Solving First-Degree Equations Practice Problems - All Methods

Master solving linear equations using addition, subtraction, multiplication, division, combining like terms, and distributive property with step-by-step practice problems.

πŸ“šPractice Solving Equations Using Every Method You Need to Know
  • Solve equations by adding or subtracting the same number from both sides
  • Master multiplying and dividing both sides to eliminate coefficients and fractions
  • Combine like terms by moving variables to one side and constants to the other
  • Apply the distributive property to eliminate parentheses in linear equations
  • Work with equations containing variables on both sides of the equal sign
  • Build confidence solving first-degree equations with one variable step-by-step

Understanding Solving Equations Using All Methods

Complete explanation with examples

First-degree equation in one variable – solving by all methods

2xβˆ’6=342x-6=34Variable

A first-degree equation is an equation where the highest power is 11 and there is only one variable 11.

Solving an Equation by Adding/Subtracting from Both Sides If the number is next to XX with a plus, we need to subtract it from both sides.
If the number is next to XX with a minus, we need to add it to both sides.

Solving an Equation by Multiplying/Dividing Both Sides We will need to multiply or divide both sides of the equations where there is a coefficient for XX.

Solving an Equation by Combining Like Terms Move all the XXs to the right side and all the numbers to the left side.

Solving an equation using the distributive property We will solve according to the distributive property
a(b+c)=ab+bca(b+c)=ab+bc

Detailed explanation

Practice Solving Equations Using All Methods

Test your knowledge with 151 quizzes

Solve for Z:

\( z+2=8 \)

Examples with solutions for Solving Equations Using All Methods

Step-by-step solutions included
Exercise #1

Solve for b b :

8βˆ’b=6 8-b=6

Step-by-Step Solution

First we will move terms so that -b remains remains on the left side of the equation.

We'll move 8 to the right-hand side, making sure to retain the plus and minus signs accordingly:

βˆ’b=6βˆ’8 -b=6-8

Then we will subtract as follows:

βˆ’b=βˆ’2 -b=-2

Finally, we will divide both sides by -1 (be careful with the plus and minus signs when dividing by a negative):

βˆ’bβˆ’1=βˆ’2βˆ’1 \frac{-b}{-1}=\frac{-2}{-1}

b=2 b=2

Answer:

2 2

Video Solution
Exercise #2

βˆ’16+a=βˆ’17 -16+a=-17

Step-by-Step Solution

Let's solve the equation βˆ’16+a=βˆ’17 -16 + a = -17 by isolating the variable a a .

To isolate a a , add 16 to both sides of the equation to cancel out the βˆ’16 -16 :

βˆ’16+a+16=βˆ’17+16 -16 + a + 16 = -17 + 16

This simplification results in:

a=βˆ’1 a = -1

Thus, the solution to the equation βˆ’16+a=βˆ’17 -16 + a = -17 is a=βˆ’1 a = -1 .

If we review the answer choices given, the correct answer is Choice 4, βˆ’1 -1 .

The solution to the problem is a=βˆ’1 a = -1 .

Answer:

βˆ’1 -1

Video Solution
Exercise #3

Solve for X:

x+9=15 x + 9 = 15

Step-by-Step Solution

Step-by-step solution:

1. Begin with the equation: x+9=15 x + 9 = 15

2. Subtract 9 from both sides: x+9βˆ’9=15βˆ’9 x + 9 - 9 = 15 - 9 , which simplifies to x=6 x = 6

Answer:

6

Video Solution
Exercise #4

4=3y 4=3y

Step-by-Step Solution

The goal is to solve the equation 4=3y 4 = 3y to find the value of y y . To do this, we can follow these steps:

  • Step 1: Divide both sides of the equation by 3 to isolate y y .
  • Step 2: Simplify the result to solve for y y .

Now, let's work through the solution:

Step 1: We start with the equation:

4=3y 4 = 3y

To solve for y y , divide both sides by 3:

y=43 y = \frac{4}{3}

Step 2: Simplify the fraction:

y=43=113 y = \frac{4}{3} = 1 \frac{1}{3}

Therefore, the solution to the equation is y=113 y = 1 \frac{1}{3} .

This corresponds to choice y=113 y = 1\frac{1}{3} in the provided multiple-choice answers.

Answer:

y=113 y=1\frac{1}{3}

Video Solution
Exercise #5

11=aβˆ’16 11=a-16

a=? a=\text{?}

Step-by-Step Solution

To find the value of aa, we must solve the given linear equation:

11=aβˆ’1611 = a - 16

We aim to isolate aa by performing operations that maintain the balance of the equation. Currently, aa is being decreased by 16. To reverse this, we need to add 16 to both sides.

Step-by-step:

  • Start with the given equation: 11=aβˆ’1611 = a - 16.
  • Add 16 to both sides to start isolating aa:

11+16=aβˆ’16+1611 + 16 = a - 16 + 16

  • This simplifies to:

27=a27 = a

Thus, the value of aa is 27.

Therefore, the solution to the equation 11=aβˆ’1611 = a - 16 is a=27a = 27.

Answer:

27 27

Video Solution

Frequently Asked Questions

What is a first-degree equation with one variable?

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A first-degree equation with one variable is an equation where the highest power of the variable is 1 and contains only one variable (usually x). Examples include 3x + 5 = 20 or 4(x + 2) - 2x = 12. The goal is to find the value of x that makes the equation true.

When do I add or subtract from both sides of an equation?

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Add or subtract from both sides to isolate the variable. If a number is added to x (like x + 7), subtract that number from both sides. If a number is subtracted from x (like x - 4), add that number to both sides. This keeps the equation balanced while moving terms.

How do I solve equations with coefficients or fractions?

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For coefficients (like 2x = 12), divide both sides by the coefficient to isolate x. For fractions (like x/4 = 5), multiply both sides by the denominator to eliminate the fraction. Always perform the same operation on both sides to maintain equality.

What does combining like terms mean in equations?

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Combining like terms means moving all variable terms to one side and all constant numbers to the other side. For example, in 5x - 3 = 2x + 9, move the x terms to get 5x - 2x = 9 + 3, then simplify to 3x = 12.

When do I use the distributive property in equations?

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Use the distributive property when you see parentheses in an equation, like 2(x + 3) = 14. Apply a(b + c) = ab + ac to get 2x + 6 = 14, then solve normally. This eliminates parentheses and simplifies the equation.

What are the steps to solve any first-degree equation?

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Follow these steps in order: 1) Use distributive property to eliminate parentheses, 2) Combine like terms on each side, 3) Move all variable terms to one side and constants to the other, 4) Divide both sides by the coefficient of the variable. Always check your answer by substituting back into the original equation.

How do I check if my solution to an equation is correct?

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Substitute your answer back into the original equation and verify both sides are equal. For example, if you solved 2x - 6 = 34 and got x = 20, check: 2(20) - 6 = 40 - 6 = 34 βœ“. If both sides equal the same number, your solution is correct.

What's the difference between solving 2x = 8 and x/2 = 4?

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For 2x = 8, divide both sides by 2 to get x = 4. For x/2 = 4, multiply both sides by 2 to get x = 8. When the variable is multiplied by a number, divide by that number. When the variable is divided by a number, multiply by that number.

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