Area of Isosceles Trapezoid Practice Problems with Solutions

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information relevant to the trapezoid.
• Step 2: Apply the appropriate formula for the area of a trapezoid.
• Step 3: Perform the necessary calculations to find the area.

Now, let's work through each step:
Step 1: The problem gives us two bases, $b_1 = 6$ cm and $b_2 = 12$ cm, and a height $h = 4$ cm.
Step 2: We'll use the formula for the area of a trapezoid: $A = \frac{1}{2} \cdot (b_1 + b_2) \cdot h$
Step 3: Substituting in the given values: $A = \frac{1}{2} \cdot (6 + 12) \cdot 4 = \frac{1}{2} \cdot 18 \cdot 4 = \frac{72}{2} = 36 \text{ cm}^2$

Therefore, the solution to the problem is $36$ cm².

To calculate the area of the trapezoid ABCD, we will follow these steps:

Given:

• Base $AB = 7$
• Base $CD = 11$
• Height $= 5$

Apply the trapezoid area formula:

The formula for the area of a trapezoid is:

Substitute the values into the formula:

Simplify the expression:

Calculate:

Finally, compute the area:

Thus, the area of trapezoid ABCD is $45$.

To solve this problem, we'll calculate the area of trapezoid ABCD using the appropriate formula.

The formula for the area $A$ of a trapezoid is given by:

$A = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$

Substituting the given values into the formula, we have:

$A = \frac{1}{2} \times (5 + 10) \times 4$

First, calculate the sum of the bases:

$5 + 10 = 15$

Multiply by the height, and then take half:

$A = \frac{1}{2} \times 15 \times 4 = \frac{1}{2} \times 60 = 30$

Therefore, the area of the trapezoid ABCD is 30 square units.

To solve this problem, we follow these steps:

• Step 1: Identify the given dimensions of the trapezoid.
• Step 2: Use the formula for the area of a trapezoid.
• Step 3: Substitute the given values into the formula and calculate the area.

Now, let's work through these steps:

Step 1: We know from the problem that trapezoid ABCD has bases $AB = 5$ and $CD = 8$, with a height of $AD = 4$.

Step 2: The formula for the area of a trapezoid is:
$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Step 3: Plugging in the values:
$A = \frac{1}{2} \times (5 + 8) \times 4 = \frac{1}{2} \times 13 \times 4 = \frac{52}{2} = 26$

Therefore, the area of the trapezoid ABCD is $26$.

To solve this problem, we'll follow these steps:

• Identify the given measurements: the lengths of the parallel sides (bases) and the height.
• Use the trapezoid area formula to calculate the area.
• Perform the necessary arithmetic to find the numerical answer.

Now, let's work through each step:
Step 1: The given measurements are $\text{Base}_1 = 9$, $\text{Base}_2 = 12$, and the height = 5.
Step 2: The formula for the area of a trapezoid is $\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$.
Step 3: Substituting the numbers into the formula, we have:
$\text{Area} = \frac{1}{2} \times (9 + 12) \times 5$

Calculating inside the parentheses first:
$9 + 12 = 21$

Then multiply by the height:
$21 \times 5 = 105$

Finally, multiply by one-half:
$\frac{1}{2} \times 105 = 52.5$

Therefore, the area of trapezoid $ABCD$ is $52.5$ .