Area of Isosceles Trapezoid Practice Problems with Solutions

To solve this problem, we follow these steps:

• Step 1: Identify the given dimensions of the trapezoid.
• Step 2: Use the formula for the area of a trapezoid.
• Step 3: Substitute the given values into the formula and calculate the area.

Now, let's work through these steps:

Step 1: We know from the problem that trapezoid ABCD has bases $AB = 5$ and $CD = 8$, with a height of $AD = 4$.

Step 2: The formula for the area of a trapezoid is:
$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Step 3: Plugging in the values:
$A = \frac{1}{2} \times (5 + 8) \times 4 = \frac{1}{2} \times 13 \times 4 = \frac{52}{2} = 26$

Therefore, the area of the trapezoid ABCD is $26$.

Formula for the area of a trapezoid:

$\frac{(base+base)}{2}\times altura$

We substitute the data into the formula and solve:

$\frac{9+12}{2}\times5=\frac{21}{2}\times5=\frac{105}{2}=52.5$

To solve this problem, we'll follow these steps:

• Step 1: Recall the formula for the area of a trapezoid.
• Step 2: Substitute the given values into the formula.
• Step 3: Calculate the area using arithmetic operations.

Let's work through each step:
Step 1: The formula for the area of a trapezoid is given by:
$\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$
Step 2: Plug in the values: $\text{Base}_1 = AB = 6$, $\text{Base}_2 = CD = 8$, and the height $AD = 3$.
$\text{Area} = \frac{1}{2} \times (6 + 8) \times 3$
Step 3: Perform the calculations:
$\text{Area} = \frac{1}{2} \times 14 \times 3 = \frac{1}{2} \times 42 = 21$

Therefore, the area of trapezoid $ABCD$ is $21$.

First, let's remind ourselves of the formula for the area of a trapezoid:

$A=\frac{\left(Base\text{ }+\text{ Base}\right)\text{ h}}{2}$

We substitute the given values into the formula:

(2.5+4)*6 =
6.5*6=
39/2 =
19.5

To solve this problem, we'll follow these steps:

• Step 1: Identify the lengths of the trapezoid's bases: $AB = 7$ and $CD = 9$.
• Step 2: Identify the height of the trapezoid: $AD = 5$.
• Step 3: Apply the trapezoid area formula: $A = \frac{1}{2} \times (b_1 + b_2) \times h$.
• Step 4: Calculate the area using the values from Steps 1 and 2.

Now, let us work through each step:
Step 1: The length of base $AB$ is $(b_1 = 7)$ units, and the length of base $CD$ is $(b_2 = 9)$ units.
Step 2: The height $AD$ is $(h = 5)$ units.

Step 3: Substitute the known values into the formula for the area of a trapezoid:
$A = \frac{1}{2} \times (7 + 9) \times 5$

Step 4: Calculate the results:
$A = \frac{1}{2} \times 16 \times 5 = \frac{1}{2} \times 80 = 40$

Therefore, the area of trapezoid ABCD is $\mathbf{40}$ square units.