# Circumference - Examples, Exercises and Solutions

The circumference is actually the length of the circular line. It is calculated by multiplying the radius by 2, which has an approximate value of π. It can also be said that the circumference is equal to the the diameter of the circumference multiplied by π (since the diameter is actually twice the radius of the circumference). It is customary to identify the circumference (the perimeter) with the letter P.

## Practice Circumference

### Exercise #1

Look at the circle in the figure:

Its radius is equal to 4.

What is its circumference?

### Step-by-Step Solution

The formula for the circumference is equal to:

$2\pi r$

### Exercise #2

O is the center of the circle in the figure below.

What is its circumference?

### Step-by-Step Solution

We use the formula:$P=2\pi r$

We replace the data in the formula:$P=2\times8\pi$

$P=16\pi$

$16\pi$ cm

### Exercise #3

Look at the circle in the figure.

What is its circumference if its radius is equal to 6?

### Step-by-Step Solution

Formula of the circumference:

$P=2\pi r$

We replace the data in the formula:

$P=2\times6\times\pi$

$P=12\pi$

$12\pi$

### Exercise #4

A circle has a circumference of 31.41.

### Step-by-Step Solution

To solve the exercise, first we must remember the circumference formula:

$P= 2\pi R$

P is the circumference and Pi has a value of 3.14 (approximately).

We substitute in the known data:

$31.41=2\cdot3.141\cdot R$

Keep in mind that the result can be easily simplified using Pi:

$\frac{31.41}{3.141}=2R$

$10=2R$

Finally, we simplify by 2:

$5=R$

5

### Exercise #5

A circle has a circumference of 50.25.

### Step-by-Step Solution

We use the formula:

$P=2\pi r$

We replace the data in the formula:

$50.25=3.14\times2r$

$50.25=2\times r\times3.14$

$50.25=6.28r$

$\frac{50.25}{6.28}=\frac{6.28r}{6.28}$

$r=8$

8

### Exercise #1

The circumference of a circle is 14.

How long is the circle's radius?

### Step-by-Step Solution

We use in the formula:

$P=2\pi r$

We replace the data in the formula:

$14=2\times\pi\times r$

We divide Pi by 2:

$\frac{14}{2\pi}=\frac{2\pi r}{2\pi}$

$\frac{7}{\pi}=r$

$\frac{7}{\pi}$

### Exercise #2

Below is a circle bounded by a parallelogram:

All meeting points are tangential to the circle.
The circumference is 25.13.

What is the area of the parallelogram?

### Step-by-Step Solution

First, we add letters as reference points:

Let's observe points A and B.

We know that two tangent lines to a circle that start from the same point are parallel to each other.

Therefore:

$AE=AF=3$
$BG=BF=6$

And from here we can calculate:

$AB=AF+FB=3+6=9$

Now we need the height of the parallelogram.

We know that F is tangent to the circle, so the diameter that comes out of point F will also be the height of the parallelogram.

It is also known that the diameter is equal to two radii.

Since the circumference is 25.13.

Circumference formula:$2\pi R$
We replace and solve:

$2\pi R=25.13$
$\pi R=12.565$
$R\approx4$

The height of the parallelogram is equal to two radii, that is, 8.

And from here you can calculate with a parallelogram area formula:

$AlturaXLado$

$9\times8\approx72$

$\approx72$

### Exercise #3

The following is a circle enclosed in a parallelogram:

All meeting points are tangent to the circle.
The circumference is 25.13.

What is the area of the zones marked in blue?

### Step-by-Step Solution

First, we add letters as reference points:

Let's observe points A and B.

We know that two tangent lines to a circle that start from the same point are parallel to each other.

Therefore:

$AE=AF=3$
$BG=BF=6$

From here we can calculate:

$AB=AF+FB=3+6=9$

Now we need the height of the parallelogram.

We know that F is tangent to the circle, so the diameter that comes out of point F will also be the height of the parallelogram.

It is also known that the diameter is equal to two radii.

It is known that the circumference of the circle is 25.13.

Formula of the circumference:$2\pi R$
We replace and solve:

$2\pi R=25.13$
$\pi R=12.565$
$R\approx4$

The height of the parallelogram is equal to two radii, that is, 8.

And from here it is possible to calculate the area of the parallelogram:

$\text{Lado }x\text{ Altura}$$9\times8\approx72$

Now, we calculate the area of the circle according to the formula:$\pi R^2$

$\pi4^2=50.26$

Now, subtract the area of the circle from the surface of the trapezoid to get the answer:

$72-56.24\approx21.73$

$\approx21.73$

### Exercise #4

Given the circle whose radius has a length of 9 cm

What is its perimeter?

56.55

### Exercise #5

A circle has a diameter of 12.

What is its perimeter?

12π

### Exercise #1

A circle has a radius of 3 cm.

What is its perimeter?

### Video Solution

$6\pi$ cm

### Exercise #2

O is the center of the circle in the diagram.

What is its perimeter?

### Video Solution

$8\pi$ cm

### Exercise #3

O is the center of the circle.

AB = 15

Is it possible to work out its circumference?

### Video Solution

Yes, $15\pi$ cm

### Exercise #4

Look at the circle in the figure.

Is it possible to calculate its circumference?

### Video Solution

It is not possible to calculate.

### Exercise #5

Look at the circle in the figure.

Given that its radius is equal to 3, what is its circumference?

### Video Solution

$6\pi$