The area of the triangle below is equal to 10 cm² and its height is 5 times greater than its base.
Calculate X.
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The area of the triangle below is equal to 10 cm² and its height is 5 times greater than its base.
Calculate X.
To solve this problem, we shall adhere to the following steps:
Now, let us execute these steps:
Step 1: Start by applying the triangle area formula .
The given area is , the base is , and the height is . Thus, the formula becomes:
Step 2: Simplify the equation:
Multiply both sides by to eliminate the fraction:
Divide both sides by :
Take the square root of both sides:
So, the value of is .
Step 3: Upon reviewing the given multiple-choice options, the answer corresponds to one of the listed choices, ensuring our calculations align with the expected solution.
Therefore, the solution to the problem is .
Angle A is equal to 30°.
Angle B is equal to 60°.
Angle C is equal to 90°.
Can these angles form a triangle?
This means height = 5 × base. If the base is x, then the height is 5x. It's multiplication, not addition!
Because you're multiplying base (x) times height (5x), which gives x × 5x = 5x². This creates a quadratic equation that you solve by taking the square root.
No! Since x represents a length measurement (the base of a triangle), it must be positive. Always take the positive square root for geometric problems.
Think: Area = ½ × base × height. The ½ comes from the fact that a triangle is half of a rectangle with the same base and height!
Not really! When you substitute the relationship (height = 5x) into the area formula, you naturally get 5x². Quadratic equations are common in geometry problems.
Always double-check your work! Substitute x = 2 back: base = 2, height = 5(2) = 10, so Area = ½ × 2 × 10 = 10 cm². It matches!
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