Solving Equations Using All Methods - Examples, Exercises and Solutions

Question Types:
Simplifying and Combining Like Terms: Combining like termsSimplifying and Combining Like Terms: Equations with variables on both sidesSimplifying and Combining Like Terms: Exercises with fractionsSimplifying and Combining Like Terms: One sided equationsSimplifying and Combining Like Terms: Opening parenthesesSimplifying and Combining Like Terms: Solving an equation using all techniquesSimplifying and Combining Like Terms: Solving an equation with fractionsSimplifying and Combining Like Terms: Using additional geometric shapesSimplifying and Combining Like Terms: Worded problemsSolving an Equation by Multiplication/ Division: Addition, subtraction, multiplication and divisionSolving an Equation by Multiplication/ Division: Combining like termsSolving an Equation by Multiplication/ Division: Decimal numbersSolving an Equation by Multiplication/ Division: Equations with variables on both sidesSolving an Equation by Multiplication/ Division: Exercises on Both Sides (of the Equation)Solving an Equation by Multiplication/ Division: Number of termsSolving an Equation by Multiplication/ Division: One sided equationsSolving an Equation by Multiplication/ Division: Rearranging EquationsSolving an Equation by Multiplication/ Division: Solving an equation using all techniquesSolving an Equation by Multiplication/ Division: Solving an equation with fractionsSolving an Equation by Multiplication/ Division: BinomialSolving an Equation by Multiplication/ Division: Using additional geometric shapesSolving an Equation by Multiplication/ Division: Using fractionsSolving an Equation by Multiplication/ Division: Worded problemsSolving Equations by using Addition/ Subtraction: Complete the missing numberSolving Equations by using Addition/ Subtraction: Equations with variables on both sidesSolving Equations by using Addition/ Subtraction: Exercises on Both Sides (of the Equation)Solving Equations by using Addition/ Subtraction: More than Two TermsSolving Equations by using Addition/ Subtraction: One sided equationsSolving Equations by using Addition/ Subtraction: MonomialSolving Equations by using Addition/ Subtraction: Solving an equation by multiplying/dividing both sidesSolving Equations by using Addition/ Subtraction: Solving an equation using all techniquesSolving Equations by using Addition/ Subtraction: Solving an equation with fractionsSolving Equations by using Addition/ Subtraction: Simplifying expressionsSolving Equations by using Addition/ Subtraction: Test if the coefficient is different from 1Solving Equations by using Addition/ Subtraction: BinomialSolving Equations by using Addition/ Subtraction: Using variablesSolving Equations by using Addition/ Subtraction: Worded problemsSolving Equations Using All Methods: Addition, subtraction, multiplication and divisionSolving Equations Using All Methods: Combining like termsSolving Equations Using All Methods: Decimal numbersSolving Equations Using All Methods: Domain of definitionSolving Equations Using All Methods: Equations with variables on both sidesSolving Equations Using All Methods: Exercises with fractionsSolving Equations Using All Methods: Number of termsSolving Equations Using All Methods: One sided equationsSolving Equations Using All Methods: Opening parenthesesSolving Equations Using All Methods: Rearranging EquationsSolving Equations Using All Methods: MonomialSolving Equations Using All Methods: BinomialSolving Equations Using All Methods: Using additional geometric shapesSolving Equations Using All Methods: Using fractionsSolving Equations Using All Methods: Worded problemsSolving Quadratic Equations using Factoring: Equations with variables on both sidesSolving Quadratic Equations using Factoring: One sided equationsSolving Quadratic Equations using Factoring: Solving an equation using all techniquesSolving Quadratic Equations using Factoring: Solving an equation with fractionsSolving Quadratic Equations using Factoring: Solving the problemSolving Quadratic Equations using Factoring: Worded problems

First-degree equation in one variable – solving by all methods

2x6=342x-6=34Variable

A first-degree equation is an equation where the highest power is 11 and there is only one variable 11.

Solving an Equation by Adding/Subtracting from Both Sides If the number is next to XX with a plus, we need to subtract it from both sides.
If the number is next to XX with a minus, we need to add it to both sides.

Solving an Equation by Multiplying/Dividing Both Sides We will need to multiply or divide both sides of the equations where there is a coefficient for XX.

Solving an Equation by Combining Like Terms Move all the XXs to the right side and all the numbers to the left side.

Solving an equation using the distributive property We will solve according to the distributive property
a(b+c)=ab+bca(b+c)=ab+bc

Suggested Topics to Practice in Advance

  1. Solving Equations by Adding or Subtracting the Same Number from Both Sides
  2. Solving Equations by Multiplying or Dividing Both Sides by the Same Number
  3. Solving Equations by Simplifying Like Terms
  4. Solving Equations Using the Distributive Property

Practice Solving Equations Using All Methods

Examples with solutions for Solving Equations Using All Methods

Exercise #1

Solve for b b :

8b=6 8-b=6

Video Solution

Step-by-Step Solution

First we will move terms so that -b remains remains on the left side of the equation.

We'll move 8 to the right-hand side, making sure to retain the plus and minus signs accordingly:

b=68 -b=6-8

Then we will subtract as follows:

b=2 -b=-2

Finally, we will divide both sides by -1 (be careful with the plus and minus signs when dividing by a negative):

b1=21 \frac{-b}{-1}=\frac{-2}{-1}

b=2 b=2

Answer

2 2

Exercise #2

7x+4x+5x=0 7x+4x+5x=0

x=? x=\text{?}

Video Solution

Step-by-Step Solution

Let's combine all the x terms together:

7x+4x+5x=11x+5x=16x 7x+4x+5x=11x+5x=16x

The resulting equation is:

16x=0 16x=0

Now let's divide both sides by 16:

16x16=016 \frac{16x}{16}=\frac{0}{16}

x=016=0 x=\frac{0}{16}=0

Answer

0 0

Exercise #3

Determine the value of x x :

2(x+4)+8=0 2(x+4)+8=0

Video Solution

Step-by-Step Solution

Let's first expand the parentheses using the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

(2×x)+(2×4)+8=0 (2\times x)+(2\times4)+8=0

2x+8+8=0 2x+8+8=0

Next, we will substitute in our terms accordingly:

2x+16=0 2x+16=0

Then, we will move the 16 to the left-hand side, keeping the appropriate sign:

2x=16 2x=-16

Finally, we divide both sides by 2:

2x2=162 \frac{2x}{2}=-\frac{16}{2}

x=8 x=-8

Answer

x=8 x=-8

Exercise #4

3(a+1)3=0 3(a+1)-3=0

Video Solution

Step-by-Step Solution

Let's proceed to solve the linear equation 3(a+1)3=0 3(a+1) - 3 = 0 :

Step 1: Distribute the 3 in the expression 3(a+1) 3(a+1) .

We get:
3a+313=0 3 \cdot a + 3 \cdot 1 - 3 = 0

This simplifies to:
3a+33=0 3a + 3 - 3 = 0

Step 2: Simplify the expression by combining like terms.

We simplify this to:
3a+0=0 3a + 0 = 0 or simply 3a=0 3a = 0

Step 3: Isolate a a by dividing both sides by 3.

3a3=03\frac{3a}{3} = \frac{0}{3}

Thus,
a=0 a = 0

Therefore, the solution to the problem is a=0 a = 0 .

The correct choice is the option corresponding to a=0 a = 0 .

Answer

a=0 a=0

Exercise #5

16+a=17 -16+a=-17

Video Solution

Step-by-Step Solution

Let's solve the equation 16+a=17 -16 + a = -17 by isolating the variable a a .

To isolate a a , add 16 to both sides of the equation to cancel out the 16 -16 :

16+a+16=17+16 -16 + a + 16 = -17 + 16

This simplification results in:

a=1 a = -1

Thus, the solution to the equation 16+a=17 -16 + a = -17 is a=1 a = -1 .

If we review the answer choices given, the correct answer is Choice 4, 1 -1 .

The solution to the problem is a=1 a = -1 .

Answer

1 -1

Exercise #6

Solve for X:

5x=38 5x=\frac{3}{8}

Video Solution

Step-by-Step Solution

ax=cb ax=\frac{c}{b}

x=cba x=\frac{c}{b\cdot a}

Answer

340 \frac{3}{40}

Exercise #7

Solve for X:

x+9=15 x + 9 = 15

Video Solution

Step-by-Step Solution

Step-by-step solution:

1. Begin with the equation: x+9=15 x + 9 = 15

2. Subtract 9 from both sides: x+99=159 x + 9 - 9 = 15 - 9 , which simplifies to x=6 x = 6

Answer

6

Exercise #8

4=3y 4=3y

Video Solution

Step-by-Step Solution

The goal is to solve the equation 4=3y 4 = 3y to find the value of y y . To do this, we can follow these steps:

  • Step 1: Divide both sides of the equation by 3 to isolate y y .
  • Step 2: Simplify the result to solve for y y .

Now, let's work through the solution:

Step 1: We start with the equation:

4=3y 4 = 3y

To solve for y y , divide both sides by 3:

y=43 y = \frac{4}{3}

Step 2: Simplify the fraction:

y=43=113 y = \frac{4}{3} = 1 \frac{1}{3}

Therefore, the solution to the equation is y=113 y = 1 \frac{1}{3} .

This corresponds to choice y=113 y = 1\frac{1}{3} in the provided multiple-choice answers.

Answer

y=113 y=1\frac{1}{3}

Exercise #9

11=a16 11=a-16

a=? a=\text{?}

Video Solution

Step-by-Step Solution

To find the value of aa, we must solve the given linear equation:

11=a1611 = a - 16

We aim to isolate aa by performing operations that maintain the balance of the equation. Currently, aa is being decreased by 16. To reverse this, we need to add 16 to both sides.

Step-by-step:

  • Start with the given equation: 11=a1611 = a - 16.
  • Add 16 to both sides to start isolating aa:

11+16=a16+1611 + 16 = a - 16 + 16

  • This simplifies to:

27=a27 = a

Thus, the value of aa is 27.

Therefore, the solution to the equation 11=a1611 = a - 16 is a=27a = 27.

Answer

27 27

Exercise #10

Solve for x:

7(2x+5)=77 7(-2x+5)=77

Video Solution

Step-by-Step Solution

To open parentheses we will use the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

(7×2x)+(7×5)=77 (7\times-2x)+(7\times5)=77

We multiply accordingly

14x+35=77 -14x+35=77

We will move the 35 to the right section and change the sign accordingly:

14x=7735 -14x=77-35

We solve the subtraction exercise on the right side and we will obtain:

14x=42 -14x=42

We divide both sections by -14

14x14=4214 \frac{-14x}{-14}=\frac{42}{-14}

x=3 x=-3

Answer

-3

Exercise #11

Solve for A:

a5=10 a-5=10

Step-by-Step Solution

To solve for a a , we need to isolate it on one side of the equation. Starting with:

a5=10 a-5=10

Add 5 5 to both sides to get:

a5+5=10+5 a-5+5=10+5

This simplifies to:

a=15 a=15

Therefore, the solution isa=15 a = 15 .

Answer

15 15

Exercise #12

Solve for B:

b+6=14 b+6=14

Step-by-Step Solution

To solve for b b , we need to isolate it on one side of the equation. Starting with:

b+6=14 b+6=14

Subtract6 6 from both sides to get:

b+66=146 b+6-6=14-6

This simplifies to:

b=8 b=8

Therefore, the solution is b=8 b = 8 .

Answer

8 8

Exercise #13

Solve for X:

6x=72 6x=72

Video Solution

Step-by-Step Solution

To solve for xx in the equation 6x=726x = 72, follow these steps:

Step 1: Identify the equation and the coefficient of xx.
The given equation is 6x=726x = 72, where the coefficient of xx is 6.

Step 2: Isolate xx by dividing both sides of the equation by the coefficient (6).
Perform the division: x=726x = \frac{72}{6}.

Step 3: Simplify the result.
Calculating 726\frac{72}{6}, we get x=12x = 12.

Therefore, the solution to the equation is x=12x = 12.

Answer

12

Exercise #14

Solve for X:

x+3=7 x + 3 = 7

Video Solution

Step-by-Step Solution

To solve for x x , start by isolating x x on one side of the equation:
Subtract 3 from both sides:
x+33=73 x + 3 - 3 = 7 - 3 simplifies to
x=4 x = 4 .

Answer

4

Exercise #15

Solve for X:

x+7=12 x + 7 = 12

Video Solution

Step-by-Step Solution

To solve for x x , start by isolating x x on one side of the equation:
Subtract 7 from both sides:
x+77=127 x + 7 - 7 = 12 - 7 simplifies to
x=5 x = 5 .

Answer

5

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