Let's proceed to solve the linear equation 3(a+1)β3=0:
Step 1: Distribute the 3 in the expression 3(a+1).
We get:
3β
a+3β
1β3=0
This simplifies to:
3a+3β3=0
Step 2: Simplify the expression by combining like terms.
We simplify this to:
3a+0=0 or simply 3a=0
Step 3: Isolate a by dividing both sides by 3.
33aβ=30β
Thus,
a=0
Therefore, the solution to the problem is a=0.
The correct choice is the option corresponding to a=0.