .

Answer

135°