Solving First-Degree Equations Practice Problems - All Methods

Let's first expand the parentheses using the formula:

$a(x+b)=ax+ab$

$(2\times x)+(2\times4)+8=0$

$2x+8+8=0$

Next, we will substitute in our terms accordingly:

$2x+16=0$

Then, we will move the 16 to the left-hand side, keeping the appropriate sign:

$2x=-16$

Finally, we divide both sides by 2:

$\frac{2x}{2}=-\frac{16}{2}$

$x=-8$

To solve the given linear equation $-8 - x = 5$, we will follow these steps:

• Add 8 to both sides of the equation to isolate the term involving $x$.
• Subtract $x$ from both sides to further simplify; however, applying approach 1 directly cancels this step.
• Multiply both sides by -1 to solve for $x$.

First, let's add 8 to both sides of the equation:

This simplifies to:

To find $x$, multiply both sides of the equation by -1:

Therefore, the solution to the equation is $x = -13$.

To solve the equation $x + 5 = 8$, follow these steps:

• Step 1: Start with the original equation:
  $x + 5 = 8$.
• Step 2: Subtract 5 from both sides of the equation to isolate $x$:
  $x + 5 - 5 = 8 - 5$.
• Step 3: Simplify both sides:
  $x = 3$.

Therefore, the solution to the equation is $x = 3$.

The correct answer choice is: :

3

To solve for $a$, we need to isolate it on one side of the equation. Starting with:

$a-5=10$

Add $5$ to both sides to get:

$a-5+5=10+5$

This simplifies to:

$a=15$

Therefore, the solution is$a = 15$.

To solve for $b$, we need to isolate it on one side of the equation. Starting with:

$b+6=14$

Subtract$6$ from both sides to get:

$b+6-6=14-6$

This simplifies to:

$b=8$

Therefore, the solution is $b = 8$.