Conditions for the similarity between two triangles

To demonstrate the similarity between triangles it is not necessary to show again and again the relationship between the three pairs of sides and the equivalence between all the corresponding angles. This would require too much unnecessary work.

There are three criteria by which we can see the similarity betweentriangles:

Angle - Angle (AA): two triangles are similar if they have two equal angles.

Side - Angle - Side (SAS): Two triangles are similar if the ratio between two pairs of sides and also the angle they form are equal.

Side - Side - Side (SSS): Two triangles are similar if the ratio between all their sides (similarity ratio) is equal in both triangles.

The proof is immediate. We will rely on the criterion we have just learned. Let's note that we have been given two respectively equal angles in the two triangles. We will write it down as follows:

$∢A=∢D$ (angle) $∢B=∢E$ (angle).

It follows that: $Δ ABC$ ~ $Δ DEF$ (According to the similarity criterion Angle - Angle).

We observe that, if in two triangles there is equivalence between two pairs of corresponding angles, there must be equivalence between the third pair, since the sum of the internal angles of a triangle is always$180°$. This is the explanation of the first criterion of similarity: Angle - Angle.

Similarity criterion 2 - Side, Angle, Side (SAS)

Definition: Side - Angle - Side (SAS): Two triangles are similar if the ratio between two pairs of sides and also the angle they form are equal.

Do you know what the answer is?

Question 1

Look at the two triangles below:

Angle B is equal to angle E. Angle A is equal to angle D.

We also know that: $BC = 4$ $CA = 6$ $EF = 2$ $FD = 3$ $∢F=∢C$

Prove that the triangles are similar and calculate the similarity ratio.

Demonstration: We will rely on the second criterion of similarity that we just learned: Side - Angle - Side.

Let's pay attention to the relationship between the length of the sides: $\frac{FD}{CA}=\frac{3}{6}=\frac{1}{2}$

$\frac{EF}{BC}=\frac{2}{4}=\frac{1}{2}$

That is, we see that the ratio between two pairs of sides is equal. Also the datum $∢F=∢C$

That is, the angles formed between the two pairs of sides are equal. From the above we can deduce that

$Δ ABC$ ~ $Δ DEF$ (According to the similarity criterion Side - Angle - Side).

The similarity ratio is $1:2$

Similarity criterion 3 - Side, Side, Side (SSS)

Side - Side - Side (SSS): Two triangles are similar if the proportion between all their sides (similarity ratio) is equal in both triangles. Given the two triangles: $Δ ABC$ $Δ DEF$