Inputing Values into a Function

In mathematics, we often assign numerical values to variables in equations or mathematical expressions. A function can be thought of as a machine: you input a value (called the input), the function processes it according to a specific rule, and produces a result (called the output). The input is usually represented by \(x)\, and the output by f(x)f(x) or yy.

Understanding Variables and Substitution

A variable is a placeholder for an unknown number, often called the "unknown". When we replace a variable with a specific value, we refer to this process as substitution.

  • If an equation contains only one variable, we can solve for its value by isolating it.
  • If an equation contains multiple variables, there can be multiple solutions. Each value substituted affects the remaining variables in the equation.

When we talk about inputting values into a function, we are essentially substituting the variables in a mathematical expression or equation with specific numerical values to evaluate the result.
Often "solving an equation" is actually finding the values of the variables inside it.

For example

Suppose we have three variables, two of which have known values:

X=3 X=3

Y=2 Y=2

Z=? Z=\text{?}

We are also given the equation:

X2+Y=Z X^2+Y=Z

Remember! when facing this kind of questions, you want to try and find the values of the variables.
To solve the problem, we will first substitute the known values into the equation:

32+2=Z 3^2+2=Z

Simplify and solve:

9+2=Z9+2=Z

Z=11Z=11

By substituting the known values and performing the necessary operations, we were able to isolate and calculate the value of ZZ

Answer: Z=11 Z=11

X Y Z By assigning the numerical value, the general form becomes a particular case

Suggested Topics to Practice in Advance

  1. Ways to Represent a Function
  2. Representing a Function Verbally and with Tables
  3. Graphical Representation of a Function
  4. Algebraic Representation of a Function
  5. Notation of a Function
  6. Rate of Change of a Function
  7. Variation of a Function
  8. Rate of change represented with steps in the graph of the function
  9. Rate of change of a function represented graphically
  10. Constant Rate of Change
  11. Variable Rate of Change
  12. Rate of Change of a Function Represented by a Table of Values
  13. Functions for Seventh Grade
  14. Increasing and Decreasing Intervals (Functions)
  15. Increasing functions
  16. Decreasing function
  17. Constant Function
  18. Decreasing Interval of a function
  19. Increasing Intervals of a function

Practice Inputing Values into a Function

Examples with solutions for Inputing Values into a Function

Exercise #1

6x+5=1 \frac{6}{x+5}=1

What is the field of application of the equation?

Video Solution

Step-by-Step Solution

To solve this problem, we will determine the domain, or field of application, of the equation 6x+5=1 \frac{6}{x+5} = 1 .

Step-by-step solution:

  • Step 1: Identify the denominator. In the given equation, the denominator is x+5 x+5 .
  • Step 2: Determine when the denominator is zero. Solve for x x by setting x+5=0 x+5 = 0 .
  • Step 3: Solve the equation: x+5=0 x+5 = 0 gives x=5 x = -5 .
  • Step 4: Exclude this value from the domain. The domain is all real numbers except x=5 x = -5 .

Therefore, the field of application of the equation is all real numbers except where x=5 x = -5 .

Thus, the domain is x5 x \neq -5 .

Answer

x5 x\operatorname{\ne}-5

Exercise #2

x+y:32x+6=4 \frac{x+y:3}{2x+6}=4

What is the field of application of the equation?

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps to find the domain:

  • Step 1: Recognize that the expression x+y:32x+6=4\frac{x+y:3}{2x+6}=4 involves a fraction. The denominator 2x+62x + 6 must not be zero, as division by zero is undefined.
  • Step 2: Set the denominator equal to zero and solve for xx to find the values that must be excluded: 2x+6=02x + 6 = 0.
  • Step 3: Solve 2x+6=02x + 6 = 0:
    • 2x+6=02x + 6 = 0
    • 2x=62x = -6
    • x=3x = -3
  • Step 4: Conclude that the domain of the function excludes x=3x = -3, meaning x3x \neq -3.

Thus, the domain of the given expression is all real numbers except x=3x = -3. This translates to:

x3 x\operatorname{\ne}-3

Answer

x3 x\operatorname{\ne}-3

Exercise #3

3x:4y+6=6 \frac{3x:4}{y+6}=6

What is the field of application of the equation?

Video Solution

Step-by-Step Solution

To determine the field of application of the equation 3x:4y+6=6\frac{3x:4}{y+6}=6, we must identify values of yy for which the equation is defined.

  • The denominator of the given expression is y+6y + 6. In order for the expression to be defined, the denominator cannot be zero.
  • This leads us to solve the equation y+6=0y + 6 = 0.
  • Solving y+6=0y + 6 = 0 gives us y=6y = -6.
  • This means y=6y = -6 would make the denominator zero, thus the expression would be undefined for this value.

Therefore, the field of application, or the domain of the equation, is all real numbers except y=6y = -6.

We must conclude that y6 y \neq -6 .

Comparing with the provided choices, the correct answer is choice 3: y6 y \neq -6 .

Answer

y6 y\operatorname{\ne}-6

Exercise #4

Given the following function:

5x2x \frac{5-x}{2-x}

Does the function have a domain? If so, what is it?

Video Solution

Step-by-Step Solution

To determine the domain of the function 5x2x \frac{5-x}{2-x} , we need to identify and exclude any values of x x that make the function undefined. This occurs when the denominator equals zero.

  • Step 1: Set the denominator equal to zero:
    2x=0 2-x = 0
  • Step 2: Solve for x x :
    Adding x x to both sides gives 2=x 2 = x . Hence, x=2 x = 2 .

This means that the function is undefined when x=2 x = 2 . Therefore, the domain of the function consists of all real numbers except x=2 x = 2 .

Thus, the domain is: x2 x \ne 2 .

The correct answer choice is:

Yes, x2 x\ne2

Answer

Yes, x2 x\ne2

Exercise #5

Given the following function:

49+2xx+4 \frac{49+2x}{x+4}

Does the function have a domain? If so, what is it?

Video Solution

Step-by-Step Solution

To determine the domain of the function 49+2xx+4 \frac{49 + 2x}{x + 4} , we need to focus on avoiding division by zero, which occurs when the denominator is zero.

Let's identify the denominator of the function:

  • The denominator is x+4 x + 4 .

Next, we set the denominator equal to zero and solve for x x :

  • x+4=0 x + 4 = 0
  • Subtract 4 from both sides: x=4 x = -4

This calculation shows that the function is undefined when x=4 x = -4 . Thus, the domain of the function is all real numbers except x=4 x = -4 .

Therefore, the domain of the function is x4 x \neq -4 .

In terms of the provided choices, this corresponds to choice 4:

Yes, x4 x \ne -4

Answer

Yes, x4 x\ne-4

Exercise #6

Given the following function:

235x2 \frac{23}{5x-2}

Does the function have a domain? If so, what is it?

Video Solution

Step-by-Step Solution

To determine the domain of the function 235x2 \frac{23}{5x-2} , follow these steps:

  • Step 1: Identify where the function is undefined by setting the denominator equal to zero.
    Equation: 5x2=0 5x - 2 = 0
  • Step 2: Solve the equation for x x .

Let's perform the calculation:
Step 1: Set 5x2=0 5x - 2 = 0 .

Step 2: Solve for x x by adding 2 to both sides:
5x=2 5x = 2

Next, divide both sides by 5:
x=25 x = \frac{2}{5}

This shows that the function is undefined at x=25 x = \frac{2}{5} , thus excluding this point from the domain of the function.

The domain of 235x2 \frac{23}{5x-2} consists of all real numbers except x=25 x = \frac{2}{5} .

Therefore, the domain is expressed as x25 x \ne \frac{2}{5} .

Considering the multiple-choice options, the correct choice is:

Yes, x25 x\ne\frac{2}{5}

Answer

Yes, x25 x\ne\frac{2}{5}

Exercise #7

Does the given function have a domain? If so, what is it?

9x4 \frac{9x}{4}

Video Solution

Step-by-Step Solution

Since the function's denominator equals 4, the domain of the function is all real numbers. This means that any one of the x values could be compatible.

Answer

No, the entire domain

Exercise #8

Look at the following function:

5x \frac{5}{x}

Does the function have a domain? If so, what is it?

Video Solution

Step-by-Step Solution

Since the unknown variable is in the denominator, we should remember that the denominator cannot be equal to 0.

In other words, x0 x\ne0

The domain of the function is all those values that, when substituted into the function, will make the function legal and defined.

The domain in this case will be all real numbers that are not equal to 0.

Answer

Yes, x0 x\ne0

Exercise #9

Given the following function:

2421x7 \frac{24}{21x-7}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To determine the domain of the function 2421x7 \frac{24}{21x-7} , we need to ensure that the denominator is not equal to zero.

Step 1: Set the denominator equal to zero and solve for x x :

  • 21x7=0 21x - 7 = 0

  • 21x=7 21x = 7

  • x=721 x = \frac{7}{21}

  • x=13 x = \frac{1}{3}

The function is undefined when x=13 x = \frac{1}{3} because it would cause division by zero.

Step 2: The domain of the function is all real numbers except x=13 x = \frac{1}{3} .

Therefore, the domain of the function is all x x such that x13 x \neq \frac{1}{3} .

Thus, the correct answer is x13 \boxed{ x\ne\frac{1}{3}} .

Answer

x13 x\ne\frac{1}{3}

Exercise #10

Look the following function:

15x4 \frac{1}{5x-4}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To determine the domain of the function 15x4 \frac{1}{5x-4} , we need to find the values of x x for which the function is undefined. This occurs when the denominator equals zero:

First, set the denominator equal to zero:
5x4=0 5x - 4 = 0

Next, solve for x x :
5x=4 5x = 4
x=45 x = \frac{4}{5}

The function is undefined at x=45 x = \frac{4}{5} . Therefore, the domain of the function includes all real numbers except x=45 x = \frac{4}{5} .

In mathematical notation, the domain is:
x45 x \ne \frac{4}{5} .

This matches choice 3 among the given options.

Answer

x45 x\ne\frac{4}{5}

Exercise #11

Given the following function:

128x4 \frac{12}{8x-4}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To find the domain of the function 128x4 \frac{12}{8x-4} , we must determine when the denominator equals zero and exclude these values.

Step 1: Set the denominator equal to zero and solve for x x :

8x4=0 8x - 4 = 0

Step 2: Solve the equation 8x4=0 8x - 4 = 0 for x x :

Add 4 to both sides: 8x=4 8x = 4

Divide both sides by 8: x=48=12 x = \frac{4}{8} = \frac{1}{2}

Step 3: The value x=12 x = \frac{1}{2} is where the denominator becomes zero, so this value is excluded from the domain.

Therefore, the domain of the function is all real numbers except x=12 x = \frac{1}{2} .

The domain of the function is x12\boxed{x \ne \frac{1}{2}}.

Answer

x12 x\ne\frac{1}{2}

Exercise #12

Look at the following function:

2x+29x+6 \frac{2x+2}{9x+6}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To solve this problem, we will determine the domain of the rational function by following these steps:

  • Step 1: Identify the denominator of the function, which is 9x+6 9x + 6 .
  • Step 2: Set the denominator equal to zero to find values of x x that need to be excluded from the domain: 9x+6=0 9x + 6 = 0 .
  • Step 3: Solve the equation 9x+6=0 9x + 6 = 0 for x x .
  • Step 4: To solve, subtract 6 from both sides to get 9x=6 9x = -6 .
  • Step 5: Divide each side by 9 to solve for x x , resulting in x=23 x = -\frac{2}{3} .
  • Step 6: The domain of the function excludes the value x=23 x = -\frac{2}{3} since it makes the denominator zero.

Thus, the domain of the given function is all real numbers except x=23 x = -\frac{2}{3} , expressed as x23 x \ne -\frac{2}{3} .

Therefore, the correct choice for the domain is: x23 x\ne-\frac{2}{3} .

Answer

x23 x\ne-\frac{2}{3}

Exercise #13

Look at the following function:

10x35x3 \frac{10x-3}{5x-3}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To find the domain of the function 10x35x3\frac{10x-3}{5x-3}, we'll follow these steps:

  • Identify the denominator: B(x)=5x3B(x) = 5x - 3.
  • Set the denominator equal to zero: 5x3=05x - 3 = 0.
  • Solve for xx: Add 3 to both sides, getting 5x=35x = 3. Then, divide by 5: x=35x = \frac{3}{5}.
  • Conclude that the domain is all real numbers except x=35x = \frac{3}{5}, since this makes the denominator zero.

Therefore, the domain of the function is all real numbers except x35 x\ne\frac{3}{5} .

Answer

x35 x\ne\frac{3}{5}

Exercise #14

Consider the following function:

3x+42x1 \frac{3x+4}{2x-1}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To determine the domain of the function 3x+42x1 \frac{3x+4}{2x-1} , follow these steps:

  • Step 1: Identify the denominator of the rational function, which is 2x1 2x-1 .
  • Step 2: Set the denominator equal to zero to find the values of x x that make the function undefined:
    2x1=0 2x - 1 = 0 .
  • Step 3: Solve for x x :
    Add 1 to both sides: 2x=1 2x = 1 .
    Divide both sides by 2: x=12 x = \frac{1}{2} .

The value x=12 x = \frac{1}{2} makes the denominator zero, which means the function 3x+42x1 \frac{3x+4}{2x-1} is undefined at x=12 x = \frac{1}{2} . Therefore, this value must be excluded from the domain.

The domain of the function is all real numbers except x=12 x = \frac{1}{2} .

Therefore, the solution to the problem is x12 x \ne \frac{1}{2} .

Answer

x12 x\ne\frac{1}{2}

Exercise #15

Look at the following function:

2010x5 \frac{20}{10x-5}

What is the domain of the function?

Video Solution

Step-by-Step Solution

To determine the domain of the function 2010x5 \frac{20}{10x-5} , we need to ensure that the denominator is not zero.

  • Step 1: Identify the denominator, which is 10x5 10x - 5 .
  • Step 2: Set the denominator equal to zero and solve for x x . This gives us the equation:

10x5=0 10x - 5 = 0

  • Step 3: Add 5 to both sides of the equation:

10x=5 10x = 5

  • Step 4: Divide both sides by 10 to isolate x x :

x=510 x = \frac{5}{10}

  • Step 5: Simplify the fraction:

x=12 x = \frac{1}{2}

This means that the function is undefined at x=12 x = \frac{1}{2} . Therefore, the domain of the function is all real numbers except x=12 x = \frac{1}{2} .

Therefore, the domain of the function is x12 x \ne \frac{1}{2} .

Answer

x12 x\ne\frac{1}{2}

Topics learned in later sections

  1. Domain of a Function
  2. Indefinite integral