Area of Isosceles Trapezoid Practice Problems with Solutions

First, let's remind ourselves of the formula for the area of a trapezoid:

$A=\frac{\left(Base\text{ }+\text{ Base}\right)\text{ h}}{2}$

We substitute the given values into the formula:

(2.5+4)*6 =
6.5*6=
39/2 =
19.5

First, we need to remind ourselves of how to work out the area of a trapezoid:

$\frac{(Base+Base)\cdot h}{2}=Area$

Now let's substitute the given data into the formula:

(10+6)*5 =
2

Let's start with the upper part of the equation:

16*5 = 80

80/2 = 40

Formula for the area of a trapezoid:

$\frac{(base+base)}{2}\times altura$

We substitute the data into the formula and solve:

$\frac{9+12}{2}\times5=\frac{21}{2}\times5=\frac{105}{2}=52.5$

The formula for the area of a trapezoid is:

We are given the following dimensions:

• Base $AB = 5$ cm
• Base $DC = 9$ cm
• Height $h = 7$ cm

Substituting these values into the formula, we have:

First, add the lengths of the bases:

Now substitute back into the formula:

Calculate the multiplication:

Then multiply by the height:

Thus, the area of the trapezoid is 49 cm$^2$.

To calculate the area of the trapezoid ABCD, we will follow these steps:

Given:

• Base $AB = 7$
• Base $CD = 11$
• Height $= 5$

Apply the trapezoid area formula:

The formula for the area of a trapezoid is:

Substitute the values into the formula:

Simplify the expression:

Calculate:

Finally, compute the area:

Thus, the area of trapezoid ABCD is $45$.