Abbreviated Multiplication Formulas Practice Problems

Master algebraic identities with step-by-step practice problems. Learn square of sum, difference of squares, and cubic formulas through interactive exercises.

📚Master Abbreviated Multiplication Formulas with Targeted Practice
  • Apply (a+b)² = a² + 2ab + b² formula to expand binomial squares
  • Use (a-b)² = a² - 2ab + b² to solve difference of squares problems
  • Master (a+b)(a-b) = a² - b² for sum-difference multiplication
  • Expand cubic expressions using (a+b)³ and (a-b)³ formulas
  • Factor algebraic expressions back into abbreviated forms
  • Solve real-world problems involving quadratic and cubic identities

Understanding Short Multiplication Formulas

Complete explanation with examples

What are Abbreviated Multiplication Formulas?

Abbreviated multiplication formulas, also known as algebraic identities, are shortcuts that simplify the process of expanding and factoring expressions. These formulas save time and reduce the steps required for complex calculations. Abbreviated multiplication formulas will be used throughout our math studies, from elementary school to high school. In many cases, we will need to know how to expand or add these equations to arrive at the solution to various math exercises.

Abbreviated Multiplication Formulas for 2nd degree

Here are the basic formulas for abbreviated multiplication:

The square of the sum:
(X+Y)2=X2+2XY+Y2(X + Y)^2=X^2+ 2XY + Y^2

The squared difference:

(XY)2=X22XY+Y2(X - Y)^2=X^2 - 2XY + Y^2

The difference of squares:

(X+Y)×(XY)=X2Y2(X + Y)\times (X - Y) = X^2 - Y^2

Visual breakdown of abbreviated multiplication formulas: (a+b)² = a² + 2ab + b² and (a−b)² = a² − 2ab + b², with color-coded area models representing the expansion of binomials


Abbreviated Multiplication Formulas for 3rd degree

Abbreviated multiplication formulas for 3rd-degree expressions, also known as cubic identities, build upon the concepts of the 2nd-degree formulas we’ve already covered. The key difference is the adjustment for working with cubic (3rd-degree) terms instead of quadratic (2nd-degree) terms. These formulas simplify complex cubic expressions, breaking them into manageable parts to make calculations faster and more efficient. They are particularly useful in solving problems involving volumes of cubes and other 3D shapes or in advanced mathematics, such as polynomial factoring and equation solving.

Here are two of the most common abbreviated multiplication formulas for 3rd-degree expressions:

Cube of a Sum

(a+b)3=a3+3a2b+3ab2+b3(a+b)^3=a^3+3a^2 b+3ab^2+b^3

Cube of a Difference

​​​​​​​(ab)3=a33a2b+3ab2b3​​​​​​​(a-b)^3=a^3-3a^2 b+3ab^2-b^3


Abbreviated Multiplication Formulas Verification and Examples

We will test the shortcut multiplication formulas by expanding the parentheses.

Square of a Sum:

(X+Y)2=(X+Y)×(X+Y)=(X + Y)^2 = (X + Y)\times (X+Y) =

X2+XY+YX+Y2=X^2 + XY + YX + Y^2=

Since: XY=YXXY = YX

X2+2XY+Y2X^2 + 2XY + Y^2

Example:

(x+3)2 (x+3)^2

(x+3)2=x2+2(x)(3)+32=x2+6x+9 (x+3)^2=x^2+2(x)(3)+3^2=x^2+6x+9


Square of a Difference:

(XY)2=(XY)×(XY)=(X - Y)^2 = (X - Y)\times (X-Y) =

X2XYYX+Y2=X^2 - XY - YX + Y^2=

Since:XY=YX XY = YX

X22XY+Y2X^2 - 2XY + Y^2

Example:

(x4)2 (x−4)^2

(x4)2=x22(x)(4)+42=x28x+16 (x−4)^2=x^2−2(x)(4)+4^2=x^2−8x+16


Product of a Sum and a Difference:

(X+Y)×(XY)=(X + Y)\times (X-Y) =

X2XY+YXY2=X^2 - XY + YX - Y^2=

Since: XY=YX XY = YX

XY+YX=0 - XY + YX = 0

X2Y2X^2 - Y^2

Example:

(x+5)(x5) (x+5)(x−5)

(x+5)(x5)=x252=x225 (x+5)(x−5)=x^2−5^2=x^2−25


Using Abbreviated Multiplication Formulas to Shift the Expression Both Ways

It’s important to remember that these formulas are not one-sided; you can use them to switch between different forms of an expression as needed. For example, you can use the formula:

(X+Y)2=X2+2XY+Y2(X + Y)^2=X^2+ 2XY + Y^2

to expand an expression in parentheses into its expanded form. Conversely, if you encounter an expression like

X2+2XY+Y2X^2+ 2XY + Y^2

you can factor it back into

(X+Y)2(X + Y)^2

This flexibility allows you to work with the representation that is most useful for the problem at hand, whether it’s simplifying, solving, or analyzing the expression. Understanding this two-way functionality is essential for mastering algebraic manipulation.

Detailed explanation

Practice Short Multiplication Formulas

Test your knowledge with 48 quizzes

\( (x^2+4)^2= \)

Examples with solutions for Short Multiplication Formulas

Step-by-step solutions included
Exercise #1

Choose the expression that has the same value as the following:

(x+y)2 (x+y)^2

Step-by-Step Solution

To solve this problem, we will use the formula for the square of a sum, which is (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2.

Here, we identify a=x a = x and b=y b = y . Thus, our expression (x+y)2 (x+y)^2 can be expanded as follows:

(x+y)2=x2+2xy+y2 (x+y)^2 = x^2 + 2xy + y^2

Now we will match this expanded form with the given choices.

  • Choice 1: x2+y2 x^2 + y^2 - This is missing the middle term 2xy 2xy .
  • Choice 2: y2+x2+2xy y^2 + x^2 + 2xy - This matches the expanded expression.
  • Choice 3: x2+xy+y2 x^2 + xy + y^2 - The term xy xy doesn't match the required 2xy 2xy .
  • Choice 4: x22xy+y2 x^2 - 2xy + y^2 - The middle term has an incorrect sign.

Therefore, the expression that is equivalent to (x+y)2 (x+y)^2 is choice 2: y2+x2+2xy y^2 + x^2 + 2xy .

Answer:

y2+x2+2xy y^2+x^2+2xy

Video Solution
Exercise #2

Choose the expression that has the same value as the following:


(x+3)2 (x+3)^2

Step-by-Step Solution

We use the abbreviated multiplication formula:

x2+2×x×3+32= x^2+2\times x\times3+3^2=

x2+6x+9 x^2+6x+9

Answer:

x2+6x+9 x^2+6x+9

Video Solution
Exercise #3

Choose the expression that has the same value as the following:

(xy)2 (x-y)^2

Step-by-Step Solution

We use the abbreviated multiplication formula:

(xy)(xy)= (x-y)(x-y)=

x2xyyx+y2= x^2-xy-yx+y^2=

x22xy+y2 x^2-2xy+y^2

Answer:

x22xy+y2 x^2-2xy+y^2

Video Solution
Exercise #4

Choose the expression that has the same value as the following:

(x7)2 (x-7)^2

Step-by-Step Solution

To solve the problem, we need to expand the expression (x7)2(x-7)^2 using the formula for the square of a difference.

The formula for the square of a difference is (ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2.

Let's apply this formula to our expression (x7)2(x-7)^2:

  • Identify a=xa = x and b=7b = 7.
  • Substitute these values into the formula: (x7)2=x22(x)(7)+72(x-7)^2 = x^2 - 2(x)(7) + 7^2.
  • Calculate each term:
    • x2x^2 remains as x2x^2.
    • 2(x)(7)=14x-2(x)(7) = -14x.
    • 72=497^2 = 49.

So, expanding the expression, we get x214x+49x^2 - 14x + 49.

Thus, the expression that has the same value as (x7)2(x-7)^2 is x214x+49x^2 - 14x + 49.

Answer:

x214x+49 x^2-14x+49

Video Solution
Exercise #5

(x26)2= (x^2-6)^2=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify a and b in the expression (x26)2 (x^2 - 6)^2 .
  • Step 2: Apply the square of a difference formula.
  • Step 3: Simplify the resulting expression.

Now, let's work through each step:
Step 1: The expression is (x26)2 (x^2 - 6)^2 . Here, a=x2 a = x^2 and b=6 b = 6 .
Step 2: Apply the binomial formula: (ab)2=a22ab+b2 (a - b)^2 = a^2 - 2ab + b^2 .
Step 3:
1. Calculate a2 a^2 :
a2=(x2)2=x4 a^2 = (x^2)^2 = x^4 .
2. Calculate 2ab 2ab :
2ab=2(x2)(6)=12x2 2ab = 2(x^2)(6) = 12x^2 .
3. Calculate b2 b^2 :
b2=62=36 b^2 = 6^2 = 36 .
4. Substitute these back into the formula:
(x26)2=x412x2+36(x^2 - 6)^2 = x^4 - 12x^2 + 36.

Therefore, the expanded expression is x412x2+36 x^4 - 12x^2 + 36 .

Answer:

x412x2+36 x^4-12x^2+36

Video Solution

Frequently Asked Questions

What are abbreviated multiplication formulas and why are they important?

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Abbreviated multiplication formulas, also known as algebraic identities, are shortcuts that simplify expanding and factoring expressions. They save time in calculations and are essential for solving complex algebraic problems throughout middle school, high school, and beyond.

How do I remember the difference between (a+b)² and (a-b)² formulas?

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The key difference is in the middle term: (a+b)² = a² + 2ab + b² has a positive middle term, while (a-b)² = a² - 2ab + b² has a negative middle term. Remember that the sign of the middle term matches the sign in the original expression.

When should I use the difference of squares formula (a+b)(a-b) = a² - b²?

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Use this formula when you see the product of two binomials where one is a sum and the other is a difference of the same terms. It's particularly useful for factoring expressions like x² - 9 = (x+3)(x-3) or simplifying complex fractions.

What are the most common mistakes students make with abbreviated multiplication formulas?

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Common mistakes include: 1) Forgetting the middle term coefficient (2ab), 2) Getting signs wrong in the difference formula, 3) Not recognizing when to apply the formulas, 4) Mixing up expansion and factoring directions.

How do cubic formulas (a+b)³ and (a-b)³ differ from quadratic ones?

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Cubic formulas have four terms instead of three and involve higher powers. (a+b)³ = a³ + 3a²b + 3ab² + b³ follows a pattern with coefficients 1, 3, 3, 1, while (a-b)³ alternates signs. The coefficients come from Pascal's triangle.

Can I use abbreviated multiplication formulas with numbers and variables together?

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Yes! These formulas work with pure numbers (like (5+3)²), pure variables (like (x+y)²), or combinations (like (x+4)²). The key is identifying the pattern regardless of whether you're working with numbers, variables, or both.

How do I factor expressions back into abbreviated forms?

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Look for patterns that match the expanded formulas. For example, if you see x² + 6x + 9, recognize it as a perfect square trinomial (x+3)² because it fits the pattern a² + 2ab + b² where a=x and b=3.

What real-world applications use abbreviated multiplication formulas?

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These formulas appear in geometry (calculating areas and volumes), physics (motion equations), engineering (structural calculations), and economics (profit/loss models). They're fundamental tools for any field requiring mathematical modeling.

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