Some of you may know the radius as a "dial". Either way, the meaning is identical with the same characteristics. So, what is the radius? It is a specific segment that connects the center of a circle with a particular point on the circumference .

Some of you may know the radius as a "dial". Either way, the meaning is identical with the same characteristics. So, what is the radius? It is a specific segment that connects the center of a circle with a particular point on the circumference .

The formula for calculating the perimeter or circumference of a circle is: $P=2πR$

Where $P =$ is the perimeter of the circle, $R =$ is the radius of the circle, and $π =$ is a number approximately equal to $3.14$.

Given: A circle with a circumference of $18.84$. The radius of the circle needs to be calculated.

We will place the known data into the formula: $18.84=2πR$

The perimeter can be translated in terms of $π$, that is: $18.84:3.14=6$

Then we obtain: $6π=2πR$

Reduce the value of $π$ and get $6=2R$. Continue with a division by $2$ to isolate the value of $R$.

That is: $R=\frac{6}{2}$ and, therefore, the result obtained is that the radius of the circle $=3$.

A circle has a diameter of 12.

What is its perimeter?

**More examples:**

Given: A circle whose perimeter is $25.45$, we must calculate the radius of the circle

We will place the data we know into the formula: $25.45=2πR$

The circumference can be translated in terms of $π$, that is: $25.45=$

Then we obtain: $25.45=6.28R$

To isolate the value of $R$ divide $25.45/6.28$

Therefore, the result is that the radius of the circle $=4.05$

Given a circle with a circumference of $50.25$, we must calculate the radius of the circle

We will place the known data into the formula: $50.25=2πR$

The circumference can be expressed in terms of $π$, that is: $50.25=$

Then we obtain: $50.25=6.28R$

To isolate the value of $R$, it is necessary to divide $50.25/6.28$

Therefore, the result is that the radius of the circle $=8$

The data of a circle whose circumference is $11$, the radius of the circle must be calculated.

To isolate the value of $R$ divide $11/6.28$

Therefore, the result is that the radius of the circle $=1.75$

Test your knowledge

Question 1

A circle has a radius of 3 cm.

What is its perimeter?

Question 2

Given the circle whose radius has a length of 9 cm

What is its perimeter?

Question 3

Look at the circle in the figure below.

The diameter of the circle is 4.

What is its perimeter?

**Exercise 1:**

**Task:**

How will the circumference change if we double its diameter?

**Solution:**

The radius is equal to $K$

$P=2π\times r$

$=2π\times (\frac{K}{2} )$

$=2π\times (\frac{K}{2} )=\pi K$

The radius is equal to $2K$

$P=2π\times r$

$=2π\times (\frac{2K}{2} )$

$=2π\times (\frac{2K}{2} )=2 \pi \cdot K$

$\frac{P2K}{PK}=\frac{2πK}{πK}=2$

**Answer:**

The circumference will double

**Exercise 2:**

Given the shape of the figure.

The quadrilateral is a square with $5$ cm side length.

**Task:**

What is the perimeter of the figure?

**Solution:**

The perimeter is made up of $4$ halves of the circle.

$4\times\frac{1}{2}P=2P$

That is, a total of $2$ circumferences with $5$ cm diameter.

$Diameter = 2 radius$

$2\times radius=5$

$radius=\frac{5}{2}=2.5$

Circle diameter $5$ cm

$P=2π\times2.5=5π$

$P=2\times P=2\times5π=10\pi$

**Answer:**

$10\pi$

**Exercise 3:**

Given:

Mirta runs at a speed of $7$ minutes per kilometer.

She runs on a circular path with a radius of $20$ meters and circles it $4$ times.

**Task:**

How long will Mirta run?

**Solution:**

First, we calculate the length of the path.

Path length = The circumference has a radius of $20$ meters.

$2π\times20=2\times3.14\times20=125.6$

Mirta's path distance = Path length $\times4$ = $125.6\times4=502.4$ (meters)

That is: $0.5024$ km

$\text{Time}=7\times0.5024=3.52$

**Answer:**

It will take Mirta $3.52$ minutes to complete the run.

**Exercise 4:**

Given the circle with a circumference of $6.28$

**Question:**

What is its area?

**Solution:**

Let's recall the circumference formula:

$2πR$

We replace with the known data:

$6.28=2πR$

We divide by $2$

$3.14=πR$

Now we divide by $π$

$1=R$

From here we can replace the data in the area formula of the circumference:

$A=πR^2$

$A=π1^2$

$A=π\times1$

$A=π$

**Answer:**

$Area=π$

```

Look at the circle in the figure.

What is its circumference if its radius is equal to 6?

Formula of the circumference:

$P=2\pi r$

We insert the given data into the formula:

$P=2\times6\times\pi$

$P=12\pi$

$12\pi$

Look at the circle in the figure:

Its radius is equal to 4.

What is its circumference?

The formula for the circumference is equal to:

$2\pi r$

8π

O is the center of the circle in the figure below.

What is its circumference?

We use the formula:$P=2\pi r$

We replace the data in the formula:$P=2\times8\pi$

$P=16\pi$

$16\pi$ cm

Is it possible that the circumference of a circle is 8 meters and its diameter is 4 meters?

To calculate, we will use the formula:

$\frac{P}{2r}=\pi$

Pi is the ratio between the circumference of the circle and the diameter of the circle.

The diameter is equal to 2 radii.

Let's substitute the given data into the formula:

$\frac{8}{4}=\pi$

$2\ne\pi$

Therefore, this situation is not possible.

Impossible

Look at the circle in the figure.

The radius of the circle is $\frac{2}{3}$.

What is its perimeter?

The radius is a straight line that extends from the center of the circle to its outer edge.

The radius is essential for calculating the circumference of the circle, according to the following formula:

If we substitute the radius we currently have, the formula will be:

2*π*2/3

Let's start solving, we'll rearrange the formula:

π*2*2/3 =

We'll multiply the fraction by the whole number:

π*(2*2)/3 =

π*4/3 =

4/3π

And that's the result!

$\frac{4}{3}\pi$

More and more students are lamenting the way they are taught the material- that they are not taught how to study for exams. There is a big difference between solving a question in class with the teacher and with the help of classmates, and dealing with questions in real time during the exam. The secret to success? Practice the material and mentally prepare to believe in yourself, and above all, reduce feelings of stress. So, how do you prepare for the exam in the best way?

**1. Start studying about a week and a half before the exam**

Some schools distribute the exam schedule to students on the first day of classes. This means that you know when you will be tested, so you can prepare in advance according to your own time and priorities. A week and a half is a sufficient amount of time to study for a math exam, assuming that you have mastered most of the material and need this period just for practice and memorizing formulas.

**2. Create a detailed personal learning program.**

Additionally, it's worth creating a schedule for yourself that details what you will study each day of the week. It's not enough to say: "On Monday, I will study circles and radii", but you should specify exactly what you are doing:

- List the hours. For example: from 4:00 PM to 8:00 PM.
- What will you do exactly (memorize formulas, review the properties of shapes, solve exercises)?
- In just a few pages, you will progress through the workbook and so on.

**3. Breaks during learning are very important**

When creating a learning schedule for yourself, also incorporate breaks. If you study for hours on end and intensely, you can reach burnout quickly. The goal is to maintain your motivation and not to arrive at a pre-exam situation of exhaustion. For every two hours of study, take a fresh half-hour break.

**4. Learning Groups!**

Is it worth studying with friends? Yes! Just make sure that you're actually studying and it's not turning into an impromptu party. Every three days of study, use a study group with 2-3 members. The goal is to solve exercises together, while each of you can contribute your knowledge to the other members and thus strengthen certain topics. Those of you who want to simulate an exam situation can open timers and check how much time it takes to solve the exercises.

**5. Come to math class with questions.**

During home study, it's likely that some more challenging and complex questions will arise, which is fine. Teachers allow you to raise questions that you want them to solve in class, and it's definitely worth asking questions. Your teacher will guide you through solving the question, while you will learn how to deal with questions at this specific level during the test.

And what about a private tutor? A personalized math class can definitely contribute to your understanding. The recommendation is not to wait for private lessons only just before the exam, but to make sure you gradually assimilate the material learned throughout your studies. The private lesson can be conducted at the student's home, at the teacher's home, or online.

Do you know what the answer is?

Question 1

Look at the circle in the figure below.

The radius of the circle equals 7.

What is its perimeter?

Question 2

Look at the circle in the figure below.

The radius of the circle is equal to 8.

What is its perimeter?

Question 3

Look at the circle in the figure below.

The radius of the circle equals 5.

What is its perimeter?

Related Subjects

- Area
- Trapezoids
- Area of a trapezoid
- Perimeter of a trapezoid
- Parallelogram
- The area of a parallelogram: what is it and how is it calculated?
- Perimeter of a Parallelogram
- Elements of the circumference
- Circle
- Diameter
- Pi
- Area of a circle
- Distance from a chord to the center of a circle
- Chords of a Circle
- Central Angle in a Circle
- Arcs in a Circle
- Perpendicular to a chord from the center of a circle
- Inscribed angle in a circle
- Tangent to a circle
- The Circumference of a Circle
- The Center of a Circle
- Radius
- How is the radius calculated using its circumference?
- Rectangle
- Calculating the Area of a Rectangle
- The perimeter of the rectangle
- Perimeter
- Triangle
- The Area of a Triangle
- Area of a right triangle
- Area of Isosceles Triangles
- Area of a Scalene Triangle
- Area of Equilateral Triangles
- Perimeter of a triangle
- Cylinder Area
- Cylinder Volume