Area of Isosceles Trapezoid Practice Problems with Solutions

We use the formula (base+base) multiplied by the height and divided by 2.

Note that we are only provided with one base and it is not possible to determine the size of the other base.

Therefore, the area cannot be calculated.

To find the area of the trapezoid, we would ideally use the formula:

$A = \frac{1}{2} \times (b_1 + b_2) \times h$

where $b_1$ and $b_2$ are the lengths of the two parallel sides and $h$ is the height. However, the given information is incomplete for these purposes.

The numbers provided ($6$, $7$, $12$, and $5$) do not clearly designate which are the bases and what is the height. Without this information, the dimensions cannot be definitively identified, making it impossible to calculate the area accurately.

Thus, the problem, based on the given diagram and information, cannot be solved for the area of the trapezoid.

Therefore, the correct answer is: It cannot be calculated.

The formula for the area of a trapezoid is:

We are given the following dimensions:

• Base $AB = 5$ cm
• Base $DC = 9$ cm
• Height $h = 7$ cm

Substituting these values into the formula, we have:

First, add the lengths of the bases:

Now substitute back into the formula:

Calculate the multiplication:

Then multiply by the height:

Thus, the area of the trapezoid is 49 cm$^2$.

To solve this problem, we follow these steps:

• Step 1: Identify the given dimensions of the trapezoid.
• Step 2: Use the formula for the area of a trapezoid.
• Step 3: Substitute the given values into the formula and calculate the area.

Now, let's work through these steps:

Step 1: We know from the problem that trapezoid ABCD has bases $AB = 5$ and $CD = 8$, with a height of $AD = 4$.

Step 2: The formula for the area of a trapezoid is:
$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Step 3: Plugging in the values:
$A = \frac{1}{2} \times (5 + 8) \times 4 = \frac{1}{2} \times 13 \times 4 = \frac{52}{2} = 26$

Therefore, the area of the trapezoid ABCD is $26$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the lengths of the trapezoid's bases: $AB = 7$ and $CD = 9$.
• Step 2: Identify the height of the trapezoid: $AD = 5$.
• Step 3: Apply the trapezoid area formula: $A = \frac{1}{2} \times (b_1 + b_2) \times h$.
• Step 4: Calculate the area using the values from Steps 1 and 2.

Now, let us work through each step:
Step 1: The length of base $AB$ is $(b_1 = 7)$ units, and the length of base $CD$ is $(b_2 = 9)$ units.
Step 2: The height $AD$ is $(h = 5)$ units.

Step 3: Substitute the known values into the formula for the area of a trapezoid:
$A = \frac{1}{2} \times (7 + 9) \times 5$

Step 4: Calculate the results:
$A = \frac{1}{2} \times 16 \times 5 = \frac{1}{2} \times 80 = 40$

Therefore, the area of trapezoid ABCD is $\mathbf{40}$ square units.