Linear Equations - Examples, Exercises and Solutions

We start by moving the sections:

5X-15 = 30
5X = 30+15

5X = 45

Now we divide by 5

X = 9

To solve the exercise, we first rewrite the entire division as a fraction:

$\frac{20}{4x}=5$

Actually, we didn't have to do this step, but it's more convenient for the rest of the process.

To get rid of the fraction, we multiply both sides of the equation by the denominator, 4X.

20=5*4X

20=20X

Now we can reduce both sides of the equation by 20 and we will arrive at the result of:

X=1

To solve the equation $6 - x = 10 - 2$, follow these steps:

1. First, simplify both sides of the equation:

2. On the right side, calculate $10 - 2 = 8$.

3. The equation simplifies to $6 - x = 8$.

4. To isolate x, subtract 6 from both sides:

5. $6 - x - 6 = 8 - 6$

6. This simplifies to $-x = 2$.

7. Multiply both sides by -1 to solve for x:

8. $x = -2 \times -1 = 2$.

9. Since the problem requires only manipulation by transferring terms, the initial approach to the equation setup should lead to x = 4 as the solution before re-evaluation.

Therefore, the correct solution to the equation is $x=2$.

First, simplify the right side of the equation:
$12 - 4 = 8$
Hence, the equation becomes $5 - x = 8$.
Subtract 5 from both sides to isolate $x$:
$5 - x - 5 = 8 - 5$
This simplifies to:
$-x=3$
Divide by -1 to solve for $x$:
$x=-3$
Therefore, the solution is $x=-3$.

First, simplify the right side of the equation:
$15 - 5 = 10$
Hence, the equation becomes $7 - x = 10$.
Subtract 7 from both sides to isolate $x$:
$7 - x - 7 = 10 - 7$
This simplifies to:
$-x=3$
Divide by -1 to solve for$x$:
$x=-3$
Therefore, the solution is $x=-3$.

First, simplify the right side of the equation:
$16 - 7 = 9$
Hence, the equation becomes $9 - x = 9$.
Since both sides are equal, $x$ must be $0$.
Therefore, the solution is $x = 0$.

First, simplify the right side of the equation:
$10 - 6 = 4$
Hence, the equation becomes $3 - x = 4$.
Subtract 3 from both sides to isolate $x$:
$3 - x - 3 = 4 - 3$
This simplifies to:
$-x=1$
Divide by -1 to solve for$x$:
$x=-1$
Therefore, the solution is $x = 1$.

First, simplify both sides of the equation:

Left side: $3 + x - 2 = 1 + x$

Right side: $7 - 3 = 4$

So the equation becomes:

$1 + x = 4$

Next, isolate $x$ by subtracting 1 from both sides:

$1 + x - 1 = 4 - 1$

This simplifies to:

$x = 3$

To solve $5 + x - 3 = 2 + 1$, we first simplify both sides:

Left side:
$5 - 3 + x = 2 + x$$$

Right side:
$2 + 1 = 3$

Now the equation is $2 + x = 3$.

Subtract 2 from both sides:
$x = 3 - 2$

So, $x = 1$.

To solve $3 + x + 1 = 6 - 2$, we first simplify both sides:

Left side:
$3 + 1 + x = 4 + x$

Right side:
$6 - 2 = 4$

Now the equation is $4 + x = 4$.

Subtract 4 from both sides:
$x = 4 - 4$

So, $x = 0$.

First, simplify both sides of the equation:

Left side: $x + 4 - 2 = x + 2$

Right side: $6 + 1 = 7$

Now the equation is: $x + 2 = 7$

Subtract 2 from both sides to isolate$x$:

$x + 2 - 2 = 7 - 2$

Simplifying gives:

$x = 5$

First, simplify both sides of the equation:

Left side: $x - 3 + 5 = x + 2$

Right side: $8 - 2 = 6$

Now the equation is: $x + 2 = 6$

Subtract 2 from both sides to isolate $x$:

$x + 2 - 2 = 6 - 2$

Simplifying gives:

$x = 4$

First, we will arrange the equation so that we have variables on one side and numbers on the other side.

Therefore, we will move $\frac{5}{6}$ to the other side, and we will get

$\frac{1}{3}x=-\frac{1}{6}-\frac{5}{6}$

Note that the two fractions on the right side share the same denominator, so you can subtract them:

 $\frac{1}{3}x=-\frac{6}{6}$

Observe the minus sign on the right side!

$\frac{1}{3}x=-1$

Now, we will try to get rid of the denominator, we will do this by multiplying the entire exercise by the denominator (that is, all terms on both sides of the equation):

$1x=-3$

 $x=-3$

To solve the equation $7x - 3 = 4x + 9$, follow these steps:

1. Subtract $4x$ from both sides to get:

$7x - 4x - 3 = 9$

2. Simplify the equation:

$3x - 3 = 9$

3. Add $3$ to both sides:

$3x = 12$

4. Divide both sides by $3$:

$x=4$

We have an equation with a variable.

Usually, in these equations, we will be asked to find the value of the missing (X),

This is how we solve it:

To solve the exercise, first we have to change the mixed fractions to an improper fraction,

So that it will then be easier for us to solve them.

Let's start with the four and the third:

To convert a mixed fraction, we start by multiplying the whole number by the denominator

4*3=12

Now we add this to the existing numerator.

12+1=13

And we find that the first fraction is 13/3

Let's continue with the second fraction and do the same in it:
21*3=63

63+2=65

The second fraction is 65/3

We replace the new fractions we found in the equation:

 13/3x = 65/3

At this point, we will notice that all the fractions in the exercise share the same denominator, 3.

Therefore, we can multiply the entire equation by 3.

13x=65

Now we want to isolate the unknown, the x.

Therefore, we divide both sides of the equation by the unknown coefficient -
13.

63:13=5

x=5