Exponents Rules - Examples, Exercises and Solutions

Question Types:
Applying Combined Exponents Rules: A power lawApplying Combined Exponents Rules: Applying the formulaApplying Combined Exponents Rules: BinomialApplying Combined Exponents Rules: Calculating powers with negative exponentsApplying Combined Exponents Rules: Complete the equationApplying Combined Exponents Rules: converting Negative Exponents to Positive ExponentsApplying Combined Exponents Rules: Factoring Out the Greatest Common Factor (GCF)Applying Combined Exponents Rules: FactorizationApplying Combined Exponents Rules: Identify the greater valueApplying Combined Exponents Rules: MonomialApplying Combined Exponents Rules: More than one unknownApplying Combined Exponents Rules: Multiplying Exponents with the same baseApplying Combined Exponents Rules: Number of termsApplying Combined Exponents Rules: Presenting powers in the denominator as powers with negative exponentsApplying Combined Exponents Rules: Presenting powers with negative exponents as fractionsApplying Combined Exponents Rules: Presenting powers with negative exponents as fractionsApplying Combined Exponents Rules: Single VariableApplying Combined Exponents Rules: The power of zeroApplying Combined Exponents Rules: TrinomialApplying Combined Exponents Rules: Two VariablesApplying Combined Exponents Rules: Using laws of exponents with parametersApplying Combined Exponents Rules: Using multiple rulesApplying Combined Exponents Rules: Using the laws of exponentsApplying Combined Exponents Rules: Using variablesApplying Combined Exponents Rules: Variable in the base of the powerApplying Combined Exponents Rules: Variable in the exponent of the powerApplying Combined Exponents Rules: Variables in the exponent of the powerApplying Combined Exponents Rules: Worded problems

Definition of Exponentiation

Exponents are a way to write the multiplication of a term by itself several times in a shortened form.

The number that is multiplied by itself is called the base, while the number of times the base is multiplied is called the exponent.

A - Exponentiation

an=aaa a^n=a\cdot a\cdot a ... (n times)

For example:

5555=54 5\cdot5\cdot5\cdot5=5^4

5 5 is the base, while 4 4 is the exponent.

In this case, the number 5 5 is multiplied by itself 4 4 times and, therefore, it is expressed as 5 5 to the fourth power or 5 5 to the power of 4 4 .

Practice Exponents Rules

Examples with solutions for Exponents Rules

Exercise #1

2423= \frac{2^4}{2^3}=

Video Solution

Step-by-Step Solution

Let's keep in mind that the numerator and denominator of the fraction have terms with the same base, therefore we use the property of powers to divide between terms with the same base:

bmbn=bmn \frac{b^m}{b^n}=b^{m-n}

We apply it in the problem:

2423=243=21 \frac{2^4}{2^3}=2^{4-3}=2^1

Remember that any number raised to the 1st power is equal to the number itself, meaning that:

b1=b b^1=b

Therefore, in the problem we obtain:

21=2 2^1=2

Therefore, the correct answer is option a.

Answer

2 2

Exercise #2

9993= \frac{9^9}{9^3}=

Video Solution

Step-by-Step Solution

Note that in the fraction and its denominator, there are terms with the same base, so we will use the law of exponents for division between terms with the same base:

bmbn=bmn \frac{b^m}{b^n}=b^{m-n}

Let's apply it to the problem:

9993=993=96 \frac{9^9}{9^3}=9^{9-3}=9^6

Therefore, the correct answer is b.

Answer

96 9^6

Exercise #3

(35)4= (3^5)^4=

Video Solution

Step-by-Step Solution

To solve the exercise we use the power property:(an)m=anm (a^n)^m=a^{n\cdot m}

We use the property with our exercise and solve:

(35)4=35×4=320 (3^5)^4=3^{5\times4}=3^{20}

Answer

320 3^{20}

Exercise #4

(62)13= (6^2)^{13}=

Video Solution

Step-by-Step Solution

We use the formula:

(an)m=an×m (a^n)^m=a^{n\times m}

Therefore, we obtain:

62×13=626 6^{2\times13}=6^{26}

Answer

626 6^{26}

Exercise #5

50= 5^0=

Video Solution

Step-by-Step Solution

We use the power property:

X0=1 X^0=1 We apply it to the problem:

50=1 5^0=1 Therefore, the correct answer is C.

Answer

1 1

Exercise #6

1120=? 112^0=\text{?}

Video Solution

Step-by-Step Solution

We use the zero exponent rule.

X0=1 X^0=1 We obtain

1120=1 112^0=1 Therefore, the correct answer is option C.

Answer

1

Exercise #7

Solve the following problem:

(34)×(32)= \left(3^4\right)\times\left(3^2\right)=

Video Solution

Step-by-Step Solution

In order to solve this problem, we'll follow these steps:

  • Step 1: Identify the base and exponents

  • Step 2: Use the formula for multiplying powers with the same base

  • Step 3: Simplify the expression by applying the relevant exponent rule

Now, let's work through each step:

Step 1: The given expression is (34)×(32) (3^4) \times (3^2) . Here, the base is 3, and the exponents are 4 and 2.

Step 2: Apply the exponent rule, which states that when multiplying powers with the same base, we add the exponents:
am×an=am+n a^m \times a^n = a^{m+n}

Step 3: Using the rule identified in Step 2, we add the exponents 4 and 2:
34×32=34+2=36 3^4 \times 3^2 = 3^{4+2} = 3^6

Therefore, the simplified form of the expression is 36 3^6 .

Answer

36 3^6

Exercise #8

3532= \frac{3^5}{3^2}=

Video Solution

Step-by-Step Solution

Using the quotient rule for exponents: aman=amn \frac{a^m}{a^n} = a^{m-n} .

Here, we have 3532=352 \frac{3^5}{3^2} = 3^{5-2}

Simplifying, we get 33 3^3

Answer

33 3^3

Exercise #9

5654= \frac{5^6}{5^4}=

Video Solution

Step-by-Step Solution

Using the quotient rule for exponents: aman=amn \frac{a^m}{a^n} = a^{m-n} .

Here, we have 5654=564 \frac{5^6}{5^4} = 5^{6-4} . Simplifying, we get 52 5^2 .

Answer

52 5^2

Exercise #10

Insert the corresponding expression:

6764= \frac{6^7}{6^4}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Identify the given information and relevant exponent rules.

  • Apply the quotient property of exponents.

  • Simplify the expression.

Now, let's work through each step:
Step 1: The problem gives us the expression 6764 \frac{6^7}{6^4} . The base is 6, and the exponents are 7 and 4, respectively.
Step 2: According to the rule of exponents, when dividing powers with the same base, we subtract the exponents: aman=amn \frac{a^m}{a^n} = a^{m-n} In this case, a=6 a = 6 , m=7 m = 7 , and n=4 n = 4 .
Step 3: Applying this rule gives us: 6764=674=63 \frac{6^7}{6^4} = 6^{7 - 4} = 6^3

Therefore, the solution to the problem is 63 6^3 .

Answer

63 6^3

Exercise #11

Insert the corresponding expression:

(92)4= \left(9^2\right)^4=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the provided expression: (92)4(9^2)^4.

  • Step 2: Apply the power of a power rule for exponents.

  • Step 3: Simplify by multiplying the exponents.

Now, let's work through each step:

Step 1: We have the expression (92)4(9^2)^4.

Step 2: Using the power of a power rule ((am)n=amn(a^m)^n = a^{m \cdot n}), apply it to the expression:

(92)4=92×4 (9^2)^4 = 9^{2 \times 4}

Step 3: Simplify by calculating the product of the exponents:

2×4=8 2 \times 4 = 8

Therefore, (92)4=98(9^2)^4 = 9^8.

The correct expression corresponding to the given problem is 98\boxed{9^8}.

Answer

98 9^8

Exercise #12

Simplify the following equation:

47×53×42×54= 4^7\times5^3\times4^2\times5^4=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify and group the terms with the same base.

  • Step 2: Apply the laws of exponents to simplify by adding the exponents of each base.

  • Step 3: Write the simplified form.

Let's work through each step:

Step 1: We are given that 47×53×42×54 4^7 \times 5^3 \times 4^2 \times 5^4 .

Step 2: First, group the terms with the same base:

47×42 4^7 \times 4^2 and 53×54 5^3 \times 5^4 .

Step 3: Use the law of exponents, which states am×an=am+n a^m \times a^n = a^{m+n} .

For the base 4: 47×42=47+2=49 4^7 \times 4^2 = 4^{7+2} = 4^9 .

For the base 5: 53×54=53+4=57 5^3 \times 5^4 = 5^{3+4} = 5^7 .

Therefore, the simplified form of the expression is 49×57 4^9 \times 5^7 .

Answer

49×57 4^9\times5^7

Exercise #13

Simplify the following equation:

75×23×72×24= 7^5\times2^3\times7^2\times2^4=

Video Solution

Step-by-Step Solution

To solve this problem, we'll apply the laws of exponents to simplify the expression 75×23×72×24 7^5 \times 2^3 \times 7^2 \times 2^4 .

Let's follow these steps:

  • Step 1: Identify like bases.
    We have two like bases in the expression: 7 and 2.

  • Step 2: Apply the product of powers rule for each base separately.
    For the base 7: 75×72=75+2=77 7^5 \times 7^2 = 7^{5+2} = 7^7 .
    For the base 2: 23×24=23+4=27 2^3 \times 2^4 = 2^{3+4} = 2^7 .

  • Step 3: Combine the results.
    The expression simplifies to 77×27 7^7 \times 2^7 .

The simplified form of the original expression is therefore 77×27 7^7 \times 2^7 .

Answer

77×27 7^7\times2^7

Exercise #14

Simplify the following equation:

53×24×52×23= 5^3\times2^4\times5^2\times2^3=

Video Solution

Step-by-Step Solution

Let's simplify the expression 53×24×52×23 5^3 \times 2^4 \times 5^2 \times 2^3 using the rules for exponents. We'll apply the product of powers rule, which states that when multiplying like bases, you can add the exponents.

  • Step 1: Focus on terms with the same base.
    Combine 53 5^3 and 52 5^2 . Since both terms have the base 55, we apply the rule am×an=am+na^m \times a^n = a^{m+n}: 53×52=53+2=55 5^3 \times 5^2 = 5^{3+2} = 5^5

  • Step 2: Combine 24 2^4 and 23 2^3 . Similarly, for the base 22: 24×23=24+3=27 2^4 \times 2^3 = 2^{4+3} = 2^7

After simplification, the expression becomes:
55×27 5^5 \times 2^7

Answer

55×27 5^5\times2^7

Exercise #15

Simplify the following equation:

42×35×43×32= 4^2\times3^5\times4^3\times3^2=

Video Solution

Step-by-Step Solution

To simplify the given expression 42×35×43×32 4^2 \times 3^5 \times 4^3 \times 3^2 , we will follow these steps:

  • Step 1: Identify and group similar bases.

  • Step 2: Apply the rule for multiplying like bases.

  • Step 3: Simplify the expression.

Now, let's go through each step thoroughly:

Step 1: Identify and group similar bases:
We see two distinct bases here: 4 and 3.

Step 2: Apply the rule for multiplying like bases:
For base 4: Combine 424^2 and 434^3, using the rule am×an=am+na^m \times a^n = a^{m+n}.

Add the exponents for base 4: 2+3=5 2 + 3 = 5 , thus, 42×43=45 4^2 \times 4^3 = 4^5 .

For base 3: Combine 353^5 and 323^2, still using the same exponent rule.

Add the exponents for base 3: 5+2=7 5 + 2 = 7 , resulting in 35×32=37 3^5 \times 3^2 = 3^7 .

Step 3: Simplify the expression:
The simplified expression is 45×37 4^5 \times 3^7 .

Therefore, the final simplified expression is 45×37 4^5 \times 3^7 .

Answer

45×37 4^5\times3^7