Solve for X: Trapezoid Area of 78 cm² with Sides (X+10) and (12X-10)

Trapezoid Area with Algebraic Side Lengths

The area of the trapezoid in the diagram is 78 cm².

Calculate X.

X+10X+10X+1012X-1012X-1012X-10666

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 We'll use the formula for calculating trapezoid area
00:07 (Sum of bases(AB+DC) multiplied by height(H))divided by 2
00:13 We'll substitute appropriate values according to the given data and solve for X
00:31 We'll group the numbers as one factor and X as another factor
00:42 We'll divide 6 by 2
00:53 We'll isolate X
01:04 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

The area of the trapezoid in the diagram is 78 cm².

Calculate X.

X+10X+10X+1012X-1012X-1012X-10666

2

Step-by-step solution

To solve this problem, we need to apply the area formula for a trapezoid:

  • The area A A of a trapezoid is given by A=12×(b1+b2)×h A = \frac{1}{2} \times (b_1 + b_2) \times h where b1 b_1 and b2 b_2 are the base lengths, and h h is the height.

The problem provides:

  • Area A=78 A = 78 cm²
  • Base 1, b1=X+10 b_1 = X + 10
  • Base 2, b2=12X10 b_2 = 12X - 10
  • Height h=6 h = 6 cm

Substitute these into the area formula:

78=12×((X+10)+(12X10))×6 78 = \frac{1}{2} \times ((X + 10) + (12X - 10)) \times 6

Simplify the expression:

78=12×(13X)×6 78 = \frac{1}{2} \times (13X) \times 6

Multiply through by 2 to clear the fraction:

156=13X×6 156 = 13X \times 6

Simplify further:

156=78X 156 = 78X

Solving for X X gives:

X=15678 X = \frac{156}{78}

X=2 X = 2

Therefore, the solution to the problem is X=2 X = 2 .

3

Final Answer

2 2

Key Points to Remember

Essential concepts to master this topic
  • Formula: Area = 12×(b1+b2)×h \frac{1}{2} \times (b_1 + b_2) \times h for trapezoids
  • Technique: Combine like terms: (X+10) + (12X-10) = 13X
  • Check: Substitute X=2: bases become 12 and 14, area = ½(26)(6) = 78 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to combine like terms in the bases
    Don't leave the bases as separate expressions (X+10) and (12X-10) when substituting = messy calculations! This makes the algebra much harder and leads to errors. Always combine like terms first: (X+10) + (12X-10) = 13X.

Practice Quiz

Test your knowledge with interactive questions

Given the following trapezoid:

AAABBBCCCDDD584

Calculate the area of the trapezoid ABCD.

FAQ

Everything you need to know about this question

Why do I add the two bases together in the formula?

+

The trapezoid area formula uses the average of the two parallel sides (bases). Adding them together, then multiplying by ½, gives you that average length times the height.

How do I know which sides are the bases?

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The bases are the parallel sides - in this diagram, they're the top side (X+10) and bottom side (12X-10). The height (6) is always perpendicular to these parallel sides.

What if I get a negative value for X?

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Check if negative X makes sense! If X = -3, then X+10 = 7, but 12X-10 = -46. Since side lengths can't be negative, X must be positive in geometry problems.

Can I use the rectangle area formula instead?

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No! A trapezoid has two different parallel sides, unlike a rectangle where opposite sides are equal. Always use A=12(b1+b2)h A = \frac{1}{2}(b_1 + b_2)h for trapezoids.

How do I handle the fractions when solving?

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Multiply both sides by 2 early to eliminate the fraction: 78×2=156 78 \times 2 = 156 . This makes the algebra simpler and reduces calculation errors.

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