How is the radius calculated using its circumference?

🏆Practice circumference

Some of you may know the radius as a "dial". Either way, the meaning is identical with the same characteristics. So, what is the radius? It is a specific segment that connects the center of a circle with a particular point on the circumference .

How is the radius calculated using its perimeter?

The formula for calculating the perimeter or circumference of a circle is: P=2πR P=2πR

Where P= P = is the perimeter of the circle, R= R = is the radius of the circle, and π= π = is a number approximately equal to 3.14 3.14 .

Given: A circle with a circumference of 18.84 18.84 . The radius of the circle needs to be calculated.

We will place the known data into the formula: 18.84=2πR 18.84=2πR

The perimeter can be translated in terms of π π , that is: 18.84:3.14=6 18.84:3.14=6

Then we obtain: 6π=2πR 6π=2πR

Reduce the value of π π and get 6=2R 6=2R . Continue with a division by 2 2 to isolate the value of R R .

That is: R=62 R=\frac{6}{2} and, therefore, the result obtained is that the radius of the circle =3 =3 .

1 - How to calculate the radius using its perimeter

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Test yourself on circumference!

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\( r=11 \)

Calculate the circumference.

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Another way to solve:

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More examples:

Given: A circle whose perimeter is 25.45 25.45 , we must calculate the radius of the circle
We will place the data we know into the formula: 25.45=2πR 25.45=2πR
The circumference can be translated in terms of π π , that is: 25.45= 25.45=
Then we obtain: 25.45=6.28R 25.45=6.28R

To isolate the value of R R divide 25.45/6.28 25.45/6.28
Therefore, the result is that the radius of the circle =4.05 =4.05

Given a circle with a circumference of 50.25 50.25 , we must calculate the radius of the circle
We will place the known data into the formula: 50.25=2πR 50.25=2πR
The circumference can be expressed in terms of π π , that is: 50.25= 50.25=
Then we obtain: 50.25=6.28R 50.25=6.28R
To isolate the value of R R , it is necessary to divide 50.25/6.28 50.25/6.28
Therefore, the result is that the radius of the circle =8 =8

The data of a circle whose circumference is 11 11 , the radius of the circle must be calculated.
To isolate the value of R R divide 11/6.28 11/6.28
Therefore, the result is that the radius of the circle =1.75 =1.75

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Exercises on Calculating Radius and Circumference

Exercise 1:

How will the circumference change if we double its diameter

Task:

How will the circumference change if we double its diameter?

Solution:

The radius is equal to K K

P=2π×r P=2π\times r

=2π×(K2) =2π\times (\frac{K}{2} )

=2π×(K2)=πK =2π\times (\frac{K}{2} )=\pi K

The radius is equal to 2K 2K

P=2π×r P=2π\times r

=2π×(2K2) =2π\times (\frac{2K}{2} )

=2π×(2K2)=2πK =2π\times (\frac{2K}{2} )=2 \pi \cdot K

P2KPK=2πKπK=2 \frac{P2K}{PK}=\frac{2πK}{πK}=2

Answer:

The circumference will double


Exercise 2:

Given the shape of the figure.

The quadrilateral is a square with 5 5 cm side length.

Given the shape of the figure

Task:

What is the perimeter of the figure?

Solution:

The perimeter is made up of 4 4 halves of the circle.

4×12P=2P 4\times\frac{1}{2}P=2P

That is, a total of 2 2 circumferences with 5 5 cm diameter.

Diameter=2radius Diameter = 2 radius

2×radius=5 2\times radius=5

radius=52=2.5radius=\frac{5}{2}=2.5

Circle diameter 5 5 cm

P=2π×2.5=5π P=2π\times2.5=5π

P=2×P=2×5π=10π P=2\times P=2\times5π=10\pi

Answer:

10π 10\pi


Exercise 3:

Given:

Mirta runs at a speed of 7 7 minutes per kilometer.

She runs on a circular path with a radius of 20 20 meters and circles it 4 4 times.

Task:

How long will Mirta run?

Solution:

First, we calculate the length of the path.

Path length = The circumference has a radius of 2020 meters.

2π×20=2×3.14×20=125.6 2π\times20=2\times3.14\times20=125.6

Mirta's path distance = Path length ×4 \times4 = 125.6×4=502.4 125.6\times4=502.4 (meters)

That is: 0.5024 0.5024 km

Time=7×0.5024=3.52 \text{Time}=7\times0.5024=3.52

Answer:

It will take Mirta 3.52 3.52 minutes to complete the run.


Exercise 4:

Given the circle with a circumference of 6.28 6.28

Given the circle with a circumference of 6.28

Question:

What is its area?

Solution:

Let's recall the circumference formula:

2πR 2πR

We replace with the known data:

6.28=2πR 6.28=2πR

We divide by 2 2

3.14=πR 3.14=πR

Now we divide by π π

1=R 1=R

From here we can replace the data in the area formula of the circumference:

A=πR2 A=πR^2

A=π12 A=π1^2

A=π×1 A=π\times1

A=π A=π

Answer:

Area=π Area=π


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How to Calculate the Radius Using Its Circumference? (Examples and Exercises with Solutions)

Exercise #1

O is the center of the circle in the figure below.

888OOO What is its circumference?

Video Solution

Step-by-Step Solution

We use the formula:P=2πr P=2\pi r

We replace the data in the formula:P=2×8π P=2\times8\pi

P=16π P=16\pi

Answer

16π 16\pi cm

Exercise #2

Look at the circle in the figure:

444

Its radius is equal to 4.

What is its circumference?

Video Solution

Step-by-Step Solution

The formula for the circumference is equal to:

2πr 2\pi r

Answer

Exercise #3

Look at the circle in the figure.

What is its circumference if its radius is equal to 6?

6

Video Solution

Step-by-Step Solution

Formula of the circumference:

P=2πr P=2\pi r

We replace the data in the formula:

P=2×6×π P=2\times6\times\pi

P=12π P=12\pi

Answer

12π 12\pi

Exercise #4

A circle has a circumference of 31.41.

What is its radius?

Video Solution

Step-by-Step Solution

To solve the exercise, first we must remember the circumference formula:

P=2πR P= 2\pi R

P is the circumference and Pi has a value of 3.14 (approximately).

We substitute in the known data:

31.41=23.141R 31.41=2\cdot3.141\cdot R

Keep in mind that the result can be easily simplified using Pi:

31.413.141=2R \frac{31.41}{3.141}=2R

10=2R 10=2R

Finally, we simplify by 2:

5=R 5=R

Answer

5

Exercise #5

A circle has a circumference of 50.25.

What is its radius?

Video Solution

Step-by-Step Solution

We use the formula:

P=2πr P=2\pi r

We replace the data in the formula:

50.25=3.14×2r 50.25=3.14\times2r

50.25=2×r×3.14 50.25=2\times r\times3.14

50.25=6.28r 50.25=6.28r

50.256.28=6.28r6.28 \frac{50.25}{6.28}=\frac{6.28r}{6.28}

r=8 r=8

Answer

8

Take a Breather: 5 Excellent Tips for Effective Learning Before Exams

More and more students are lamenting the way they are taught the material- that they are not taught how to study for exams. There is a big difference between solving a question in class with the teacher and with the help of classmates, and dealing with questions in real time during the exam. The secret to success? Practice the material and mentally prepare to believe in yourself, and above all, reduce feelings of stress. So, how do you prepare for the exam in the best way?

1. Start studying about a week and a half before the exam

Some schools distribute the exam schedule to students on the first day of classes. This means that you know when you will be tested, so you can prepare in advance according to your own time and priorities. A week and a half is a sufficient amount of time to study for a math exam, assuming that you have mastered most of the material and need this period just for practice and memorizing formulas.

2. Create a detailed personal learning program.

Additionally, it's worth creating a schedule for yourself that details what you will study each day of the week. It's not enough to say: "On Monday, I will study circles and radii", but you should specify exactly what you are doing:

  • List the hours. For example: from 4:00 PM to 8:00 PM.
  • What will you do exactly (memorize formulas, review the properties of shapes, solve exercises)?
  • In just a few pages, you will progress through the workbook and so on.

3. Breaks during learning are very important

When creating a learning schedule for yourself, also incorporate breaks. If you study for hours on end and intensely, you can reach burnout quickly. The goal is to maintain your motivation and not to arrive at a pre-exam situation of exhaustion. For every two hours of study, take a fresh half-hour break.

4. Learning Groups!

Is it worth studying with friends? Yes! Just make sure that you're actually studying and it's not turning into an impromptu party. Every three days of study, use a study group with 2-3 members. The goal is to solve exercises together, while each of you can contribute your knowledge to the other members and thus strengthen certain topics. Those of you who want to simulate an exam situation can open timers and check how much time it takes to solve the exercises.

5. Come to math class with questions.

During home study, it's likely that some more challenging and complex questions will arise, which is fine. Teachers allow you to raise questions that you want them to solve in class, and it's definitely worth asking questions. Your teacher will guide you through solving the question, while you will learn how to deal with questions at this specific level during the test.

And what about a private tutor? A personalized math class can definitely contribute to your understanding. The recommendation is not to wait for private lessons only just before the exam, but to make sure you gradually assimilate the material learned throughout your studies. The private lesson can be conducted at the student's home, at the teacher's home, or online.


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